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\(=426-\left\{3\cdot\left(152-9\right)+1\right\}:10\)
\(=426-\left\{3\cdot143+1\right\}:10\)
=426-43
=383
![](https://rs.olm.vn/images/avt/0.png?1311)
a) (426 + x) : 5 = 120
(=) 426 + x = 120 :5
(=) 426 + x = 24
(=) x = 24 - 426
(=) x = - 402
Vậy x = - 402
b) 5844 : x -159 = 328
(=) 5844 : x = 328+ 159
(=) 5844 : x = 487
(=) x = 5844 : 487
(=) x = 12
Vậy x = 12
c) 32x + 1 = 27
(=) 32x = 27 -1
(=) 32x = 26
=> vô lý
vậy x thuộc tập hợp rỗng
d) (3x - 1)2 = 64
(=) (3x - 1)2 = 82
(=) 3x - 1 = 8
(=) 3x = 8 + 1
(=) 3x = 9
(=) x = 9 : 3
(=) x = 3
Vậy x = 3
( 426 + x ) : 5 = 120
( 426 + x ) = 600
x = 600 - 426
x = 174
b ) 5844 : x - 159 = 328
5844 : x = 328 + 159
5844 : x = 487
x = 5844 : 487
x = 12
d ) ( 3x - 1 ) 2 = 64
( 3x - 1 ) = 8
3x = 9
x = 3
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\(2\left(x-5\right)+3\left(2-3x\right)=5x+7\)
\(\Leftrightarrow2x-10+6-9x=5x+7\)
\(\Leftrightarrow\left(2x-9x\right)+\left(6-10\right)=5x+7\)
\(\Leftrightarrow-7x-4=5x+7\)
\(\Leftrightarrow-7x-5x=4+7\)
\(\Leftrightarrow-12x=11\)
\(\Leftrightarrow x=\frac{-11}{12}\)
\(3x-5\left(x-2\right)+7=4x-12\)
\(\Leftrightarrow3x-5x-10+7=4x-12\)
\(\Leftrightarrow\left(3x-5x\right)-\left(10-7\right)=4x-12\)
\(\Leftrightarrow-2x-3=4x-12\)
\(\Leftrightarrow-2x-4x=3-12\)
\(\Leftrightarrow-6x=-15\)
\(\Leftrightarrow x=\frac{-15}{-6}=\frac{5}{2}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
c.\(\dfrac{3}{7}+\dfrac{5}{7}:x=\dfrac{1}{3}\)
\(\dfrac{5}{7}:x=\dfrac{1}{3}-\dfrac{3}{7}\)
\(\dfrac{5}{7}:x=-\dfrac{2}{21}\)
\(x=\dfrac{5}{7}:-\dfrac{2}{21}\)
\(x=-\dfrac{15}{2}\)
d.\(3\dfrac{1}{4}:\left|2x-\dfrac{5}{12}\right|=\dfrac{39}{16}\)
\(\left|2x-\dfrac{5}{12}\right|=3\dfrac{1}{4}:\dfrac{39}{16}\)
\(\left|2x-\dfrac{5}{12}\right|=\dfrac{4}{3}\)
\(\rightarrow\left[{}\begin{matrix}2x-\dfrac{5}{12}=\dfrac{4}{3}\\2x-\dfrac{4}{12}=-\dfrac{4}{3}\end{matrix}\right.\) \(\rightarrow\left[{}\begin{matrix}2x=\dfrac{7}{4}\\2x=-\dfrac{11}{12}\end{matrix}\right.\) \(\rightarrow\left[{}\begin{matrix}x=\dfrac{7}{8}\\x=-\dfrac{11}{24}\end{matrix}\right.\)
A, \(\dfrac{4}{9}+x=\dfrac{5}{3}\)
\(x\)\(=\dfrac{5}{3}-\dfrac{4}{9}\)
\(x\)\(=\dfrac{11}{9}\)
B,\(\dfrac{3}{4}.x=\dfrac{-1}{2}\)
\(x=\dfrac{-1}{2}:\dfrac{3}{4}\)
\(x=\)\(\dfrac{-2}{3}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
Answer:
Bài 1:
\(\left(135-35\right).\left(-37\right)+37.\left(-42-58\right)\)
\(=100.\left(-37\right)+37.\left(-100\right)\)
\(=\left(-3700\right)+\left(-3700\right)\)
\(=-7400\)
\(-65.\left(87-17\right)-87.\left(17-65\right)\)
\(=\left(-65\right).87-\left(-65\right).17-87.17+87.65\)
\(=-\left(-65\right).17-87.17\)
\(=17.\left(65-87\right)\)
\(=-374\)
\([3.\left(-2\right)-\left(-8\right)].\left(-7\right)-\left(-2\right).\left(-5\right)\)
\(=[\left(-6\right)+8].\left(-7\right)-\left(-2\right).\left(-5\right)\)
\(=2.\left(-7\right)-10\)
\(=-24\)
Bài 2:
\(\left(-55\right).\left(-25\right).\left(-8\right)\)
\(=\left(-55\right).[\left(-25\right).\left(-8\right)]\)
\(=\left(-55\right).200\)
\(=-11000\)
\(\left(-1\right).\left(-2\right).\left(-3\right).\left(-4\right).\left(-5\right).10\)
\(=[\left(-1\right).10].[\left(-2\right).\left(-5\right)].[\left(-3\right).\left(-4\right)]\)
\(=\left(-10\right).10.12\)
\(=-1200\)
\(426-\left\{3.\left[152-\left(5-2\right)^2\right]\right\}:10\\ =426-\left\{3.\left[152-3^2\right]\right\}:10\\ =426-\left\{3.\left[152-9\right]\right\}\\ =426-\left\{3.143\right\}\\ =426-429=-3\)
426-{3.[152-(5-2)^2] +1} : 10=383
1672+[49+(13-7)^3]=1937