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13 tháng 7 2022

\(\dfrac{45^4.5^5}{27^3.25^4}=\dfrac{9^4.5^4.5^5}{3^9.5^8}=\dfrac{3^8.5^9}{3^9.5^8}=\dfrac{5}{3}\)

13 tháng 7 2022

\(\dfrac{45^{4^{ }}.5^5}{27^3.25^4}\) = \(\dfrac{9^4.5^4.5^5}{^{ }9^{3^{ }}.3^3.5^{4^{ }}.5^4}\)\(\dfrac{9.5}{3^3}\)=\(\dfrac{5}{3}\)

23 tháng 9 2019

= 3.25 - 5 . [43 - (27 - 25) : 1]

= 75 - 5 . [64 - 2]

= 75 - 5 . 62

= 75 - 310

= - 245

23 tháng 9 2019

A , sr nha

Kq: -235 bn ak

22 tháng 7 2023

a) \(\dfrac{27^3\cdot11+9^5\cdot5}{3^9\cdot2^4}\)

\(=\dfrac{3^9\cdot11+3^{10}\cdot5}{3^9\cdot2^4}\)

\(=\dfrac{3^9\cdot\left(11+3\cdot5\right)}{3^9\cdot2^4}\)

\(=\dfrac{11+15}{16}\)

\(=\dfrac{26}{16}\)

\(=\dfrac{13}{8}\)

b) \(\dfrac{5^8+2^2\cdot25^4+2^3\cdot125^3-15^4\cdot5^4}{4^2\cdot625^2}\)

\(=\dfrac{5^8+2^2\cdot5^8+2^3\cdot5^9-3^4\cdot5^4\cdot5^4}{2^4\cdot5^8}\)

\(=\dfrac{5^8\cdot\left(1+2^2+2^3\cdot5-3^4\right)}{5^8\cdot2^4}\)

\(=\dfrac{1+4+40-81}{16}\)

\(=\dfrac{-36}{16}\)

\(=\dfrac{-9}{4}\)

c) \(\dfrac{4^5\cdot9^4-2\cdot6^9}{2^{10}\cdot3^8+6^8\cdot20}\)

\(=\dfrac{2^{10}\cdot3^8-2\cdot2^9\cdot3^9}{2^{10}\cdot3^8+2^{10}\cdot3^8\cdot5}\)

\(=\dfrac{2^{10}\cdot3^8\cdot\left(1-3\right)}{2^{10}\cdot3^8\cdot\left(1+5\right)}\)

\(=\dfrac{-2}{6}\)

\(=-\dfrac{1}{3}\)

5 tháng 5 2021

a) \(\dfrac{-4}{6}\)

b) \(\dfrac{1}{3}\)-\(\dfrac{20}{60}\)

= 0 

c) \(-20^2\)+(\(-50^3\))

= -400 + (-125000)

=-125400

d) \(\dfrac{-2}{7}\)+\(\dfrac{15}{35}\)

\(\dfrac{-10}{35}\)+\(\dfrac{15}{35}\)

\(\dfrac{5}{35}\)=\(\dfrac{1}{7}\)

5 tháng 5 2021

Nhớ tick cho mk nha

14 tháng 12 2023

Ai giúp mình làm bước tiếp theo với ạ loading...  

=>\(\sqrt{5x+1}\left(\sqrt{5}-6\sqrt{5}-\dfrac{1}{4}\right)=\dfrac{27\sqrt{5}}{4}\)

=>căn 5x+1=\(\dfrac{27\sqrt{5}}{28\sqrt{5}-1}\)

=>5x+1=0,96

=>5x=-0,04

=>x=-0,04/5=-0,008

4 tháng 1 2022

\(\dfrac{45^{10}\cdot5^{20}}{75^{15}}=\dfrac{\left(3^2\cdot5\right)^{10}\cdot5^{20}}{\left(3\cdot5^2\right)^{15}}=\dfrac{3^{20}\cdot5^{10}\cdot5^{20}}{3^{15}\cdot5^{30}}=3^5=243\\ \dfrac{6^6+6^3+3^3+3^6}{-73}=\dfrac{46656+216+27+729}{-73}=-\dfrac{47628}{73}\\ \dfrac{27^7+3^{15}}{9^9-27}=\dfrac{\left(3^3\right)^7+3^{15}}{\left(3^2\right)^9-3^3}=\dfrac{3^{21}+3^{15}}{3^{18}-3^3}=\dfrac{3^{15}\left(3^6+1\right)}{3^3\left(3^{15}-1\right)}=\dfrac{3^5\cdot730}{3^{15}-1}\\ \dfrac{8^{20}+4^{20}}{4^{25}+64^5}=\dfrac{\left(2^3\right)^{20}+\left(2^2\right)^{20}}{\left(2^2\right)^{25}+\left(2^6\right)^5}=\dfrac{2^{60}+2^{40}}{2^{50}+2^{30}}=\dfrac{2^{40}\left(2^{20}+1\right)}{2^{30}\left(2^{20}+1\right)}=2^{10}=1024\)

