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a) \(3^n:3^2=3^{n-2}\)
\(\Rightarrow3^{n-2}=3^5\)
\(\Rightarrow n=5+2=7\)
b) \(2^n-64=2^6\)
\(\Rightarrow2^n-2^6=2^6\)
\(\Rightarrow2^n=2\cdot2^6=2^7\)
\(\Rightarrow n=7\)
c) \(2^n:16=128\)
\(\Rightarrow2^n:2^{16}=2^{n-16}=128\)
\(2^{n-16}=2^7\)
\(\Rightarrow n=7+16=23\)
\(3^n:3^2=243\)
\(3^{n-2}=243\)
\(3^{n-2}=3^5\)
\(n-2=5\Leftrightarrow n=7\)
![](https://rs.olm.vn/images/avt/0.png?1311)
Ko có giá trị của x
k mik nha
Học tốt
^_^
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a) \(2^x=16\)
\(2^x=2^4\)
\(\Rightarrow x=4\)
vay \(x=4\)
b) \(4^x=64\)
\(4^x=4^3\)
\(\Rightarrow x=3\)
vay \(x=3\)
c) \(15^x=225\)
\(15^x=15^2\)
\(\Rightarrow x=2\)
vay \(x=2\)
d) \(2^x-15=17\)
\(2^x=32\)
\(2^x=2^5\)
\(\Rightarrow x=5\)
vay \(x=5\)
e) \(2^x-64=2^6\)
\(2^x=2^6+64\)
\(2^x=128\)
\(2^x=2^7\)
\(\Rightarrow x=7\)
vay \(x=7\)
f) \(\left(7x-11\right)^3=2^5.5^2+200\)
\(\left(7x-11\right)^3=800+200\)
\(\left(7x-11\right)^3=1000\)
\(\left(7x-11\right)^3=10^3\)
\(\Rightarrow7x-11=10\)
\(\Rightarrow7x=21\)
\(\Rightarrow x=3\)
vay \(x=3\)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(6\cdot6\cdot6\cdot6\cdot3\cdot2\)
\(=6\cdot6\cdot6\cdot6\cdot\left(3\cdot2\right)\)
\(=6\cdot6\cdot6\cdot6\cdot6\)
\(=6^5\)
⇒ Chọn D
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Có thể đề là: \(\frac{1}{4}.\frac{2}{6}.\frac{3}{8}.\frac{4}{10}.....\frac{31}{64}=2^n\)
=> \(\frac{1.2.3.4....31}{\left(2.2\right)\left(2.3\right).\left(2.3\right)\left(2.4\right)\left(2.5\right)...\left(2.31\right).\left(2.32\right)}=2^n\)
=> \(\frac{1.2.3.4...31}{2^{16}.\left(2.3.4.5..31.32\right)}=2^n\) => \(\frac{1}{2^{16}.32}=2^n\) => 216.25.2n = 1
=> 231+n = 1 = 20 => 31 + n = 0 => n = -31
\(=\frac{1.2.3.....30}{4.6.8....64}=\frac{1}{2.2...2.64}=\frac{1}{2^{30}.2^6}=\frac{1}{2^{36}}\) ( 30 số 2)
=> 2^n = 1/2^36
=> n = -36
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6.2^n + 3.2^n = 9.2^n
=> 6.2^n + 3.2^n - 9.2^n = 0
2^n.(6+3-9) = 0
2^n.0=0
=> n thuộc Z
b) 3^n : 3^2 = 243
3^n = 27 = 3^3
=> n = 3
c) 2^n - 64 = 2^6
2^n = 2^12
=> n = 12
d) 2^n - 16 = 128
2^n = 144
...
bn tự tìm xem có 2 mũ bao nhiu = 144 ko nha!!!
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a)2n*23=64
C1:2n+3=26
=>n+3=6
n=6-3
n=3
C2:2n*8=64
2n=64/8
2n=8=23
=>n=3
2n*23=23*23
=>n=3
b)56:5n=625
C1:56-n=54
=>6-n=4
n=6-4
n=2
C2:5n=56/54
5n=52
=>n=2
C3:15625/5n=625
5n=15625/625
5n=52
=>n=2
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mọi người giúp mình nhé
26/8/2021 at 9:00 mình nộp r
![](https://rs.olm.vn/images/avt/0.png?1311)
\(a,125^5:25^3=\left(5^3\right)^5:\left(5^2\right)^3=5^{15-6}=5^9\)
\(b,27^6:9^3=\left(3^3\right)^6:\left(3^2\right)^3=3^{18-6}=3^{12}\)
\(c,4^{20}:2^{15}=\left(2^2\right)^{20}:2^{15}=2^{40-15}=2^{25}\)
\(d,24^n:2^{2n}=4^n.6^n:4^n=6^n\)
\(e,64^4.16^5:4^{20}=\left(2^6\right)^4.\left(2^4\right)^5:\left(2^2\right)^{20}=2^{24+20-40}=2^4=16\)
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a) \(2^x\)\(-\)\(64\)\(=\)\(2^6\)
\(2^x\)\(-\)\(2^6\)\(=\)\(2^6\)
\(2^x\) \(=\)\(2^6\)\(+\)\(2^6\)
\(2^x\) \(=\) \(64\)\(+\)\(64\)
\(2^x\) \(=\) \(128\)
\(\Rightarrow\) \(2^x\) \(=\) \(2^7\)
b) \(\left(7x-11\right)\)\(^3\)\(=\)\(2^5\)\(.\)\(5^2\)\(+\)\(200\)
\(\left(7x-11\right)\)\(^3\)\(=\)\(32\)\(.\)\(25\)\(+\)\(200\)
\(\left(7x-11\right)\)\(^3\)\(=\) \(1000\)
\(\left(7x-11\right)\)\(^3\)\(=\) \(10^3\)
\(\Rightarrow\)\(7x-11\)\(=\)\(10\)
\(7x\) \(=\)\(10+11\)
\(7x\) \(=\) \(21\)
\(x\) \(=\) \(21\)\(:\)\(7\)
\(x\) \(=\) \(3\)
\(2^x-64=2^6\)
\(2^x-64=64\)
\(2^x=64+64\)
\(2^x=128\)
\(\)Vì \(128=2^7\) \(\Rightarrow x=7\)
\(2^n:64=2^6\\ 2^n:2^6=2^6\\ 2^{n-6}=2^6\\ n-6=6\\ n=12\)