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\((\frac{4}{3}-\frac{1}{4}-\frac{5}{12})\)+2x=\(\frac{8}{5}:\frac{3}{5}\)
=\(\frac{2}{3}\)+2x=\(\frac{8}{3}\)
2x=\(\frac{8}{3}-\frac{2}{3}\)
2x=2
x=2:2
x=1
Vậy x=1
\(\left(\frac{4}{3}-\frac{1}{4}-\frac{5}{12}\right)+2x=\frac{8}{5}:\frac{3}{5}\)
\(\left(\frac{16}{12}-\frac{3}{12}-\frac{5}{12}\right)+2x=\frac{8}{5}.\frac{5}{3}\)
\(\frac{2}{3}+2x=\frac{8}{3}\)
\(2x=\frac{8}{3}-\frac{2}{3}\)
\(2x=2\)
\(x=2:2\)
\(x=1\)
Vậy \(x=1\)
Chúc bạn học thật tốt !!!
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Ta có \(\frac{6}{5}-\frac{1}{4}+\frac{4}{5}-\frac{3}{4}+\frac{1}{2}\)
\(=\left(\frac{6}{5}+\frac{4}{5}\right)-\left(\frac{1}{4}+\frac{3}{4}\right)+\frac{1}{2}\)
\(=2-1+\frac{1}{2}\)
\(=1+\frac{1}{2}\)
\(=\frac{3}{2}\)
\(\frac{6}{5}-\frac{1}{4}+\frac{4}{5}-\frac{3}{4}+\frac{1}{2}\)
\(=\left(\frac{6}{5}+\frac{4}{5}\right)-\left(\frac{1}{4}+\frac{3}{4}\right)+\frac{1}{2}\)
\(=\frac{10}{5}-\frac{4}{4}+\frac{1}{2}\)
\(=2-1+\frac{1}{2}\)
\(=1+\frac{1}{2}=\frac{3}{2}\)
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\(\left(3\frac{1}{2}+2x\right).2\frac{2}{3}=5\frac{1}{3}\)
<=>\(\left(\frac{7}{2}+2x\right).\frac{8}{3}=\frac{16}{3}\)
<=>\(\frac{28}{3}+\frac{16x}{3}=\frac{16}{3}\)
<=>\(\frac{16x}{3}=\frac{-2}{3}\)
<=>\(16x=-2\)
<=>\(x=\frac{-1}{8}\)
vậy \(x=\frac{-1}{8}\)
b,\(\left|2x+3\right|=5\)
xét x<0,ta co: \(\left|2x+3\right|=5\)<=> \(-2x+3=5\)<=>\(-2x=2\)<=>\(x=-1\)(loại)
xét x>0,ta co:\(\left|2x+3\right|=5\)<=>\(2x+3=5\)<=>\(2x=2\)<=>\(x=1\)
c,\(\frac{x-2}{4}=\frac{5+x}{3}\)
<=>\(\frac{3x-6}{12}=\frac{20+4x}{12}\)
=>\(3x-6=20+4x\)
<=>\(3x-6-20-4x=0\)
<=>\(-x-26=0\)
<=>\(-x=26\)
<=>\(x=-26\)
kl:.......
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2x-x=\(\frac{-1}{6}\)-\(\frac{1}{4}\)+\(\frac{1}{3}\)
x=\(\frac{-1}{12}\)
\(\frac{2x-1}{3}=\frac{x-1}{6}-\frac{1}{4}\)
\(\frac{8x-4}{12}=\frac{2x-2}{12}-\frac{3}{12}\)
\(8x-4=2x-2-3\)
\(8x-4-2x+2+3=0\)
\(6x+1=0\Leftrightarrow x=-\frac{1}{6}\)
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a) \(\left(2x+\frac{1}{3}\right)^4\ge0\Rightarrow A\ge-1\)
Dấu \(=\)xảy ra khi \(2x+\frac{1}{3}=0\Leftrightarrow x=-\frac{1}{6}\).
b) \(\left(\frac{4}{9}x-\frac{2}{15}\right)^6\ge0\Rightarrow B\le3\)
Dấu \(=\)xảy ra khi \(\frac{4}{9}x-\frac{2}{15}=0\Leftrightarrow x=\frac{3}{10}\).
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Ta có: \(\left(4,5-2x\right):\frac{3}{4}=1\frac{1}{3}\)
=> \(\left(4,5-2x\right):\frac{3}{4}=\frac{4}{3}\)
=> \(4,5-2x=1\)
=> \(2x=3,5\Rightarrow x=1,75\)
Vậy x=1,75
⇔2x+12x=4+45=245⇔2x+12x=4+45=245
=>24x=10x+5
=>14x=5
hay x=5/14