Question

[Lê Thị Quỳnh]

Giải hộ mk phương trình này với nha :

      \(\frac{3000-10x}{x}.\left(x+10\right)+8x=3000\)

Answer 1

[Đức Phạm]

\(\frac{3000-10x}{x}.\left(x+10\right)+8x=3000\)

\(\Leftrightarrow\left(3000-10x\right).\left(x+10\right)+8x^2=3000x\)

\(\Leftrightarrow3000x+30000-10x^2-100x+8x^2-3000x=0\)

\(\Leftrightarrow-2x^2-100x+30000=0\)

\(\Leftrightarrow\orbr{\begin{cases}x=100\\x=-150\end{cases}}\)

Answer 2

[nguyen hải]

    3000x-10x^2+30000-100x                8x^2

<>---------------------------------------     +    ------------    =  3000

                     x                                    x

<> -10x^2+2900x+30000+8x^2=3000x

<> -2x^2-100x+30000=0

<>2x^2+100x-30000=0

<>x=-150

<>x=100