K
Khách

Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.

25 tháng 12 2022

\(\dfrac{2}{67}-\left(\dfrac{3}{7}+\dfrac{2}{67}\right)\\ =\dfrac{2}{67}-\dfrac{215}{469}\\ =\dfrac{-3}{7}\)

25 tháng 12 2022

\(\dfrac{3}{4}.\dfrac{5}{2}+\dfrac{5}{4}.\dfrac{5}{2}\\ =\left(\dfrac{3}{4}+\dfrac{5}{4}\right).\dfrac{5}{2}\\ =2.\dfrac{5}{2}\\ =\dfrac{5}{1}\)

12 tháng 10 2021

=???

ok chị

2 tháng 11 2021

cái nịt

24 tháng 12 2022

\(\left(\dfrac{1}{3}+\dfrac{12}{67}+\dfrac{13}{41}\right)-\left(\dfrac{79}{67}-\dfrac{28}{41}\right)\)
\(=\dfrac{1}{3}+\dfrac{12}{67}+\dfrac{13}{41}-\dfrac{79}{67}+\dfrac{28}{41}\)
\(=\dfrac{1}{3}+\left(\dfrac{12}{67}-\dfrac{79}{67}\right)+\left(\dfrac{13}{41}+\dfrac{28}{41}\right)\)
\(=\dfrac{1}{3}+\left(-1\right)+1=\dfrac{1}{3}+0=\dfrac{1}{3}\)
\(\left(\dfrac{15}{4}-5x\right).\left(9x^2-4\right)=0\)
\(\left[{}\begin{matrix}\dfrac{15}{4}-5x=0\\9x^2-4=0\end{matrix}\right.\)
\(\left[{}\begin{matrix}5x=\dfrac{15}{4}\\9x^2=4\end{matrix}\right.\)
\(\left[{}\begin{matrix}x=\dfrac{3}{4}\\x=\dfrac{2}{3}\end{matrix}\right.\)

`4/7 + 2/3 = 12/21 + 14/21 = 26/21`

`5/6 -3/4 = 10/12 - 9/12 = 1/12`

`3/10 xx 15/6 = 3/10 xx 5/2 = 3/4`

`7/6 : 5/4 = 7/6 xx 4/5 = 14/15`

5 tháng 2 2023

`4/7 + 2/3 `

`=12/21 + 14/21`

`=28/21`

`5/6 - 3/4 `

`=20/24 - 18/24`

`=2/24`

`3/10 x 15/6`

`=3/4`

`7/6 : 5/4`

`=7/6 xx 4/5`

`=14/15`

28 tháng 1 2016

72

tick mk nha

28 tháng 1 2016

tick di la 72 do

15 tháng 4 2020

63:(39-2.(2x+1)^2)+4^3=67

\(63:\left(39-2\left(2x+1\right)^2\right)+64=67\)

\(63:\left(39-2\left(2x+1\right)^2\right)=3\)

\(39-2\left(2x+1\right)^2=21\)

\(2\left(2x+1\right)^2=18\)

\(\left(2x+1\right)^2=9\)

\(2x+1=3\)

\(2x=2\)

\(x=1\)

6 tháng 9 2021

\(\sqrt{4\sqrt{2}-\sqrt{4+16\sqrt{6-4\sqrt{2}}}}+\sqrt{\sqrt{3}+\sqrt{228+50\sqrt{67-16\sqrt{3}}}}\)

\(=\sqrt{4\sqrt{2}-\sqrt{4+16\sqrt{\left(\sqrt{2}-2\right)^2}}}+\sqrt{\sqrt{3}+\sqrt{228+50\sqrt{\left(\sqrt{3}-8\right)^2}}}\)

\(=\sqrt{4\sqrt{2}-\sqrt{4+16\left(2-\sqrt{2}\right)}}+\sqrt{\sqrt{3}+\sqrt{228+50\left(8-\sqrt{3}\right)}}\)

\(=\sqrt{4\sqrt{2}-\sqrt{36-16\sqrt{2}}}+\sqrt{\sqrt{3}+\sqrt{628-50\sqrt{3}}}\)

\(=\sqrt{4\sqrt{2}-\sqrt{\left(4\sqrt{2}-2\right)^2}}+\sqrt{\sqrt{3}+\sqrt{\left(\sqrt{3}-25\right)^2}}\)

\(=\sqrt{4\sqrt{2}-4\sqrt{2}+2}+\sqrt{\sqrt{3}+25-\sqrt{3}}\)

\(=\sqrt{2}+5\)

6 tháng 9 2021

\(\sqrt{4\sqrt{2}-\sqrt{4+16\sqrt{6-4\sqrt{2}}}}+\sqrt{\sqrt{3}+\sqrt{228+50\sqrt{67-16\sqrt{3}}}}=\sqrt{4\sqrt{2}-\sqrt{4+16\sqrt{\left(2-\sqrt{2}\right)^2}}}+\sqrt{\sqrt{3}+\sqrt{228+50\sqrt{\left(8-\sqrt{3}\right)^2}}}=\sqrt{4\sqrt{2}-\sqrt{4+32-16\sqrt{2}}}+\sqrt{\sqrt{3}+\sqrt{228+400-50\sqrt{3}}}=\sqrt{4\sqrt{2}-\sqrt{36-16\sqrt{2}}}+\sqrt{\sqrt{3}+\sqrt{628-50\sqrt{3}}}=\sqrt{4\sqrt{2}-4\sqrt{2}+2}+\sqrt{\sqrt{3}+25-\sqrt{3}}=\sqrt{2}+\sqrt{25}=5+\sqrt{2}\)

6 tháng 11 2016

2/15-2/65-4/39=4/39-4/39=0

32/13-(7/23+8/23)=32/13-15/23=541/299

(1/3+12/67+13/41) - (79/67 - 28/41)=6836/8241-1363/2747=1/3

38/145 - (8/45-17/51-3/11)=38/145-(-212/495)=1982/2871