2x + 5 = 17
-14 + 3x = 13
4x - 13 = -77
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CT
2
KV
18 tháng 9 2023
2x - 3 = 17
2x = 17 + 3
2x = 20
x = 20 : 2
x = 10
---------------
4² - 3x = 27.3 - 77
16 - 3x = 81 - 77
16 - 3x = 4
3x = 16 - 4
3x = 12
x = 12 : 3
x = 4
----------------
48 + 2x = 3.2³
48 + 2x = 3.8
48 + 2x = 24
2x = 24 - 48
2x = -24
x = -24 : 2
x = -12
----------------
(13x - 12²) : 5 = 5
13x - 144 = 5.5
13x - 144 = 25
13x = 25 + 144
13x = 169
x = 169 : 13
x = 13
VN
Võ Ngọc Phương
CTVHS
VIP
18 tháng 9 2023
\(2x-3=17\)
\(2x=17+3\)
\(2x=20\)
\(x=20:2\)
\(x=10\)
____
\(4^2-3x=27.3-77\)
\(16-3x=81-77\)
\(16-3x=4\)
\(3x=16-4\)
\(3x=12\)
\(x=12:3\)
\(x=4\)
_____
\(48+2x=3.2^3\)
\(48+2x=3.8=24\)
\(2x=24-48\)
\(2x=\left(-24\right)\)
\(x=\left(-24\right):2\)
\(x=\left(-12\right)\)
____
\(\left(13x-12^2\right):5=5\)
\(\left(13x-144\right):5=5\)
\(13x-144=5.5\)
\(13x-144=25\)
\(13x=25+144\)
\(13x=169\)
\(x=169:13\)
\(x=13\)
ND
6 tháng 3 2018
1. 3y = 0
=> y = 0
2. 1+x = 0
<+ x = -1
3.
\(1-2t=0\)
\(\Leftrightarrow2t=1\)
\(\Leftrightarrow\dfrac{1}{2}\)
4. 2x +x + 3 =0
\(\Leftrightarrow3x+3=0\)
\(\Leftrightarrow x=-3\)
5.
\(25x-20=0\)
\(\Leftrightarrow25x=20\)
\(\Leftrightarrow x=\dfrac{4}{5}\)
ND
6 tháng 3 2018
7.
2x-3 = x+5
<=> 2x - x = 5+3
<=> x = 8
8.
x-8=2x+3
<=> x - 2x = 3+8
<=> -x = 11
<=> x = -11
9. 17-2x = 3x-5
<=> -2x-3x = -5-17
<=> -5x = -22
<=> x = \(\dfrac{22}{5}\)
10.
2x+x+22=0
<=> 3x+22=0
<=> 3x = -22
<=> x = \(\dfrac{-22}{3}\)
Mấy bài kia tự giải tương tự nhá!!!
BT
2 tháng 6 2017
a) \(\dfrac{2}{3}x-\dfrac{1}{2}=\dfrac{1}{10}\)
\(\dfrac{2}{3}x=\dfrac{1}{10}+\dfrac{1}{2}=\dfrac{3}{5}\)
\(x=\dfrac{3}{5}:\dfrac{2}{3}=\dfrac{9}{10}\)
b) \(\dfrac{39}{7}:x=13\)
\(x=\dfrac{\dfrac{39}{7}}{13}=\dfrac{3}{7}\)
c) \(\left(\dfrac{14}{5}x-50\right):\dfrac{2}{3}=51\)
\(\dfrac{14}{5}x-50=51\cdot\dfrac{2}{3}=34\)
\(\dfrac{14}{5}x=34+50=84\)
\(x=\dfrac{84}{\dfrac{14}{5}}=30\)
d) \(\left(x+\dfrac{1}{2}\right)\left(\dfrac{2}{3}-2x\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}x+\dfrac{1}{2}=0\\\dfrac{2}{3}-2x=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=-\dfrac{1}{2}\\x=\dfrac{1}{3}\end{matrix}\right.\)
e) \(\dfrac{2}{3}x-\dfrac{1}{2}x=\dfrac{5}{12}\)
\(\dfrac{1}{6}x=\dfrac{5}{12}\)
\(x=\dfrac{5}{12}:\dfrac{1}{6}=\dfrac{5}{2}\)
g) \(\left(x\cdot\dfrac{44}{7}+\dfrac{3}{7}\right)\dfrac{11}{5}-\dfrac{3}{7}=-2\)
\(\left(x\cdot\dfrac{44}{7}+\dfrac{3}{7}\right)\cdot\dfrac{11}{5}=-2+\dfrac{3}{7}=-\dfrac{11}{7}\)
\(x\cdot\dfrac{44}{7}+\dfrac{3}{7}=-\dfrac{11}{7}:\dfrac{11}{5}=-\dfrac{5}{7}\)
\(\dfrac{44}{7}x=-\dfrac{5}{7}-\dfrac{3}{7}=-\dfrac{8}{7}\)
\(x=-\dfrac{8}{7}:\dfrac{44}{7}=-\dfrac{2}{11}\)
h) \(\dfrac{13}{4}x+\left(-\dfrac{7}{6}\right)x-\dfrac{5}{3}=\dfrac{5}{12}\)
\(\dfrac{25}{12}x-\dfrac{5}{3}=\dfrac{5}{12}\)
\(\dfrac{25}{12}x=\dfrac{5}{12}+\dfrac{5}{3}=\dfrac{25}{12}\)
\(x=1\)
Mỏi tay woa bn làm nốt nha!!
