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21 tháng 8 2021

13/10x = 7/2 + 5/2

13/10x = 6

x = 6 : 13/10

x = 6 . 10/13

x = 60/13

27 tháng 10 2023

a) 5.2² + (x + 3) = 5²

5.4 + x + 3 = 25

20 + x + 3 = 25

x + 23 = 25

x = 25 - 23

x = 2

b) 2³ + (x - 3²) = 5³ - 4³

8 + (x - 9) = 125 - 64

8 + x - 9 = 61

x - 1 = 61

x = 61 + 1

x = 62

c) 4.(x - 5) - 2³ = 2⁴.3

4x - 20 - 8 = 16.3

4x - 28 = 48

4x = 48 + 28

4x = 76

x = 76 : 4

x = 19

d) 5.(x + 7) - 10 = 2³.5

5x + 35 - 10 = 8.5

5x + 25 = 40

5x = 40 - 25

5x = 15

x = 15 : 5

x = 3

e) 7² - 7.(13 - x) = 14

49 - 91 + 7x = 14

7x - 42 = 14

7x = 14 + 42

7x = 56

x = 56 : 7

x = 8

27 tháng 10 2023

a) \(5\cdot2^2+\left(x+3\right)=5^2\)

\(\Rightarrow x+3=5^2-5\cdot2^2\)

\(\Rightarrow x+3=25-5\cdot4\)

\(\Rightarrow x+3=5\)

\(\Rightarrow x=5-3\)

\(\Rightarrow x=2\)

b) \(2^3+\left(x-3^2\right)=5^3-4^3\)

\(\Rightarrow8+\left(x-9\right)=125-64\)

\(\Rightarrow8+x-9=61\)

\(\Rightarrow x-1=61\)

\(\Rightarrow x=61+1\)

\(\Rightarrow x=62\)

c) \(4\left(x-5\right)-2^3=2^4\cdot3\)

\(\Rightarrow4\left(x-5\right)=2^4\cdot3+2^3\)

\(\Rightarrow4\cdot\left(x-5\right)=16\cdot3+8\)

\(\Rightarrow4\cdot\left(x-5\right)=56\)

\(\Rightarrow x-5=56:4\)

\(\Rightarrow x-5=14\)

\(\Rightarrow x=19\)

d) \(5\left(x+7\right)-10=2^3\cdot5\)

\(\Rightarrow5\left(x+7\right)=8\cdot5+10\)

\(\Rightarrow5\left(x+7\right)=40+10\)

\(\Rightarrow5\left(x+7\right)=50\)

\(\Rightarrow x+7=10\)

\(\Rightarrow x=10-7\)

\(\Rightarrow x=3\)

e) \(7^2-7\left(13-x\right)=14\)

\(\Rightarrow7\left(13-x\right)=7^2-14\)

\(\Rightarrow7\left(13-x\right)=49-14\)

\(\Rightarrow7\left(13-x\right)=35\)

\(\Rightarrow13-x=5\)

\(\Rightarrow x=13-5\)

\(\Rightarrow x=8\)

f) \(5x-5^2=10\)

\(\Rightarrow5x=10+5^2\)

\(\Rightarrow5x=10+25\)

\(\Rightarrow5x=35\)

\(\Rightarrow x=\dfrac{35}{5}\)

\(\Rightarrow x=7\)

g) \(9x-2\cdot3^2=3^4\)

\(\Rightarrow9x=3^4+2\cdot3^2\)

\(\Rightarrow9x=81+2\cdot9\)

\(\Rightarrow9x=99\)

\(\Rightarrow x=\dfrac{99}{9}\)

\(\Rightarrow x=11\)

h) \(10x+2^2\cdot5=10^2\)

\(\Rightarrow10x=10^2-2^2\cdot5\)

\(\Rightarrow10x=100-4\cdot5\)

\(\Rightarrow10x=80\)

\(\Rightarrow x=\dfrac{80}{10}\)

\(\Rightarrow x=8\)

i) \(125-5\left(4+x\right)=15\)

\(\Rightarrow5\left(4+x\right)=125-5\)

\(\Rightarrow5\left(4+x\right)=120\)

\(\Rightarrow4+x=\dfrac{120}{5}\)

\(\Rightarrow4+x=24\)

\(\Rightarrow x=24-4\)

\(\Rightarrow x=20\)

j) \(2^6+\left(5+x\right)=3^4\)

\(\Rightarrow5+x=3^4-2^6\)

\(\Rightarrow5+x=81-64\)

\(\Rightarrow5+x=17\)

\(\Rightarrow x=17-5\)

\(\Rightarrow x=12\)

18 tháng 1 2019

1)6x-8=3x+1

6x-3x=1+8

3x=9

x=3

Vậy x=3

2: 12-10x=25-30x

=>20x=13

=>x=13/20

3: \(3\left(2x+3\right)-2\left(4x-5\right)=10x+21\)

=>6x+9-8x+10=10x+21

=>10x+21=-2x+19

=>12x=-2

=>x=-1/6

4: \(\Leftrightarrow25x-15-6x+12=11-5x\)

=>19x-3=11-5x

=>24x=14

=>x=7/12

5: \(\Leftrightarrow8-12x-5+10x=4-6x\)

=>4-6x=-2x+3

=>-4x=-1

=>x=1/4

6: \(\Leftrightarrow32x-24-6+9x=13-40x\)

=>41x-30=13-40x

=>81x=43

=>x=43/81

7: \(\Leftrightarrow10x-5+20x=5x-11\)

=>30x-5=5x-11

=>25x=-6

=>x=-6/25

25 tháng 1 2018

Các bn ơi giúp mk với.

