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x + (-23 ) = -100 + 77
x + ( -23 ) = -23
x = -23 - ( -23 )
x = -23 + 23
x = 0
( -15 ) + x = ( -14 ) - ( -57 )
( -15 ) + x = 43
x = 43 - ( -15 )
x = 43 + 15
x = 58
Mấy câu còn lại cũng dễ bn tự làm nha! Bye bye
\(x+\left(-23\right)=-100+77\)
\(\Leftrightarrow x-23=-23\)
\(\Leftrightarrow x=-23+23\)
\(\Leftrightarrow x=0\)
\(-15+x=-14-\left(-57\right)\)
\(\Leftrightarrow-15+x=43\)
\(\Leftrightarrow x=43+15\)
\(\Leftrightarrow x=48\)
\(11-\left(15+11\right)=x-\left(25-9\right)\)
\(\Leftrightarrow11-26=x-16\)
\(\Leftrightarrow x-16=15\)
\(\Leftrightarrow x=-15+16\)
\(\Leftrightarrow x=1\)
\(x-\left(17-x\right)=x-7\)
\(\Leftrightarrow x-17+x=x-7\)
\(\Leftrightarrow2x+17=x-7\)
\(\Leftrightarrow x-2x=7-17\)
\(\Leftrightarrow-x=-10\)
\(\Leftrightarrow x=10\)
\(\left(-12\right)^{2x}=56+10.13x\)
\(\Leftrightarrow144^x=56+10.13x\)
![](https://rs.olm.vn/images/avt/0.png?1311)
\((-12)^2\cdot x=56-(-10)\cdot13x\)
\(\Rightarrow144\cdot x=56-(-130x)\)
\(\Rightarrow144x=56+130x\)
\(\Rightarrow144x-130x=56\)
\(\Rightarrow14x=56\)
\(\Rightarrow x=4\)
P/S : Hoq chắc :D
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a) 2|x+1|=10
\(\left|x+1\right|\) = 10:2
\(\left|x+1\right|\) = 5
\(\left[{}\begin{matrix}x+1=5\\x+1=-5\end{matrix}\right.\) \(\Rightarrow\) \(\left[{}\begin{matrix}x=5-1\\x=\left(-5\right)-1\end{matrix}\right.\) \(\Rightarrow\) \(\left[{}\begin{matrix}x=4\\x=-6\end{matrix}\right.\)
b) (−12)2x=56+10.13x
144x= 56+130x
144x-130x= 56
14x= 56
x= 56: 14
x= 4
a) 2\(|\)x + 1\(|\) = 10 \(\Rightarrow\) \(|\)x + 1\(|\) = 5
\(\Rightarrow\) x + 1 = 5 hay x = 4
hoặc x + 1 = \(-\)5 hay x = \(-\)6.
ĐS : x = 4, x = \(-\)6.
b) x = 4.
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= 144 . x = 56 + 130. x
= 144 . x - 130 . x = 56
= x.[144 - 130] = 56
= x.14 = 56
= x = 56 : 14
= x = 4
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Đáp án là B
Ta có:
- 12 2 .x = 56 + 10.13x
144x = 56 + 130x
144x - 130x = 56
14x = 56
x = 4
![](https://rs.olm.vn/images/avt/0.png?1311)
a) (-12)2.x = 56 + 10.13x
=> 144.x = 56 + 130x
=> 144x - 130x = 56
=> 14x = 56
=>x = 56 : 14
=> x = 4
b) 80 - (x2 + 5) = 66
=> x2 + 5 = 80 - 66
=> x2 + 5 = 14
=> x2 = 14 - 5
=> x2 = 9
=> x2 = 32
=> \(\orbr{\begin{cases}x=3\\x=-3\end{cases}}\)
c) 9 - 25 = (7 - x) - (25 + 7)
=> -16 = (7 - x) - 32
=> 7 - x = -16 + 32
=> 7 - x = 16
=> x = 7 - 16
=> x = -9
d) \(\left(x+5\right)^2=16\)
=> \(\left(x+5\right)^2=4^2\)
=> \(\orbr{\begin{cases}x+5=4\\x+5=-4\end{cases}}\)
=> \(\orbr{\begin{cases}x=-1\\x=-9\end{cases}}\)
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Chú ý rằng |a| = b với b > 0 thì a = b hoặc a = - b.
a ) x ∈ − 5 8 ; 5 8 b ) x ∈ 1 12 ; 1 4
c ) x ∈ − 17 30 ; 9 10 d ) x ∈ − 19 4 ; 11 2
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a)
1 5 27 + 3 x − 7 9 3 = 24 27 3 x − 7 9 3 = 24 27 − 1 5 27 3 x − 7 9 3 = − 8 27 3 x − 7 9 = − 2 3 3 x = 1 9 x = 1 27
b)
2 x − 1 2 = 3 4 2 x = 5 4 x = 5 8 x = ± 5 8
c)
2 x − 1 3 + 5 6 = 1 2 x − 1 3 = 1 6 2 x − 1 3 = ± 1 6
TH1:
2 x − 1 3 = 1 6 2 x = 1 2 x = 1 4
TH2:
2 x − 1 3 = − 1 6 2 x = 1 6 x = 1 12
Vậy x = 1 4 hoặc x = 1 12
![](https://rs.olm.vn/images/avt/0.png?1311)
Sửa đề: \(2x+\dfrac{11}{6}+\dfrac{23}{12}+\dfrac{39}{20}+\dfrac{59}{30}+\dfrac{83}{42}+\dfrac{111}{56}=12\)
\(\Leftrightarrow2x+\left(2+2+2+2+2+2\right)-\left(\dfrac{1}{6}+\dfrac{1}{12}+\dfrac{1}{20}+\dfrac{1}{30}+\dfrac{1}{42}+\dfrac{1}{56}\right)=12\)
\(\Leftrightarrow2x-\left(\dfrac{1}{2}-\dfrac{1}{3}+\dfrac{1}{3}-\dfrac{1}{4}+...+\dfrac{1}{7}-\dfrac{1}{8}\right)=0\)
\(\Leftrightarrow2x-\dfrac{3}{8}=0\)
hay x=3/16