\(S=1+2+2^2+2^3+...+2^9.\) So sánh S với
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2S=2+2^2+..+2^10
=>2S-S=2^10-1
=>S=2^8.4-1
=>S<5.2^8
![](https://rs.olm.vn/images/avt/0.png?1311)
\(S=1+2+2^2+...+2^9\)
\(\Rightarrow2S=2+2^2+2^3+...+2^{10}\)
\(\Rightarrow2S-S=\left(2+2^2+2^3+...+2^{10}\right)-\left(1+2+2^2+...+2^9\right)\)
\(\Rightarrow S=2^{10}-1< 2^{10}=2^7.2^3=2^7.8\)
Do \(5.2^8=5.2.2^7=10.2^7>2^7.8\) nên \(5.2^8>2^{10}>2^{10}-1\)
\(\Rightarrow5.2^8>2^{10}-1\)
Vậy \(5.2^8>2^{10}-1\)
S = 1 + 2 + 22 + 23 + ... + 29
2S = 2 + 22 + 23 + 24 + ... + 210
2S - S = (2 + 22 + 23 + 24 + ... + 210) - (1 + 2 + 22 + 23 + ... + 29)
S = 210 - 1 < 210 = 22.28 = 4.28 < 5.28
=> S < 5.28
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2S=2(1+2+22+...+29)
2S=2+22+...+210
2S-S=(2+22+...+210)-(1+2+22+...+29)
S=210-1=1024-1=1023
5*28=5*256=1280.Vì 1280>1023
=>5*28>210-1 <=> 5*28>S
![](https://rs.olm.vn/images/avt/0.png?1311)
2S=2(1+2+22+23+..+29)
2S=2+22+...+210
2S-S=(2+22+...+210)-(1+2+22+23+..+29)
S=210-1 (tới đây tách ra làm như Trinh Hai Nam)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(2S=2+2^2+2^3+2^4+...+2^{10}\)
=> \(2S-S=\left(2+2^2+2^3+2^4+...+2^{10}\right)-\left(1+2+2^2+2^3+...+2^9\right)\)
=> \(S=2^{10}-1=1024-1=1023\)
Mà \(5.2^8=5.256=1280\)
Vì 1023 < 1280
=> \(S<5.2^8\).
Ta có :
2S=2+2^2+2^3+...+2^10
2S-S=2+2^2+2^3+...+2^10-1-2-2^2-...-2^9
S=2^10-1
=>S<2^10 (1)
Ta lại có :
5.2^8>2^10 (2)
Tu (1) va (2) suy ra : S<5.2^8
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![](https://rs.olm.vn/images/avt/0.png?1311)
\(S=1+2+2^2+...+2^9\)
\(\Rightarrow2S=2+2^2+2^3+...+2^{10}\)
\(\Rightarrow S=2^{10}-1\)
Lại có \(5.2^8=\left(2^2+1\right).2^8=2^{10}+2^8\)
Vậy \(S< 5.2^8\)
\(S=1+2+2^2+2^3+...+2^9\)
\(\Rightarrow S=\dfrac{2^{9+1}-1}{2-1}\)
\(\Rightarrow S=2^{10}-1\)
\(\Rightarrow S=2^2.2^8-1\)
\(\Rightarrow S=4.2^8-1< 5.2^8\)
Vậy \(S< 5.2^8\)
So sánh S với \(5.2^8\)