1 tháng 3 2020

a,10x+65=125

   10x      =125-65

       x      =60:10

       x      =6

Vậy:...

b,45-(5-2x)^3=2.3^2

   45-(5-2x)^3=18

    (5-2x)^3    =45-18

    (5-2x)^3    =27=3^3

=> 5-2x  = 3

     2x = 5-3

     x= 2:2

     x=1

Vậy:....

-Hok tốt ~ K mk nhak.

a, 10x + 65 = 125

10x = 125 - 65

10x = 60

x = 60 : 10

x = 6

b,45-(5-2x)^3=2.3^2

45 - ( 5 - 2x )^3 =18

(5 - 2x)^3 = 45 - 18

(5 - 2x )^3= 3^3

5 - 2x = 3

2x = 2

x = 1

c,2(x-3)-12=(-10)

2x - 6 -12 =-10

2x = -10 + 6 + 12

2x = 8

x = 4

d,x-12=(-13)+1+|-13|

x - 12 = -13 + 1 + 13

x - 12 = 1

x = 13

hok tốt!!!

20 tháng 1 2019

1)8(4x-3)-3(2-3x)=13-40x

(32x-24)-(6-9x)=13-40x

32x-24-6+9x=13-40x

41x-30=13-40x

41x+40x=13+30

81x=43

x=43/81

Vậy x=43/81

20 tháng 1 2019

2)10x-5(1-4x)=5x-11

10x-(5-20x)=5x-11

10x-5+20x=5x-11

30x-5=5x-11

30x-5x=5-11

25x=-6

x=-6/25

Vậy x=-6/25

a: \(\left(15-x\right)+\left(x-12\right)=7-\left(x-5\right)\)

=>7-x+5=15-x+x-12

=>12-x=3

hay x=9

b: \(\Leftrightarrow x-\left\{57-\left[42-23-x\right]\right\}=13-\left\{47+25-32+x\right\}\)

\(\Leftrightarrow x-\left\{57-19+x\right\}=13-\left\{40+x\right\}\)

=>x-38-x=13-40-x

=>-27-x=-38

=>x+27=38

hay x=11

e: \(x^2+3x+9⋮x+3\)

\(\Leftrightarrow x\left(x+3\right)+9⋮x+3\)

\(\Leftrightarrow x+3\in\left\{1;-1;9;-9;3;-3\right\}\)

hay \(x\in\left\{-2;-4;6;-12;0;-6\right\}\)

 

4 tháng 2 2023

\(-\dfrac{3}{5}\times x+\dfrac{1}{2}=\dfrac{4}{5}\)

\(-\dfrac{3}{5}\times x=\dfrac{4}{5}-\dfrac{1}{2}\)

\(-\dfrac{3}{5}\times x=\dfrac{3}{10}\)

\(x=\dfrac{3}{10}:-\dfrac{3}{5}\)

\(x=-\dfrac{1}{2}\)

Vậy \(x=-\dfrac{1}{2}\)

\(\dfrac{1}{2}\times x+\dfrac{3}{8}=\dfrac{7}{16}\)

\(\dfrac{1}{2}\times x=\dfrac{7}{16}-\dfrac{3}{8}\)

\(\dfrac{1}{2}\times x=\dfrac{1}{16}\)

\(x=\dfrac{1}{8}\)

Vậy \(x=\dfrac{1}{8}\)

\(\dfrac{2}{3}x-\dfrac{5}{6}x=-\dfrac{1}{2}\)

\(x\times\left(\dfrac{2}{3}-\dfrac{5}{6}\right)=-\dfrac{1}{2}\)

\(x\times\dfrac{-1}{6}=-\dfrac{1}{2}\)

\(x=3\)

Vậy \(x=3\)

\(\dfrac{2}{5}x+\dfrac{3}{10}x=-\dfrac{1}{5}\)

\(x\times\left(\dfrac{2}{5}+\dfrac{3}{10}\right)=-\dfrac{1}{5}\)

\(x\times\dfrac{7}{10}=-\dfrac{1}{5}\)

\(x=-\dfrac{2}{7}\)

Vậy \(x=-\dfrac{2}{7}\).

