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23x+4 = 1024
23x+4 = 210
3x + 4 = 10
3x = 10 - 4
3x = 6
x = 6 :3
x = 2
23x + 4=1024
đổi: 1024=210
=>23x +4=210
=>3x+4=10
3x=10-4
3x=6
x=6:3
x=2
![](https://rs.olm.vn/images/avt/0.png?1311)
\(2^{3x+4}=1024\)
Đổi 1024=\(2^{10}\)
\(=>2^{3x+4}\)=\(2^{10}\)
3x+4=\(2^{10}\)
3x=10-4
3x=6
x=6:3
x=2
tk m nhé
\(2^{3x+4}=1024\)
Đổi: \(1024=2^{10}\)
\(\Rightarrow3x+4=10\)
\(3x=10-4\)
\(3x=6\)
\(x=6:3\)
\(x=2\)
![](https://rs.olm.vn/images/avt/0.png?1311)
Tách ?
`a, 70 -5.(x-3) =45`
`=> 5.(x-3)= 70-45`
`=> 5.(x-3)=25`
`=>x-3=25:5`
`=>x-3=5`
`=>x= 5+3`
`=>x=8`
______
`b,10 + 2.x = 4^5:4^3`
`=> 10 + 2.x = 4^(5-3)`
`=> 10 + 2.x =4^2=16`
`=> 2.x=16-10`
`=>2.x=6`
`=>x=6:2`
`=>x=3`
_____
`c,60-3.x-2=51`
`=> 60-3.x= 51+2`
`=> 60-3.x=53`
`=>3.x=60-53`
`=> 3.x= 7`
`=>x= 7/3`
____
`d, 4.x-20=2^5:2^3`
`=> 4.x-20=2^(5-3)`
`=> 4.x-20=2^2`
`=> 4.x= 4+20`
`=>4.x=24`
`=>x=24:4`
`=>x=6`
____
`2^x . 4=16`
`=> 2^x=16:4`
`=>2^x= 4`
`=>2^x=2^2`
`=>x=2`
____
`f, 3^x . 3=243`
`=>3^x=243:3`
`=> 3^x=81`
`=> 3^x=3^3`
`=>x=3`
_____
`g, 64. 4^x =16^8`
`=> 4^3 . 4^x=(4^2)^8`
`=> 4^3 . 4^x = 4^(16)`
`=> 4^x= 4^(16-3)`
`=>4^x=4^(13)`
`=>x=13`
_____
`2^x . 16^2 =1024`
`=> 2^x= 1024 : 16^2`
`=>2^x=4`
`=>2^x=2^2`
`=>x=2`
a: =>5(x-3)=25
=>x-3=5
=>x=8
b: =>2x=16-10=6
=>x=3
c: =>58-3x=51
=>3x=7
=>x=7/3
d: =>4x-20=4
=>4x=24
=>x=6
e: =>2^x=4
=>2^x=2^2
=>x=2
f: =>3^x=81
=>3^x=3^4
=>x=4
g: =>4^x*4^3=4^16
=>x+3=16
=>x=13
h: =>2^x=1024/256=4=2^2
=>x=2
![](https://rs.olm.vn/images/avt/0.png?1311)
A x 2 = 1 - ( 1/2 + 1/4 + 1/8 + 1/16 + ..... + 1/512 + 1/1024 ) - 1/1024
A x 2 = 1 - 1/1024 + A
A x 2 - A = 1 - 1/1024
A = 1 - 1/1024
A = 1023 /1024
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
theo dau bai ta co
23x + 23x +23x +.......+23x ( 16 so hang )
23x . 16 = 1024
23x = 1024 : 16
23x = 64
23x = 26
=> 3x = 6
x = 6 : 3
x = 2
23x + 4=1024
đổi: 1024=210
=>23x +4=210
=>3x+4=10
3x=10-4
3x=6
x=6:3
x=2