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Bài 3 :
a: \(MSC:12\\ \dfrac{4}{3}=\dfrac{4\times4}{3\times4}=\dfrac{16}{12};\dfrac{3}{4}=\dfrac{3\times3}{3\times4}=\dfrac{9}{12}\)
b: \(MSC:12\\ \dfrac{5}{4}=\dfrac{5\times3}{4\times3}=\dfrac{15}{12};\dfrac{5}{6}=\dfrac{5\times2}{6\times2}=\dfrac{10}{12}\)
c:\(MSC:24\\ \dfrac{3}{8}=\dfrac{3\times3}{8\times3}=\dfrac{9}{24};\dfrac{1}{6}=\dfrac{1\times2}{6\times2}=\dfrac{2}{12}\)
d: \(MSC:35\\ \dfrac{2}{5}=\dfrac{2\times7}{5\times7}=\dfrac{14}{35};\dfrac{4}{7}=\dfrac{4\times5}{7\times5}=\dfrac{20}{35}\)
Bài 3:
a: 4/3=16/12
3/4=9/12
b: 5/4=30/24
5/6=20/24
c: 3/8=18/48
1/6=8/48
d: 2/5=14/35
4/7=20/35
Bài 4:
a: 7/12=28/48
5/48=5/48
b: 4/100=4/100
8/25=32/100
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bài3
1. \(\frac{4}{3}\)= \(\frac{4x4}{3x4}\)=\(\frac{20}{12}\)
\(\frac{3}{4}\)=\(\frac{3x3}{4x3}\)=\(\frac{9}{12}\)
2.\(\frac{5}{4}\)=\(\frac{5x6}{4x6}\)=\(\frac{30}{24}\)
\(\frac{5}{6}\)=\(\frac{5x4}{6x4}\)=\(\frac{20}{24}\)
3.\(\frac{3}{8}\)=\(\frac{3x6}{8x6}\)=\(\frac{18}{48}\)
\(\frac{1}{6}\)=\(\frac{1x6}{6x8}\)=\(\frac{6}{48}\)
4.\(\frac{2}{5}\)=\(\frac{2x7}{5x7}\)=\(\frac{14}{35}\)
\(\frac{4}{7}\)=\(\frac{4x5}{7x5}\)=\(\frac{20}{35}\)
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\(\dfrac{3}{4}=\dfrac{3\cdot9}{4\cdot9}=\dfrac{27}{36}\)
\(\dfrac{5}{6}=\dfrac{5\cdot6}{6\cdot6}=\dfrac{30}{36}\)
\(\dfrac{4}{9}=\dfrac{4\cdot4}{9\cdot4}=\dfrac{16}{36}\)
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3/4 : 5/6 và 4/9 ( MC = 36 )
3/4 = 27/36
5/6 = 30/36
4/9 = 16/36.
\(\dfrac{3}{4}\);\(\dfrac{5}{6}\)và \(\dfrac{4}{9}\).
\(\dfrac{3}{4}\)=\(\dfrac{27}{36}\);\(\dfrac{5}{6}\)=\(\dfrac{30}{36}\) và \(\dfrac{4}{9}\)=\(\dfrac{16}{36}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
Quy đồng mẫu số 2 phân số \(\dfrac{4}{3}\) và \(\dfrac{3}{4}\) (MSC=12)
Ta có:
\(\dfrac{4}{3}=\dfrac{4\cdot4}{3\cdot4}=\dfrac{16}{12}\)
\(\dfrac{3}{4}=\dfrac{3\cdot3}{4\cdot3}=\dfrac{9}{12}\)
Vậy quy đồng mẫu số 2 phân số \(\dfrac{4}{3}\) và \(\dfrac{3}{4}\) ta được \(\dfrac{16}{12}\) và \(\dfrac{9}{12}\).
16/12 và 9/12