(x+42)tất cả mũ 2 nhân 115 = 4 nhân 115
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a, (-17) + (-83)
= -(17 + 83)
= 100
b, 22.(-115) + 15.22 - 20220
= -22.(115 - 15) - 1
= -4.100 - 1
= -400 - 1
= -401
c, -53.(-25) + 53.(-89) + (-6)2.(-53)
= 53.25 - 53.89 - 53.36
= 53.(25 - 89 - 36)
= 53. (-100)
= - 5300
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bài 1) thực hiện phép tính
a) \(4^5-81:3^2=1024-9=1015\)
b) \(3^2.22-3^2.12=3^2.2\left(11-6\right)=18.5=90\)
c) \(2^3.15-\left[115-\left(12-5\right)\right]=120-\left(115-12+5\right)=120-115+12-5=12\)
d) \(3.3^2-19^{21}:19^{20}+2010^0=27-19+1=9\)
e)\(7^{25}:\left(7^{21}.46+7^{21}.3\right)=7^{25}:\left(7^{21}.49\right)=\frac{7^{21}.7^4}{7^{21}.49}=\frac{2401}{49}=49\)
bài 2)Tim x
a) 716 - (x - 143) = 695
<=> x - 143 = 716 - 695
<=> x - 143 = 21
<=> x = 21 + 143
<=> x = 164
vậy x = 164
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a) \(\frac{7^3.5^8}{49.25^4}=\frac{7^3.5^8}{7^2.\left(5^2\right)^4}=7.\frac{5^8}{5^8}=7\)
b) \(\frac{3^9.25.5^3}{15.625.3^8}=\frac{3.3^8.5^2.5^3}{3.5.5^4.3^8}=\frac{5^5}{5^5}=1\)
c) Đề hơi sai roi bạn oi
d) \(\left(\frac{2}{5}-\frac{1}{2}\right)^2+\left(\frac{1}{2}+\frac{3}{5}\right)^2=\left(\frac{-1}{10}\right)^2+\left(\frac{11}{10}\right)^2=\frac{1}{100}+\frac{121}{100}=\frac{61}{50}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(A=\frac{\left(4^2\right)^{17}.64^{36}}{8^{35}.32^{34}}\)
\(A=\frac{\left(2^4\right)^{17}.\left(2^6\right)^{36}}{\left(2^3\right)^{35}.\left(2^5\right)^{34}}\)
\(A=\frac{2^{68}.2^{216}}{2^{105}.2^{170}}=\frac{2^{284}}{2^{275}}=2^9=512\)
![](https://rs.olm.vn/images/avt/0.png?1311)
Ta có : \(\frac{2^7.3^4}{3^3.2^5}=\frac{2^2.3}{1.1}=4.3=12\)
k cho mk nha!
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a/ 26176
b/ 8
c/472392
d/ Ko tính dc
Thấy mình đẳng cấp ko
Cho mình 10 k nhé
cứu
\(\left(x+42\right)^2\cdot115=4\cdot115\)
=>\(\left(x+42\right)^2=4\)
=>\(\left[{}\begin{matrix}x+42=2\\x+42=-2\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=-40\\x=-44\end{matrix}\right.\)