26 tháng 7 2023

\(a.\dfrac{-4}{7}-\dfrac{5}{13}\times\dfrac{-39}{25}+\dfrac{-1}{42}:\dfrac{-5}{6}\) 

\(=\dfrac{-4}{7}+\dfrac{3}{5}+\dfrac{1}{35}\) \(=\dfrac{1}{35}+\dfrac{1}{35}=\dfrac{2}{35}\) 

\(b.\dfrac{2}{9}\times\left[\dfrac{4}{5}:\left(\dfrac{1}{5}-\dfrac{2}{15}\right)+1\dfrac{2}{3}\right]-\dfrac{-5}{27}\) 

\(=\dfrac{2}{9}\times\left[\dfrac{4}{5}:\dfrac{1}{15}+\dfrac{5}{3}\right]-\dfrac{-5}{27}\) 

\(=\dfrac{2}{9}\times\left(12+\dfrac{5}{3}\right)-\dfrac{-5}{27}\) 

\(=\dfrac{2}{9}\times\dfrac{41}{3}-\dfrac{-5}{27}=\dfrac{82}{27}-\dfrac{-5}{27}=\dfrac{29}{9}\)

18 tháng 9 2021

\(\dfrac{1}{2}\sqrt{48a}-2\sqrt{45}-\dfrac{a}{3}\sqrt{\dfrac{27}{a}}+5\sqrt{1\dfrac{4}{5}}\)

\(=2\sqrt{3a}-6\sqrt{5}-\sqrt{3a}+3\sqrt{5}\)

=\(=\sqrt{3a}-3\sqrt{5}\)

18 tháng 9 2021

\(=\sqrt{\dfrac{1}{4}.48a}-6\sqrt{5}-\sqrt{\dfrac{a^2}{9}.\dfrac{27}{a}}+\sqrt{25.\dfrac{9}{5}}\)
\(=\sqrt{12a}-6\sqrt{5}-\sqrt{3a}+3\sqrt{5}\)
\(=2\sqrt{3a}-6\sqrt{5}-\sqrt{3a}+3\sqrt{5}\)
\(=\sqrt{3a}-3\sqrt{5}\)
 

22 tháng 3 2017

13)\(\dfrac{45}{8}\left(\dfrac{4}{15}-\dfrac{7}{8}\right)+\dfrac{45}{8}\left(\dfrac{11}{15}+\dfrac{9}{8}\right)\)

=\(\dfrac{45}{8}\left(\dfrac{4}{15}-\dfrac{7}{8}+\dfrac{11}{15}+\dfrac{9}{8}\right)\)

=\(\dfrac{45}{8}\left[\left(\dfrac{4}{15}+\dfrac{11}{15}\right)-\left(\dfrac{7}{8}-\dfrac{9}{8}\right)\right]\)

=\(\dfrac{45}{8}.\dfrac{5}{4}\)=\(\dfrac{225}{32}\)

14)\(\dfrac{15}{7}\left(\dfrac{49}{35}-\dfrac{27}{8}\right)-\left(\dfrac{2}{5}-\dfrac{27}{4}\right):\dfrac{7}{15}\)

=\(\dfrac{15}{7}\left(\dfrac{49}{35}-\dfrac{27}{8}\right)-\left(\dfrac{2}{5}-\dfrac{27}{4}\right).\dfrac{15}{7}\)

=\(\dfrac{15}{7}\left[\left(\dfrac{49}{35}-\dfrac{27}{8}\right)-\left(\dfrac{2}{5}-\dfrac{27}{4}\right)\right]\)

=\(\dfrac{15}{7}\left(\dfrac{49}{35}-\dfrac{27}{8}-\dfrac{2}{5}+\dfrac{27}{4}\right)\)

=\(\dfrac{15}{7}.\dfrac{35}{8}\)=\(\dfrac{75}{8}\)

6 tháng 10 2023

-3^7.2^8/2^.3^7

=-3.2

=-6

5^3.3^5/5^3(0,5+2,5)

=5^3.3^5/5^3.3\

3^4

=81

5.7^4+7^3.25/7^5.125-7^3.50

=5.7^3(7+5

6 tháng 10 2023

5.7^4+7^3.25/7^5.125-7^3.50

=5.7^4+7^3.5^2/7^5.5^3-7^3.11.5

=5.7^3(1.7+1.5)/7^3.5(7^2.25-11)

12/1250