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19 tháng 9 2018

Đổi k ko minasan

23 tháng 10 2023

\(\dfrac{4^5\cdot9^4-2\cdot6^9}{2^{10}\cdot3^8+6^{10}}\)

\(=\dfrac{2^{10}\cdot3^8-2^{10}\cdot3^9}{2^{10}\cdot3^8+2^{10}\cdot3^{10}}\)

\(=\dfrac{2^{10}\cdot3^8\left(1-3\right)}{2^{10}\cdot3^8\left(1+3^2\right)}=-\dfrac{2}{10}=-\dfrac{1}{5}\)

24 tháng 10 2023

\(\dfrac{4^5.9^4-2.6^9}{2^{10}.3^8+6^{10}}\)

\(=\dfrac{\left(2^2\right)^5.\left(3^2\right)^4-2.\left(2.3\right)^9}{2^{10}.3^8+\left(2.3\right)^{10}}\)

\(=\dfrac{2^{10}.3^8-2.2^9.3^9}{2^{10}.3^8+2^{10}.3^{10}}\)

\(=\dfrac{2^{10}.3^8-2^{10}.3^9}{2^{10}.3^8.\left(1+3^2\right)}\)

\(=\dfrac{2^{10}.3^8.\left(1-3\right)}{2^{10}.3^8.10}\)

\(=\dfrac{-2}{10}\)

\(=\dfrac{-1}{5}\)

Đề bài yêu cầu gì?

5 tháng 7 2017

tự làm cho giỏi

5 tháng 2 2023

\(A=\dfrac{4^5.9^4-2.6^9}{2^{10}.3^8+6^8.20}\)
\(=\dfrac{2^{10}.3^8-2.2^9.3^9}{2^{10}.3^8+2^8.3^8.2^2.5}\)
\(=\dfrac{2^{10}.3^8-2^{10}.3^9}{2^{10}.3^8+2^{10}.3^8.5}\)
\(=\dfrac{2^{10}.3^8\left(1-3\right)}{2^{10}.3^8\left(1+5\right)}\)
\(=-\dfrac{2}{6}=-\dfrac{1}{3}\)

5 tháng 2 2023

\(=\dfrac{\left(2^2\right)^5.\left(3^2\right)^4-2.3^9.2^9}{2^{10}.3^8+2^8.3^8.2^2.5}=\dfrac{2^{10}.3^8-2^{10}.3^9}{2^{10}.3^8+2^{10}.3^8.5}=\dfrac{2^{10}.3^8\left(1-3\right)}{2^{10}.3^8\left(1+5\right)}=\dfrac{-2}{6}=-\dfrac{1}{3}\)

22 tháng 7 2016

a)

\(5A=5+5^2+.....+5^{101}\)

\(\Rightarrow5A-A=\left(5+5^2+.....+5^{101}\right)-\left(1+5+.....+5^{100}\right)\)

\(\Rightarrow4A=5^{101}-1\)

\(\Rightarrow A=\frac{5^{101}-1}{4}\)

b)

\(2B=1+\left(\frac{1}{2}\right)^2+....+\left(\frac{1}{2}\right)^{100}\)

\(\Rightarrow2B-B=\left(1+\frac{1}{2^2}+.....+\frac{1}{2^{100}}\right)-\left(\frac{1}{2}+\frac{1}{2^2}+......+\frac{1}{2^{99}}\right)\)

\(\Rightarrow B=1-\frac{1}{2^{100}}\)

 

2.3x+2+4.3x+1=10.36

=>2.3.3x+1+4.3x+1=10.36

=>(6+4).3x+1=10.36

=>10.3x+1=10.36

=>3x+1=36

=>x+1=6

=>x=5