![](https://rs.olm.vn/images/avt/0.png?1311)
Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\left(4x+15\right)^3=27\Rightarrow4x+15=3\Leftrightarrow x=-3\)
(4x + 15)3- 11 = ( - 2 )4
(4x + 15)3 = (-2)4+11
(4x + 15)3 = 27
(4x+15)3 = 33
=> 4x+15 = 3
4x = -12
x = -3
![](https://rs.olm.vn/images/avt/0.png?1311)
Sửa đề: \(\left(4x+15\cdot3\right)-11=-2^4\)
=>\(4x+35-11=-16\)
=>4x+24=-16
=>4x=-14-26=-40
=>x=-40/4=-10
![](https://rs.olm.vn/images/avt/0.png?1311)
`@` `\text {Ans}`
`\downarrow`
\(\dfrac{2}{3}+\left[\dfrac{4}{5}x-\dfrac{11}{15}\right]=\dfrac{5}{9}\)
`=>`\(\dfrac{4}{5}x-\dfrac{11}{15}=\dfrac{5}{9}-\dfrac{2}{3}\)
`=>`\(\dfrac{4}{5}x-\dfrac{11}{15}=-\dfrac{1}{9}\)
`=>`\(\dfrac{4}{5}x=-\dfrac{1}{9}+\dfrac{11}{15}\)
`=>`\(\dfrac{4}{5}x=\dfrac{28}{45}\)
`=>`\(x=\dfrac{28}{45}\div\dfrac{ 4}{5}\)
`=>`\(x=\dfrac{7}{9}\)
Vậy, `x = 7/9.`
\(\left(\dfrac{3}{4}-3x\right)\cdot\left(1+4x\right)=0\)
`=>`\(\left[{}\begin{matrix}\dfrac{3}{4}-3x=0\\1+4x=0\end{matrix}\right.\)
`=>`\(\left[{}\begin{matrix}3x=\dfrac{3}{4}\\4x=-1\end{matrix}\right.\)
`=>`\(\left[{}\begin{matrix}x=\dfrac{1}{4}\\x=-\dfrac{1}{4}\end{matrix}\right.\)
Vậy, `x \in {1/4; -1/4}.`
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\text{2^5.3 - 3.(x+1)=42}\)
\(3\left(x+1\right)=54\)
\(x+1=18\)
\(x=17\)
\(\text{(4x + 5) : 3 - 11^2:11=2^2}\)
\((4x+5):3-11=4\)
\((4x+5):3=15\)
\((4x+5)=5\)
\(4x=0\)
\(x=0\)
\(\text{3x - 15 . 4 = 6.(19 - x)}\)
\(\text{3x - 60 = 6.(19 - x)}\)
\(\text{3x - 60 :(19-x)= 6}\)
\(\Rightarrow x=6\)
\(\text{(x - 7).(2x - 16)=0}\)
\(\Rightarrow\hept{\begin{cases}x-7=0\\2x-16=0\end{cases}\Rightarrow\hept{\begin{cases}x=7\\8\end{cases}}}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
x^20-x=0
x(x^19-1)=0
x= 0
hoặc x ^ 19 =1
x = 0 hoặc x= 1
![](https://rs.olm.vn/images/avt/0.png?1311)
1.a) 4.(12+88) = 4.100=400
b)72- 6 .[2.8:8 ]=72-6.[16:8]=72-6 .2= 49-12=37 ( tui ko chắc lắm )
2.a) x=26-11=15
b) (4x-15)3=53
4x-15=5
4x= 5+15
4x=20
vậy x = 20
Bài 2:
a: Ta có: x+11=26
nên x=15
b: Ta có: \(\left(4x-15\right)^3=125\)
\(\Leftrightarrow4x-15=5\)
hay x=5
![](https://rs.olm.vn/images/avt/0.png?1311)
a, (x+15) - (-x+1) = 12 b, (x-2) - (2x-2) = -2
x+15+x-1 = 12 x-2- 2x+2 = -2
2x +14 =12 -x = -2
2x = 2 x = 2
x = 1
c, x+2- (5x-16) = 4x-6 d, 15- 3x+4 = 85-x
x+2 - 5x+ 16 = 4x-6 19-3x = 85-x
-4x +18 = 4x-6 19-85 = -x+3x
-4x-4x = -6-18 -66 = 2x
-8x = -24 x = 33
x = 3
e, (-11)2 - 5(x-1) = 76+x
121 - 5x+5 = 76+x
126 -5x = 76+x
126- 76 = x+5x
50 = 6x
x = 25/3
\(\left(4x-15\right)^3-11=\left(-2\right)^2\)
\(=\left(4x-15\right)^3-11=4\)
\(=\left(4x-15\right)^3=4+11\)
\(=\left(4x-15\right)^3=15\)
\(=\left(4x-15\right)=\sqrt[3]{15}\)
xong r mình chịu