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câu trả lời đây
- (\(\frac{3}{5}x-0,75\)):\(\frac{3}{7}=\frac{14}{5}\)
- ( \(\frac{3}{5}x-\frac{75}{100}\))\(:\frac{3}{7}=\frac{14}{5}\)
- (\(\frac{3}{5}x-\frac{3}{4}\))\(:\frac{3}{7}=\frac{14}{5}\)
- bí rồi ai giúp mình giải thêm nhé
(3x/5 - 3/4):3/7 =14/5
(3x/5-3/4).7/3 =21x/15 - 21/12 = 14/5
21x =( 14/5 +21/12).15
21x = 273/4
x = 13/4
đã làm là đúng
x =
![](https://rs.olm.vn/images/avt/0.png?1311)
a, \(\Leftrightarrow2x^2=72\)
\(\Leftrightarrow x^2=36\)
\(\Leftrightarrow x=\pm6\)
Vậy ...
\(b,\Leftrightarrow\dfrac{3}{5}x-0,75=2\dfrac{4}{5}.\dfrac{3}{7}=\dfrac{6}{5}\)
\(\Leftrightarrow\dfrac{3}{5}x=\dfrac{6}{5}+0,75=\dfrac{39}{20}\)
\(\Leftrightarrow x=\dfrac{39}{20}:\dfrac{3}{5}=\dfrac{13}{4}\)
Vậy ...
\(c,\Leftrightarrow2x=1\dfrac{5}{6}.\dfrac{6}{11}-\dfrac{3}{10}=\dfrac{7}{10}\)
\(\Leftrightarrow x=\dfrac{7}{10}:2=\dfrac{7}{20}\)
Vậy ...
\(d,\Leftrightarrow\dfrac{1}{x-7\dfrac{1}{3}}=1.5:2\dfrac{1}{4}=\dfrac{2}{3}\)
\(\Leftrightarrow x-7\dfrac{1}{3}=\dfrac{3}{2}\)
\(\Leftrightarrow x=\dfrac{3}{2}+7\dfrac{1}{3}=\dfrac{53}{6}\)
Vậy ...
a) 2x2 - 72 = 0
\(\Rightarrow\) 2x2 = 72
\(\Rightarrow\) x2 = 36 = 62 = (- 6)2
\(\Rightarrow\) x = 6 hoặc x = - 6
Vậy x = 6 hoặc x = - 6
b) (\(\dfrac{3}{5}\)x - 0,75) : \(\dfrac{3}{7}\) = \(2\dfrac{4}{5}\)
\(\Rightarrow\) (\(\dfrac{3}{5}\)x - 0,75) : \(\dfrac{3}{7}\) = \(\dfrac{14}{5}\)
\(\Rightarrow\) \(\dfrac{3}{5}\)x - \(\dfrac{3}{4}\) = \(\dfrac{6}{5}\)
\(\Rightarrow\) \(\dfrac{3}{5}\)x = \(\dfrac{39}{20}\)
\(\Rightarrow\) x = \(\dfrac{13}{4}\)
Vậy x = \(\dfrac{13}{4}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
1) 3x - 6= 5x + 2
5x - 3x = -6 - 2
2x = -8
x = -4
2) 15 - x = 4x - 5
4x + x = 15 + 5
5x = 20
x = 4
Tương tự như trên
![](https://rs.olm.vn/images/avt/0.png?1311)
a)21/4+x=-0,5%
5,25+x=-50
x=-50-5,25
x=-55,25
b)2x2-72=0
2x2=0+72
2x2=72
x2=72/2
x2=36
x=62=(-6)2
x={6;-6}
0,35x=7/20
x=1
\(0,75.x-\frac{2}{5}.x=\frac{7}{20}\)
=> \(\frac{3}{4}.x-\frac{2}{5}.x=\frac{7}{20}\)
=> \(x\left(\frac{3}{4}-\frac{2}{5}\right)=\frac{7}{20}\)
=> \(x.\frac{7}{20}=\frac{7}{20}\)
=> x=1