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\(=\dfrac{3^{30}\cdot2^{100}}{2^{30}\cdot3^{30}\cdot2^{75}}=\dfrac{1}{2^5}=\dfrac{1}{32}\)
\(\frac{\left(-27\right)^{10}.16^{25}}{-3.\left(-32\right)^{15}}=\frac{\left(-3\right)^{30}.\left(-2\right)^{100}}{\left(-3\right).\left(-2\right)^{75}}=\frac{\left(-3\right).\left(-3\right)^{29}.\left(-2\right)^{75}.\left(-2\right)^{25}}{\left(-3\right).\left(-2\right)^{75}}\)
= \(\left(-3\right)^{29}.\left(-2\right)^{25}\)
Đặt giá trị biểu thức là A, ta có:
\(A=\dfrac{\left(-27\right)^{10}.16^{25}}{6^{30}.\left(-32\right)^{15}}\)
\(A=\dfrac{\left(\left(-3\right)^3\right)^{10}.\left(2^4\right)^{25}}{2^{30}.3^{30}.\left(\left(-2\right)^5\right)^{15}}\)
\(A=\dfrac{\left(-3\right)^{30}.2^{100}}{2^{30}.3^{30}.\left(-2\right)^{75}}\)
\(A=\dfrac{3^{30}.2^{100}}{2^{30}.2^{75}.3^{30}}=\dfrac{1}{2^5}=\dfrac{1}{32}\)
\(3x+\frac{3}{6}=7x+\frac{3}{15}\)
\(\Rightarrow4x=\frac{3}{10}\Rightarrow x=\frac{3}{40}\)
Ta co:
2x+3/6 = 7x + 3/15
=> 3/6 = 5x + 3/15
=> x = (3/6 - 3/15):5 = 3/50
\(\dfrac{45^{10}\cdot5^{20}}{75^{15}}=\dfrac{\left(3^2\cdot5\right)^{10}\cdot5^{20}}{\left(3\cdot5^2\right)^{15}}=\dfrac{3^{20}\cdot5^{10}\cdot5^{20}}{3^{15}\cdot5^{30}}=3^5=243\\ \dfrac{6^6+6^3+3^3+3^6}{-73}=\dfrac{46656+216+27+729}{-73}=-\dfrac{47628}{73}\\ \dfrac{27^7+3^{15}}{9^9-27}=\dfrac{\left(3^3\right)^7+3^{15}}{\left(3^2\right)^9-3^3}=\dfrac{3^{21}+3^{15}}{3^{18}-3^3}=\dfrac{3^{15}\left(3^6+1\right)}{3^3\left(3^{15}-1\right)}=\dfrac{3^5\cdot730}{3^{15}-1}\\ \dfrac{8^{20}+4^{20}}{4^{25}+64^5}=\dfrac{\left(2^3\right)^{20}+\left(2^2\right)^{20}}{\left(2^2\right)^{25}+\left(2^6\right)^5}=\dfrac{2^{60}+2^{40}}{2^{50}+2^{30}}=\dfrac{2^{40}\left(2^{20}+1\right)}{2^{30}\left(2^{20}+1\right)}=2^{10}=1024\)
\(A=\dfrac{\left(-3\right)^{45}\cdot5^3\cdot2^{12}}{5^4\cdot3^{44}\cdot\left(-2\right)^{11}}=\dfrac{\left(-3\right)^{45}\cdot\left(-2\right)^{12}}{5\cdot\left(-3\right)^{44}\cdot\left(-2\right)^{11}}=\dfrac{\left(-3\right)\cdot\left(-2\right)}{5}=\dfrac{6}{5}\)
25 + 62 + 15 + 38 + 28 + 27 + 6
= 25 + 15 + 62 + 28 + 15 + 38 + 27
= 40 + 90 + 53 + 27
= 130 + 80
= 210
`((-27)^10 . 16^25)/(6^30 . (-32)^15)`
`= (3^30 . 2^100)/(2^30 . 3^30 . -2^75)`
`= (2^100)/(2^30 . -2^75)`
`= (2^70)/(-2^75)`
`= -2^145`
A = \(\dfrac{\left(-27\right)^{10}.16^{25}}{6^{30}.\left(-32\right)^{15}}\)
A = \(\dfrac{\left(3^3\right)^{10}.\left(2^4\right)^{25}}{\left(2.3\right)^{30}.\left(-32\right)^{15}}\)
A = \(\dfrac{3^{30}.2^{100}}{2^{30}.3^{30}.\left(-2^5\right)^{15}}\)
A = \(\dfrac{3^{20}.2^{100}}{3^{30}[2^{30}.\left(-2\right)^{75}].}\)
A = \(-\dfrac{2^{100}}{\left[2^{30}.\left(2\right)^{75}\right]}\)
A = -2100 - 30 - 75
A = - 270-75
A = -2-5
A = - \(\dfrac{1}{32}\)