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3x+1-3x-2=702
3x.31-3x:32=702
3x.3^1-3^x.1/9=702
3^x(3-1/9)=702
3^x.26/9=702
3^x=702:26/9
3^x=243
3^x=3^5
suy ra x=5
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1: Tìm x
a) Ta có: \(2\cdot3^x=3^{12}\cdot34+20\cdot27^4\)
\(\Leftrightarrow2\cdot3^x=3^{12}\cdot34+20\cdot3^{12}\)
\(\Leftrightarrow2\cdot3^x=3^{12}\cdot\left(34+20\right)\)
\(\Leftrightarrow2\cdot3^x-3^{12}\cdot54=0\)
\(\Leftrightarrow2\cdot3^x=3^{12}\cdot2\cdot27\)
\(\Leftrightarrow3^x=3^{12}\cdot3^3\)
\(\Leftrightarrow3^x=3^{15}\)
hay x=15
Vậy: x=15
b) Ta có: \(\left(2^x+1\right)^2+3\left(2^2+1\right)=2^2\cdot10\)
\(\Leftrightarrow\left(2^x+1\right)^2=40-3\cdot5=25\)
\(\Leftrightarrow\left[{}\begin{matrix}2^x+1=5\\2^x+1=-5\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}2^x=4\\2^x=-6\left(loại\right)\end{matrix}\right.\Leftrightarrow x=2\)
Vậy: x=2
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`x . 3/7 = 2/3`
`=>x= 2/3 : 3/7`
`=>x= 2/3 . 7/3`
`=>x=14/9`
`-----------`
`x : 8/11 = 11/3`
`=>x= 11/3 . 8/11`
`=>x= 88/33`
`=>x=8/3`
`-----------`
`4/7 . x - 2/3 = 1/5`
`=> 4/7 . x = 1/5 +2/3`
`=>4/7 . x =3/15 + 10/15`
`=>4/7 . x =13/15`
`=>x= 13/15 : 4/7`
`=>x= 13/15 xx 7/4`
`=>x= 91/60`
Lời giải:
$x.\frac{3}{7}=\frac{2}{3}$
$x=\frac{2}{3}: \frac{3}{7}=\frac{14}{9}$
-----------
$x: \frac{8}{11}=\frac{11}{3}$
$x=\frac{11}{3}.\frac{8}{11}=\frac{8}{3}$
-----------
$\frac{4}{7}x-\frac{2}{3}=\frac{1}{5}$
$\frac{4}{7}x=\frac{2}{3}+\frac{1}{5}=\frac{13}{15}$
$x=\frac{13}{15}: \frac{4}{7}=\frac{91}{60}$
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1) PT \(\Leftrightarrow\dfrac{x+3}{15}=\dfrac{4}{15}\) \(\Rightarrow x+3=4\) \(\Rightarrow x=1\)
Vậy ...
2) Mạnh dạn đoán đề là \(\left(2x-5\right)\left(x-3\right)=0\)
\(\Rightarrow\left[{}\begin{matrix}2x-5=0\\x-3=0\end{matrix}\right.\) \(\Rightarrow\left[{}\begin{matrix}x=\dfrac{5}{2}\\x=3\end{matrix}\right.\)
Vậy ...
3) PT \(\Rightarrow3x-4-2x+5=3\)
\(\Rightarrow x=2\)
Vậy ...
4) PT \(\Rightarrow\left[{}\begin{matrix}2x+1=0\\\dfrac{1}{2}x-1=0\end{matrix}\right.\) \(\Leftrightarrow\left[{}\begin{matrix}x=-\dfrac{1}{2}\\x=2\end{matrix}\right.\)
Vậy ...
3) Ta có: \(\left(3x-4\right)-\left(2x-5\right)=3\)
\(\Leftrightarrow3x-4-2x+5=3\)
\(\Leftrightarrow x+1=3\)
hay x=2
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a) 2 + (81 - x) = -34
81 - x = -34 - 2
81 - x = -36
x = 81 - (-36)
x = 81 + 36
x = 117
b) (-12).x = 60
x = 60 : (-12)
x = -5
c) 12 : (x - 1)2 = 3
(x - 1)2 = 12 : 3
(x - 1)2 = 4
(x - 1)2 = 22 (cùng số mũ)
⇒ x - 1 = 2
x = 2 + 1
x = 3
2+(81-x)=-34
81-x=(-34)-2
81-x=-36
x=81-(-36)
x= 117
![](https://rs.olm.vn/images/avt/0.png?1311)
a)-2x - 3.(x - 17) = 34 - (-x + 25)
- 2x - 3x + 51 = 34 + x - 25
- 2x - 3x - x = -51 + 34 - 25
- 6x = - 42
x = 7
Vậy x = 7
b)-2x-3.(x-17)=34-2(-x+25)
- 2x - 3x + 51 = 34 + 2x - 50
- 2x - 3x - 2x = - 51 + 34 - 50
7x = - 67
x = \(-\frac{67}{7}\)
Vậy \(x=-\frac{67}{7}\)
c)17x-(-16x-37)=2x +43
17x + 16x + 37 = 2x + 43
17x + 16x - 2x = -37 + 43
31x = 6
x = \(\frac{6}{31}\)
Vậy \(x=\frac{6}{31}\)
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a; - \(\dfrac{1}{3}\).(15\(x-9\)) + \(\dfrac{2}{7}\).(- \(x-34\)) = 1 - \(\dfrac{3}{4}\).(-16\(x+4\))
- 5\(x\) + 3 - \(\dfrac{2}{7}\)\(x\) - \(\dfrac{68}{7}\) = 1 + 12\(x\) - 3
12\(x\) + 5\(x\) + \(\dfrac{2}{7}x\) = 3 - \(\dfrac{68}{7}\) - 1 + 3
17\(x\) + \(\dfrac{2}{7}x\) = (3 - 1 + 3) - \(\dfrac{68}{7}\)
\(\dfrac{121}{7}\)\(x\) = 5 - \(\dfrac{68}{7}\)
\(\dfrac{121}{7}\) \(x\) = - \(\dfrac{33}{7}\)
\(x\) = - \(\dfrac{33}{7}\): \(\dfrac{121}{7}\)
\(x\) = - \(\dfrac{3}{11}\)
Vậy \(x\) = - \(\dfrac{3}{11}\)
\(2\left(x+3\right)+3\left(x+1\right)=34\)
\(\Rightarrow2x+6+3x+3=34\)
\(\Rightarrow\left(2x+3x\right)+\left(6+3\right)=34\)
\(\Rightarrow5x+9=34\)
\(\Rightarrow5x=25\)
\(\Rightarrow x=5\)