31 tháng 1 2017

\(-7.\left(5-x\right)-2.\left(x-10\right)=1\)

           \(-35+7x-2x+20=1\)

                                 \(-15+5x=1\)

                                                \(5x=1+15\)

                                                \(5x=16\)

                                                   \(x=\frac{16}{5}\)

\(-5.\left(2-x\right)+4.\left(x-3\right)=10x-15\)

        \(-10+5x+4x-12=10x-15\)

                              \(-22+9x=10x-15\)

                                \(9x-10x=-15+22\)

                                            \(-x=7\)

                                                \(x=-7\)

18 tháng 4 2023

\(1,-\dfrac{4}{7}+\dfrac{2}{3}\times\dfrac{-9}{14}\)

\(=\dfrac{-4}{7}+\dfrac{-18}{42}\)

\(=\dfrac{-4\times6}{7\times6}+\dfrac{-18}{42}\)

\(=\dfrac{-20}{42}+\dfrac{-18}{42}\)

\(=-\dfrac{38}{42}\)

\(=-\dfrac{19}{21}\)

\(2,\dfrac{17}{13}-\left(\dfrac{4}{13}-11\right)\)

\(=\dfrac{17}{13}-\dfrac{4}{13}+11\)

\(=\dfrac{13}{13}+11\)

\(=1+11\)

\(=12\)

\(3,8\dfrac{2}{7}-\left(3\dfrac{4}{9}+4\dfrac{2}{7}\right)\)

\(=\dfrac{58}{7}-\left(\dfrac{31}{9}+\dfrac{30}{7}\right)\)

\(=\dfrac{58}{7}-\dfrac{31}{9}-\dfrac{30}{7}\)

\(=\dfrac{58}{7}-\dfrac{30}{7}-\dfrac{31}{9}\)

\(=\dfrac{28}{7}-\dfrac{31}{9}\)

\(=\dfrac{28\times9}{7\times9}-\dfrac{31\times7}{9\times7}\)

\(=\dfrac{252}{63}-\dfrac{217}{63}\)

\(=\dfrac{35}{63}\)

\(=\dfrac{5}{9}\)

\(5,\left(\dfrac{2}{3}-1\dfrac{1}{2}\right):\dfrac{4}{3}+\dfrac{1}{2}\)

\(=\left(\dfrac{2}{3}-\dfrac{3}{2}\right):\dfrac{4}{3}+\dfrac{1}{2}\)

\(=\left(\dfrac{2\times2}{3\times2}-\dfrac{3\times3}{2\times3}\right):\dfrac{4}{3}+\dfrac{1}{2}\)

\(=\left(\dfrac{4}{6}-\dfrac{9}{6}\right):\dfrac{4}{3}+\dfrac{1}{2}\)

\(=\dfrac{-5}{6}:\dfrac{4}{3}+\dfrac{1}{2}\)

\(=\dfrac{-5}{6}\times\dfrac{3}{4}+\dfrac{1}{2}\)

\(=\dfrac{-15}{24}+\dfrac{1}{2}\)

\(=\dfrac{-15}{24}+\dfrac{1\times12}{2\times12}\)

\(=\dfrac{-15}{24}+\dfrac{12}{24}\)

\(=\dfrac{-3}{24}\)

\(=-\dfrac{1}{8}\)

\(6,\dfrac{-5}{13}+\dfrac{2}{5}+\dfrac{-8}{13}+\dfrac{3}{5}-\dfrac{3}{7}\)

\(=\left(\dfrac{-5}{13}+\dfrac{-8}{13}\right)+\left(\dfrac{2}{5}+\dfrac{3}{5}\right)-\dfrac{3}{7}\)

\(=\dfrac{-13}{13}+\dfrac{5}{5}-\dfrac{3}{7}\)

\(=-1+1-\dfrac{3}{7}\)

\(=-\dfrac{3}{7}\)

\(7,\dfrac{6}{5}\times\dfrac{3}{7}+\dfrac{6}{5}:\dfrac{7}{10}+\dfrac{6}{5}\)

\(=\dfrac{6}{5}\times\dfrac{3}{7}+\dfrac{6}{5}\times\dfrac{10}{7}+\dfrac{6}{5}\)

\(=\dfrac{6}{5}\times\left(\dfrac{3}{7}+\dfrac{10}{7}+1\right)\)

\(=\dfrac{6}{5}\times\left(\dfrac{3}{7}+\dfrac{10}{7}+\dfrac{1\times7}{1\times7}\right)\)

\(=\dfrac{6}{5}\times\left(\dfrac{3}{7}+\dfrac{10}{7}+\dfrac{7}{7}\right)\)

\(=\dfrac{6}{5}\times\dfrac{20}{7}\)

\(=\dfrac{120}{35}\)

\(=\dfrac{24}{7}\)

 

Giải:

A=2/3-2/5-2/7+2/11 / 13/3-13/5-13/7+13/11

A=1155.(2/3-2/5-2/7+2/11) / 1155.(13/3-13/5-13/7+13/11)

A=770-462-330+210 / 5005-3003-2145+1365

A=188/1222=2/13

(Số 1155 là BCNN(3;5;7;11) đấy nhé)

Chúc bạn học tốt!