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NT
0
12 tháng 3 2022
a: =(5/7+2/7)+(4/3+5/3)=3+1=4
b: =(17/12+7/12)+(29/7-8/7)
=2+3=5
c: =(2/5+3/5)+(6/9+1/3)+(7/4+1/4)
=1+2+1
=4
d: =(1/3+2/3)+(13/17+4/17)+(29/11+4/11)
=1+1+3=5
AN
2
23 tháng 2 2022
\(\dfrac{63}{18}và\dfrac{4}{18}\)
\(\dfrac{18}{21}và\dfrac{17}{21}\)
\(\dfrac{24}{36};\dfrac{9}{36}và\dfrac{20}{36}\)
5 tháng 7 2017
5/7 < 4/3
7/2 > 4/79
2/5 < 6/10
15/23 < 1
1/4 = 3/12
27/9 > 2
27/36 > 2/9
14/15 < 1
7/6 > 7/9
51/17 = 3/1
tk mình nha bạn, mình kp vs bạn r đó. .. ^^
5 tháng 7 2017
5/7 < 4/3 7/2 > 4/79 2/5 < 6/10 15/23 < 1 1/4 = 3/12 27/9 > 2 27/36 > 2/9 14/15 < 1 7/6 > 7/9 51/17 = 3/1
HM
10
24 tháng 8 2019
1+2+3+4+5+6+7+8+9+1+2+3+4+5+6+7+8+9+1+2+3+4+5+6+7+8+9=135
PT
2
9 tháng 5 2020
a) \(\frac{2}{9}+\frac{5}{6}\times\frac{4}{7}\)
\(=\frac{2}{9}+\frac{10}{21}\)
\(=\frac{44}{63}\)
b) \(\frac{21}{25}+\frac{4}{5}:\frac{8}{6}\)
\(=\frac{21}{25}+\frac{3}{5}\)
\(=\frac{36}{25}\)
c) \(\frac{17}{24}-\frac{1}{3}+\frac{3}{4}\)
\(=\frac{3}{8}+\frac{3}{4}\)
\(=\frac{9}{8}\)
9 tháng 5 2020
a) \(\frac{2}{9}+\frac{5}{6}\times\frac{4}{7}=\frac{2}{9}+\frac{10}{21}=\frac{14}{63}+\frac{30}{63}=\frac{44}{63}\)
b) \(\frac{21}{25}+\frac{4}{5}\div\frac{8}{6}=\frac{21}{25}+\frac{4}{5}\times\frac{6}{8}=\frac{21}{25}+\frac{3}{5}=\frac{21}{25}+\frac{15}{25}=\frac{36}{25}\)
c) \(\frac{17}{24}-\frac{1}{3}+\frac{3}{4}=\frac{17}{24}-\frac{8}{24}+\frac{18}{24}=\frac{27}{24}=\frac{9}{8}\)
2 tháng 7 2021
1) Ta có: \(\left(\dfrac{3}{4}\cdot\dfrac{5}{97}+\dfrac{1}{9}\cdot\dfrac{13}{47}\right)\cdot\left(\dfrac{1}{5}-\dfrac{7}{25}\cdot\dfrac{5}{7}\right)\)
\(=\left(\dfrac{3}{4}\cdot\dfrac{5}{97}+\dfrac{1}{9}\cdot\dfrac{13}{47}\right)\cdot\left(\dfrac{1}{5}-\dfrac{1}{5}\right)\)
=0
2) Ta có: \(\dfrac{8}{17}\cdot\dfrac{4}{15}+\dfrac{8}{17}\cdot\dfrac{22}{15}-\dfrac{8}{15}\cdot\dfrac{9}{17}\)
\(=\dfrac{8}{17}\left(\dfrac{4}{15}+\dfrac{22}{15}-\dfrac{9}{15}\right)\)
\(=\dfrac{8}{17}\cdot\dfrac{15}{15}=\dfrac{8}{17}\)
3) Ta có: \(\dfrac{2021}{2}\cdot\dfrac{1}{3}+\dfrac{4042}{4}\cdot\dfrac{1}{5}+\dfrac{6063}{3}\cdot\dfrac{22}{15}\)
\(=\dfrac{2021}{2}\left(\dfrac{1}{3}+\dfrac{1}{5}\right)+2021\cdot\dfrac{22}{15}\)
\(=\dfrac{2021}{2}\cdot\dfrac{8}{15}+\dfrac{2021}{2}\cdot\dfrac{44}{15}\)
\(=\dfrac{2021}{2}\cdot\dfrac{52}{15}\)
\(=\dfrac{52546}{15}\)
4) Ta có: \(\dfrac{4}{7}\cdot\dfrac{2}{13}+\dfrac{8}{13}:\dfrac{7}{4}+\dfrac{4}{7}:\dfrac{13}{2}+\dfrac{4}{7}\cdot\dfrac{1}{13}\)
\(=\dfrac{4}{7}\left(\dfrac{2}{13}+\dfrac{8}{13}+\dfrac{2}{13}+\dfrac{1}{13}\right)\)
\(=\dfrac{4}{7}\)
SASWWW
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TL
\(\frac{1}{2}+\frac{3}{7}=\frac{13}{14}\)
\(\frac{2}{3}-\frac{4}{9}=\frac{2}{9}\)
nhaaaaaa
HT