![](https://rs.olm.vn/images/avt/0.png?1311)
Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
2.34 + 23.5 - 7.(52 - 5)
2.81 + 8.5 - 7.(25 -5)
= 162 + 40 - 140
= 162 - 100
= 62
![](https://rs.olm.vn/images/avt/0.png?1311)
a: x-56:4=16
nên x-14=16
hay x=30
b: \(101+\left(36-4x\right)=105\)
\(\Leftrightarrow36-4x=4\)
hay x=8
Vì a: x-56:4=16
=>x-14=16
Hay:x=30
Vì b: 101+(36−4x)=105101+(36−4x)=105
⇔36−4x=4⇔36−4x=4
Hay:x=8
Vậy x={30:8}
Nếu sai thì thui nhá,đừng chửi mình!
![](https://rs.olm.vn/images/avt/0.png?1311)
1)\(x=\left(\dfrac{1}{5}+\dfrac{2}{3}\right):\dfrac{4}{7}=\left(\dfrac{3}{15}+\dfrac{10}{15}\right):\dfrac{4}{7}=\dfrac{13}{15}:\dfrac{4}{7}=\dfrac{91}{60}\)
2)\(x=\left(-\dfrac{3}{10}-\dfrac{3}{4}\right):\dfrac{1}{2}=\left(-\dfrac{6}{20}-\dfrac{15}{20}\right):\dfrac{1}{2}=-\dfrac{21}{20}:\dfrac{1}{2}=-\dfrac{21}{10}\)
3)\(x=-\dfrac{24}{36}-\dfrac{7}{15}=-\dfrac{2}{3}-\dfrac{7}{15}=\dfrac{-10}{15}-\dfrac{7}{15}=-\dfrac{17}{15}\)
1) \(\dfrac{4}{7}x=\dfrac{1}{5}+\dfrac{2}{3}\)
\(\dfrac{4}{7}x=\dfrac{13}{15}\)
\(x=\dfrac{91}{60}\)
2) \(\dfrac{1}{2}x=-\dfrac{3}{10}-\dfrac{3}{4}\)
\(\dfrac{1}{2}x=-\dfrac{21}{20}\)
\(x=-\dfrac{21}{10}\)
3) \(x=-\dfrac{24}{36}-\dfrac{7}{15}\)
\(x=\dfrac{-2}{3}+\dfrac{7}{15}\)
\(x=-\dfrac{17}{15}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
`#3107.101107`
a,
`2x + 3x = 5^7 \div 5^5`
$\Rightarrow (2 + 3)x = 5^{7 - 5}$
$\Rightarrow 5x = 5^2$
$\Rightarrow 5x = 25$
$\Rightarrow x = 25 \div 5$
$\Rightarrow x = 5$
Vậy, `x = 5`
b,
`5(7x - 45) = 2^3 . 5^2 - 3^2 . 20`
`\Rightarrow 5(7x - 45) = 8.25 - 9.20`
`\Rightarrow 5(7x - 45) = 40.5 - 36.5`
`\Rightarrow 5(7x - 45) = 5.(40 - 36)`
`\Rightarrow 5(7x - 45) = 5.4`
`\Rightarrow 7x - 45 = 4`
`\Rightarrow 7x = 49`
`\Rightarrow x = 49 \div 7`
`\Rightarrow x = 7`
Vậy, `x = 7.`
A) (2+3).x=5 mũ 2
5.x=5 mũ 2
5.x=25
x=25:5
x=5
vậy x=5
câu B ko bt làm bn ạ
![](https://rs.olm.vn/images/avt/0.png?1311)
1.3.5.7........99 = \(\frac{\left(1.3.5.7......99\right)\left(2.4.6......100\right)}{2.4.6......100}\)= \(\frac{1.2.3......99.100}{2^{50}\left(1.2.3.....50\right)}=\frac{51.52.53.......100}{2.2.2......2}=\frac{51}{2}.\frac{52}{2}....\frac{100}{2}\)(ĐPCM)
50 số 2
![](https://rs.olm.vn/images/avt/0.png?1311)
a: 7x+58=100
nên 7x=42
hay x=6
c: x-56:x=16
nên x-14=16
hay x=30
c)x - 56 : 4 = 16
x - 56 = 16 : 4
x- 56 = 4
x =4 + 56
x = 60
d)101 + (36 - 4x) = 105
(36- 4x ) = 105 - 101
36 - 4x = 4
4x = 36 - 4
4x = 32
x = 32:4
x = 8
![](https://rs.olm.vn/images/avt/0.png?1311)
a) (x + 1/5)2 = 9/25
=> (x + 1/5)2 = (3/5)2
=> \(\orbr{\begin{cases}x+\frac{1}{5}=\frac{3}{5}\\x+\frac{1}{5}=-\frac{3}{5}\end{cases}}\)
=> \(\orbr{\begin{cases}x=\frac{2}{5}\\x=-\frac{4}{5}\end{cases}}\)
Vậy ...
\(a,\text{ }\left(x+\frac{1}{5}\right)^2=\frac{9}{25}\)
\(\left(x+\frac{1}{5}\right)^2=\left(\pm\frac{3}{5}\right)^2\)
\(x+\frac{1}{5}=\pm\frac{3}{5}\)
\(\Rightarrow\orbr{\begin{cases}x+\frac{1}{5}=\frac{-3}{5}\\x+\frac{1}{5}=\frac{3}{5}\end{cases}}\) \(\Rightarrow\orbr{\begin{cases}x=\frac{-3}{5}-\frac{1}{5}\\x=\frac{3}{5}-\frac{1}{5}\end{cases}}\) \(\Rightarrow\orbr{\begin{cases}x=-\frac{4}{5}\\x=\frac{2}{5}\end{cases}}\)
\(\Rightarrow\text{ }x\in\left\{-\frac{4}{5}\text{ ; }\frac{2}{5}\right\}\)
bài làm
2 - ( | x | + 7 ) = -52
<=> | x | + 7 = 2 + 52
<=> | x | + 7 = 54
<=> | x | = 54 - 7 = 47
<=> x = 47 hoặc x = -47.
Vậy....
2-(|x|+7)=-52
|x|+7=2+52
|x|+7=54
|x|=54-7
|x|=47
\(\orbr{\begin{cases}x=47\\x=-47\end{cases}}\)
Vậy x=47;x=-47