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a)x+7=2x-1
<=>x-2x=-1-7
<=>-x=-8
<=>x=8
b)x+(2x-1)=7
<=>x+2x-1=7
<=>3x-1=7
<=>3x=8
\(\Leftrightarrow x=\frac{8}{3}\)
c)7+(2x-1)=x
<=>7+2x-1=x
<=>2x-1+7=x
<=>2x+6=x
<=>x-2x=6
<=>-x=6
<=>x=-6
![](https://rs.olm.vn/images/avt/0.png?1311)
a,(2x+7)+135=0 b, 1/2x-2/5=1/5
2x+7=0-135 1/2x=1/5+2/5
2x+7=-135 1/2x=3/5
2x=-135-7 x=3/5:1/2
2x=-142 x=6/5
x=-142:2 Vậy x=6/5
x=-71
Vậy x=-71
c, 10-|x+1|=5 d, 1/2x+150%x=2014
|x+1|=10-5 2x=2014
|x+1|=5 x=2014:2
*TH1:x+1=5 *TH2:x+1=-5 x=1007
x=5-1 x=-5-1 Vậy x=1007
x=4 x=-6
Vậy x=4 hoặc x=-6
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Tính nhanh.\(\frac{5}{1.4}+\frac{5}{4.7}+...+\frac{5}{57.40}\)
\(=5.\frac{1}{3}\left(\frac{3}{1.4}+\frac{3}{4.7}+...+\frac{4}{37.40}\right)\)
\(=\frac{5}{3}\left(\frac{1}{1}-\frac{1}{4}+\frac{1}{4}-\frac{1}{7}+...+\frac{1}{37}-\frac{1}{40}\right)\)
\(=\frac{5}{3}\left(\frac{1}{1}-\frac{1}{40}\right)\)
\(=\frac{5}{3}.\frac{39}{40}\)
\(=\frac{13}{8}\)
Rút gobj p/s
\(\frac{2019.2020+4038}{2022.2011-4044}\)
\(=\frac{2019.\left(2020+2\right)}{2020.\left(2011-2\right)}\)
\(=\frac{2019.2022}{2022.2019}\)
\(=\frac{1}{1}=1\)
Study well
Cho mk sorry nha dong thứ 2 từ trên cuống dưới phải là
\(5.\frac{1}{3}\left(\frac{3}{1.4}+\frac{3}{4.7}+...+\frac{3}{37.40}\right)\) nha
Sorry nhiều
Study well
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80-(5+80)=3-(x-7)
80-85=3-(x-7)
-5=3-(x-7)
3+(-5)=x-7
-2=x-7
7+(-2)=x
5=x
a/ \(80-\left(5+80\right)=3-\left(x-7\right)\)
\(\Leftrightarrow3-\left(x-7\right)=80-85=-5\)
\(\Leftrightarrow x-7=3-\left(-5\right)=8\)
\(\Rightarrow x=8+7=15\)
b/ \(150-\left(2x+1\right)=150-29=121\)
\(\Leftrightarrow2x+1=150-121=29\)
\(\Leftrightarrow2x=29-1=28\)
\(\Rightarrow x=28:2=14\)
![](https://rs.olm.vn/images/avt/0.png?1311)
a)\(\frac{1}{3}x+\frac{2}{5}\left(x-1\right)=0\)
\(\frac{1}{3}x+\frac{2}{5}x-\frac{2}{5}=0\)
\(\frac{11}{15}x-\frac{2}{5}=0\)
\(\frac{11}{15}x=\frac{2}{5}\)
\(x=\frac{6}{11}\)
b)(2x-3)(6-2x)=0
=>2x-3=0 hoặc 6-2x=0
=>x=3/2 hoặc x=3
c)\(x:\frac{3}{4}+\frac{1}{4}=-\frac{2}{3}\)
\(x:\frac{3}{4}=-\frac{11}{12}\)
\(x=-\frac{11}{16}\)
d)\(-\frac{2}{3}-\frac{1}{3}\left(2x-5\right)=\frac{3}{2}\)
\(-\frac{2}{3}-\frac{2}{3}x+\frac{5}{3}=\frac{3}{2}\)
\(-\frac{2}{3}x+1=\frac{3}{2}\)
\(-\frac{2}{3}x=\frac{1}{2}\)
\(x=-\frac{3}{4}\)
\(60\%x+\frac{2}{3}x=\frac{1}{3}.6\frac{1}{3}\)
\(\frac{3}{5}x+\frac{2}{3}x=\frac{19}{9}\)
\(\frac{19}{15}x=\frac{19}{9}\)
\(x=\frac{5}{3}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
Ta có: \(\dfrac{1}{2}x+150\%x=2020\)
\(\Leftrightarrow2x=2020\)
hay x=1010
Vậy: x=1010
![](https://rs.olm.vn/images/avt/0.png?1311)
`1/2 x + 150%x = 4044`
`1/2 x + 150/100 x= 4044`
`1/2x + 3/2x = 4044`
`(1/2+3/2)x= 4044`
`2x=4044`
`x=4044:2`
`x=2022`
Vậy `x=2022`
50% * x + 150% * x = 4044
( 0,5 + 1,5 ) * x = 4044
2 * x = 4044
x = 4044 : 2
x = 2022