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2 . (125 - x) = 546 - 440
2. (125 - x) = 106
(125 - x) = 106 : 2
125 - x = 53
x = 125 - 53
x = 72
![](https://rs.olm.vn/images/avt/0.png?1311)
440 + 2 . ( 125 - x ) = 546
2 . ( 125 - x ) = 546 - 440
2 . ( 125 - x ) = 106
125 - x = 106 : 2
125 - x = 53
x = 125 - 53
x = 72
Vậy x = 72
440 + 2. ( 125 - x ) = 546
2 ( 125 - x ) = 546 - 440
2 ( 125 - x ) = 106
125 - x = 106 ÷ 2
125 - x = 53
x = 125 - 53
x = 72
![](https://rs.olm.vn/images/avt/0.png?1311)
a, 440 + 2 . (125 - x) = 546
2 . (125 - x) = 546 - 440
2 . (125 - x) = 106
125 - x = 106 : 2
125 - x = 53
x = 125 - 53
x = 72
![](https://rs.olm.vn/images/avt/0.png?1311)
1.
a) \(125+80+375+220\)
\(=\left(125+375\right)+\left(80+220\right)\)
\(=500+300\)
\(=800\)
b) \(25.11.8.4.125\)
\(=\left(25.4\right).\left(8.125\right).11\)
\(=100.1000.11\)
\(=1100000\)
c) \(18.74+18.27-18\)
\(=18.\left(74+27-1\right)\)
\(=18.100\)
\(=1800\)
d) \(75.23+75.77-500\)
\(=75.\left(23+77\right)-500\)
\(=75.100-500\)
\(=7500-500\)
\(=7000\)
e) \(150:\left[25.\left(18-4^2\right)\right]\)
\(=150:\left[25.\left(18-16\right)\right]\)
\(=150:\left[25.2\right]\)
\(=150:50\)
\(=3\)
f) \(125.23.2.8.50\)
\(=\left(125.8\right).\left(2.50\right).23\)
\(=1000.100.23\)
\(=2300000\)
g) \(235+88+165+12\)
\(=\left(235+165\right)+\left(88+12\right)\)
\(=400+100\)
\(=500\)
h) \(71.32+71.68-1100\)
\(=71.\left(32+68\right)-1100\)
\(=71.100-1100\)
\(=7100-1100\)
\(=6000\)
i) \(6^7:6^6+4^3.2-24^0\)
\(=6+64.2-1\)
\(=6+128-1\)
\(=133\)
j) \(546-6.\left[158:\left(30+7^2\right)\right]\)
\(=546-6.\left[158:\left(30+49\right)\right]\)
\(=546-6.\left[158:79\right]\)
\(=546-6.2\)
\(=546-12\)
\(=534\)
k) \(268+147+132+253\)
\(=\left(268+132\right)+\left(147+253\right)\)
\(=400+400\)
\(=800\)
2.
a) \(7x=707\)
\(x=707:7\)
\(x=101\)
b) \(6x+5=47\)
\(6x=47-5\)
\(6x=42\)
\(x=42:6\)
\(x=7\)
c) \(35:\left(x+1\right)=7\)
\(x+1=35:7\)
\(x+1=5\)
\(x=5-1\)
\(x=4\)
d) \(12+\left(29-3x\right)=35\)
\(29-3x=35-12\)
\(29-3x=23\)
\(3x=29-23\)
\(3x=6\)
\(x=6:3\)
\(x=2\)
e) \(2.4^x+10^1=138\)
\(2.4^x=138-10\)
\(2.4^x=128\)
\(4^x=128:2\)
\(4^x=64=4^3\)
\(\Rightarrow x=3\)
f) \(7x=140\)
\(x=140:7\)
\(x=20\)
g) \(7\left(15-x\right)+14=84\)
\(7\left(15-x\right)=84-14\)
\(7\left(15-x\right)=70\)
\(15-x=70:7\)
\(15-x=10\)
\(x=15-10\)
\(x=5\)
h) \(3^x.5-15=390\)
\(3^x.5=390+15\)
\(3^x.5=405\)
\(3^x=405:5\)
\(3^x=81=3^4\)
\(\Rightarrow x=4\)
![](https://rs.olm.vn/images/avt/0.png?1311)
a)[25+(-15)]
=+10
b)512-(-88)-440-125
=512+88-440-125
=600-440-125
=160-125
=35
c)310+(-210)-907+107
=100-907+107
=-807+107
=-700
![](https://rs.olm.vn/images/avt/0.png?1311)
a) ! x ! + 23 = 45
! x ! = 45 - 23
! x ! = 22
-> x = 22 hoặc x = -22
b) ! x + 2 ! - 32 = 34
! x + 2 ! = 34 + 32
! x + 2 ! = 66
-> x + 2 = 66 hoặc x + 2 = -66
Nếu x + 2 = 66 thì Nếu x + 2 = -66
x = 66 - 2 = 64 x = -66 - 2 = -68
c) 234 + ( 34 - 23 ) + x = 546
234 + 11 + x = 546
245 + x = 546
x = 546 - 245
x = 301
a) \(\left|x\right|+23=45\)
\(\left|x\right|=45-23\)
\(\left|x\right|=22\)
\(\Rightarrow\orbr{\begin{cases}x=22\\x=-22\end{cases}}\)
vậy \(\orbr{\begin{cases}x=22\\x=-22\end{cases}}\)
b) \(\left|x+2\right|-32=34\)
\(\left|x+2\right|=34+32\)
\(\left|x+2\right|=66\)
\(\Rightarrow\orbr{\begin{cases}x+2=66\\x+2=-66\end{cases}}\Rightarrow\orbr{\begin{cases}x=64\\x=-68\end{cases}}\)
vậy \(\orbr{\begin{cases}x=64\\x=-68\end{cases}}\)
c) \(234+\left(34-23\right)+x=546\)
\(11+x=546-234\)
\(x=312-11\)
\(x=301\)
vậy \(x=301\)
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`@` `\text {Ans}`
`\downarrow`
`x + 257 = 981`
`=> x = 981 - 257`
`=> x = 724`
Vậy, `x = 724`
`x - 546 = 35`
`=> x = 35 + 546`
`=> x = 581`
Vậy, `x = 581`
`721 - x = 615`
`=> x = 721 - 615`
`=> x = 106`
Vậy, `x = 106`
`@` `\text {Kaizuu lv uuu}`
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