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Mình ko viết lại đầu bài nhé!
=> 3^x-1. (1+5) = 162
=>3^ x-1 . 6 = 162
=>3^x-1 =27
=>3^x-1 = 3^3
=>x-1 =3
=>x = 4
Vậy x=4
3^x-1.(1+5)=162
=>3^x-1=162:6
=>3^x-1=27=3^3
=>x-1=3
=>x=4
vậy x=4 nhé!
bài này dễ woa
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\(3^{-1}.3^x+5.3^{x-1}=162\)
=> \(\frac{1}{3}.3^x+5.3^x:3=162\)
=> \(\left(\frac{1}{3}+\frac{5}{3}\right).3^x=162\)
=> 2 . 3x = 162
=> 3x = 162 : 2
=> 3x = 81
=> 3x = 34
=> x = 4
Vậy ...
\(3^{-1}.3^x+5.3^{x-1}=162\)
\(\Rightarrow3^{-1+x}+5.3^{x-1}=162\)
\(\Rightarrow3^{x-1}+5.3^{x-1}=162\)
\(\Rightarrow3^{x-1}.\left(1+5\right)=162\)
\(\Rightarrow3^{x-1}.6=162\)
\(\Rightarrow3^{x-1}=162:6=27=3^3\)
\(\Rightarrow x-1=3\)
\(\Rightarrow x=4\)
Vậy x = 4
![](https://rs.olm.vn/images/avt/0.png?1311)
3x-1+5.3x-1=162
=>3x-1.(1+5)=162
=>3x-1.6=162=>3x-1=162:6=27=33
=>x-1=3=>x=4
5x+5x+2=650
=>5x+5x.52=650
=>5x.(1+25)=650
=>5x.26=650=>5x=650:26=25=52
=>x=2
![](https://rs.olm.vn/images/avt/0.png?1311)
b: Ta có: \(x+3x-2=10\)
\(\Leftrightarrow4x=12\)
hay x=3
![](https://rs.olm.vn/images/avt/0.png?1311)
3x - 1 + 5.3x - 1=162
3x - 1 .(1+5)=162
3x - 1=27
3x :31=27
3x=81
3x=34
=> x=4
\(a)3^{x-1}+5\cdot3^{x-1}=162\)
\(\Rightarrow3^{x-1}(1+5)=162\)
\(\Rightarrow3^{x-1}.6=162\)
\(\Rightarrow3^{x-1}=27\)
\(\Rightarrow x-1=3\)
\(\Rightarrow x=4\)
Câu b tự làm nhé
![](https://rs.olm.vn/images/avt/0.png?1311)
3x-1 + 5 . 3x-1 = 162
3x-1 . 1 + 5 . 3x-1 = 162
3x-1 . ( 1 + 5 ) = 162
3x-1 . 6 = 162
3x-1 = 162 : 6
3x-1 = 27
3x-1 = 33
=> x - 1 = 3
=> x = 3 + 1
=> x = 4
=0 nhe
3^x-1+5.3^x-1=162
3^x-1.(1+5)=162
3^x-1.6=162
3^x-1=162:6
3^x-1=27
3^x-1=3^3
x-1=3
x=3+1
x=4