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a: =234x(45+54+1)
=234x100
=23400
b: =(8x125)x(50x20)
=1000x1000
=1000000
a = 243x(45+54+1)
=243 x 100
=24300
b = (20 x 50 ) x (8x125)
=1000x1000
=1000000
a: \(\left(24-234\right)+\left(234-24-77\right)\)
\(=24-234+234-24-77\)
\(=\left(24-24\right)+\left(234-234\right)-77\)
=0+0-77
=-77
b: \(\left(13-135+49\right)-\left(13+49\right)\)
\(=13-135+49-13-49\)
\(=\left(13-13\right)+\left(49-49\right)-135\)
=0+0-135
=-135
c: \(159-524-\left(59-424\right)\)
\(=159-524-59+424\)
\(=\left(159-59\right)-\left(524-424\right)\)
=100-100
=0
d: \(\left(36+79\right)+\left(145-79-36\right)\)
\(=36+79+145-79-36\)
\(=\left(36-36\right)+\left(79-79\right)+145\)
=0+0+145
=145
e: \(334-\left(117+234\right)+\left(42+117\right)\)
\(=334-117-234+42+117\)
\(=\left(334-234\right)+\left(117-117\right)+42\)
=100+0+42
=142
f: \(271-\left[\left(-43\right)+271-\left(-17\right)\right]\)
\(=271+43-271+\left(-17\right)\)
\(=\left(271-271\right)+\left(43-17\right)\)
=0+26
=26
43 x 27 + 93 x 43 + 57 x 61 + 59 x 57
= 43 x ( 27 + 93 ) + 57 x ( 61 + 59 )
= 43 x 120 + 57 x 120
= 120 x ( 43 + 57 )
= 120 x 100
= 1200
b) 64 x 6 + 81 x 4 + 17 x 6
= 6 x ( 64 + 17 ) + 81 x 4
= 6 x 81 + 81 x 4
= 81 x ( 6 + 4 )
= 81 x 10
= 810
A) =43 x (27+93)+57*(61+59)
=43*120+57*120
=120*(43+57)
=120*100
=12000
a ) 159 − 524 − 59 − 424 ; = 159 − 524 − 59 + 424 = 159 − 59 − 524 − 424 = 100 − 100 = 0 b ) 36 + 79 + 145 − 79 − 36 ; = 36 + 79 + 145 − 79 − 36 = 36 − 36 + 79 − 79 + 145 = 145 c ) 334 − 117 + 234 + 42 + 117 ; = 334 − 117 − 234 + 42 + 117 = 334 − 234 − 117 − 117 + 42 = 100 + 42 = 142 d ) 271 − − 43 + 271 − − 17 . = 271 − − 43 + 271 + 17 = 271 + 43 − 271 − 17 = 271 − 271 + 43 − 17 = 26
\(\dfrac{59-x}{41}+\dfrac{57-x}{43}+\dfrac{55-x}{45}+\dfrac{53-x}{47}+\dfrac{51-x}{49}=-5\)
\(\Leftrightarrow\dfrac{59-x}{41}+1+\dfrac{57-x}{43}+1+\dfrac{55-x}{45}+1+\dfrac{53-x}{47}+1+\dfrac{51-x}{49}+1=0\)
\(\Leftrightarrow\dfrac{100-x}{41}+\dfrac{100-x}{43}+\dfrac{100-x}{45}+\dfrac{100-x}{47}+\dfrac{100-x}{49}=0\)
\(\Leftrightarrow\left(100-x\right)\left(\dfrac{1}{41}+\dfrac{1}{43}+\dfrac{1}{45}+\dfrac{1}{47}+\dfrac{1}{49}\right)=0\)
Mà \(\dfrac{1}{41}+\dfrac{1}{43}+\dfrac{1}{45}+\dfrac{1}{47}+\dfrac{1}{49}\ne0\)
\(\Leftrightarrow100-x=0\Leftrightarrow x=100\)
Vậy x = 100
Mình bạn chép đề sai, đề bài như này mới đúng nhé, bạn check lại xem đề nha :
\(\frac{59-x}{41}+\frac{57-x}{43}+\frac{55-x}{45}=-3\)
\(\Leftrightarrow\frac{59-x}{41}+1+\frac{57-x}{43}+1+\frac{55-x}{45}+1=0\)
\(\Leftrightarrow\frac{100-x}{41}+\frac{100-x}{43}+\frac{100-x}{45}=0\)
\(\Leftrightarrow\left(100-x\right)\left(\frac{1}{43}+\frac{1}{45}+\frac{1}{41}\right)=0\)
\(\Leftrightarrow100-x=0\left(\frac{1}{41}+\frac{1}{43}+\frac{1}{45}\ne0\right)\)
\(\Leftrightarrow x=100\)
Vậy : \(x=100\)
\(\dfrac{59-x}{41}+\dfrac{57-x}{43}+\dfrac{55-x}{45}+\dfrac{53-x}{47}+\dfrac{51-x}{49}=-5\)
\(\Leftrightarrow\dfrac{59-x}{41}+1+\dfrac{57-x}{43}+1+\dfrac{55-x}{45}+1+\dfrac{53-x}{47}+1+\dfrac{51-x}{49}+1=0\)
=>100-x=0
hay x=100
a, \(\left(-236\right).41+236.\left(-59\right)=\left(-236\right).\left(41+59\right)=\left(-236\right).100=-23600\)
b,\(138.\left(-125\right)-\left(-138\right).25=138.\left[\left(-125\right)-\left(-25\right)\right]=138.100=13800\)
c, \(\left(-271\right).\left(-159\right)+271.\left(-59\right)=271.\left[159+\left(-59\right)\right]=217.100=27100\)
d, \(129.\left(-73\right)+\left(-129\right).27=129.\left(-73-27\right)=129.\left(-100\right)=-12900\)
e, \(256.\left(-57\right)-\left(-256\right).\left(-43\right)=256.\left(-57-43\right)=256.\left(-100\right)=-25600\)
f, \(\left(-234\right).67+234.\left(-33\right)=234.\left(-67-33\right)=234.\left(-100\right)=-23400\)
ko cần chép đề nha
a. 236x(-41)+236x(-59)
=236x[(-41)+(-59)]
=236x(-100)
=-23600
b.-138x125-(-138)x25
=(-138)x(125-25)
=(-138)x100
=-13800
c.câu này mik giải thích là khi chuyển dấu "-" của -59 sang -271 thì -- sẽ biến thành +
c. 271x159+271x(-59)
=271x(159+(-59))
=271x100
=27100
d(-129)x73+(-129)x27
=(-129)x(73+27)
=(-129)x100
=-12900
e. (-256)x57-(-256)x(-43)
=(-256)x[57-(-43)]
=-256x100
=-25600