17 tháng 2 2020
a) Ta có: \(3x-5+7x=17-2x+8\)
\(\Leftrightarrow10x-5=25-2x\)
\(\Leftrightarrow10x-5-25+2x=0\)
\(\Leftrightarrow12x-30=0\)
\(\Leftrightarrow12x=30\)
\(\Leftrightarrow x=\frac{30}{12}=\frac{5}{2}\)
Vậy: \(x=\frac{5}{2}\)
b) Ta có: \(13-5x+14=3x-17-9x\)
\(\Leftrightarrow27-5x=-17-6x\)
\(\Leftrightarrow27-5x+17+6x=0\)
\(\Leftrightarrow44+x=0\)
\(\Leftrightarrow x=-44\)
Vậy: x=-44
c) Ta có: \(x-12+4x=25+2x-49\)
\(\Leftrightarrow x-12+4x-25-2x+49=0\)
\(\Leftrightarrow3x+12=0\)
\(\Leftrightarrow x=-4\)
Vậy: x=-4
d) Ta có: \(7x+10+5=3\left(2x-3\right)-9x\)
\(\Leftrightarrow7x+15=6x-9-9x\)
\(\Leftrightarrow7x+15-6x+9+9x=0\)
\(\Leftrightarrow10x+24=0\)
\(\Leftrightarrow10x=-24\)
\(\Leftrightarrow x=-\frac{24}{10}=\frac{-12}{5}\)
Vậy: \(x=-\frac{12}{5}\)
22 tháng 7 2019
a) \(8-\left|3x-5\right|=-14\)
\(\Rightarrow\left|3x-5\right|=22\)
\(\Rightarrow TH1:3x-5=22\Rightarrow x=9\)
\(TH2:3x-5=-22\Rightarrow x=\frac{-17}{3}\)
Vậy......
mấy câu kia tương tự
PT
1
CM
4 tháng 9 2018
x 3 - x - 1 3 4 x + 3 x - 5 = 7 x - 1 4 x + 3 - x x - 5 Đ K X Đ : x ≠ - 3 4 v à x ≠ 5 ⇔ x 3 - x - 1 3 4 x + 3 x - 5 = 7 x - 1 x - 5 4 x + 3 x - 5 - x 4 x + 3 4 x + 3 x - 5
⇔ x 3 - x - 1 3 = (7x – 1)(x – 5) – x(4x + 3)
⇔ x 3 – x 3 + 3 x 2 – 3x + 1 = 7 x 2 – 35x – x + 5 – 4 x 2 – 3x
⇔ 3 x 2 – 7 x 2 + 4 x 2 – 3x + 35x + x + 3x = 5 – 1
⇔ 36x = 4 ⇔ x = 1/9 (thoả mãn)
Vậy phương trình có nghiệm x = 1/9
f) (x – 5)2 = 9
TG
9 tháng 2 2021
a) 3x – 15 = 25 – 5x
=> 3x + 5x = 25 + 15
=> 8x = 40
=> x = 5
b) 3x - 17 = 2x – 7
=> 3x - 2x = -7 + 17
=> x = 10
c) 2x – 17 = – (3x – 18)
=> 2x - 17 = -3x + 18
=> 2x + 3x = 18 + 17
=> 5x = 35
=> x = 7
d) 3x – 14 = 2(x – 9) + 1
=> 3x - 14 = 2x - 18 + 1
=> 3x - 2x = -18 + 1 + 14
=> x = -3
f) (x – 5)2 = 9
\(\Rightarrow\left[{}\begin{matrix}x-5=3\\x-5=-3\end{matrix}\right.\)
\(\Rightarrow\left[{}\begin{matrix}x=8\\x=2\end{matrix}\right.\)
9 tháng 2 2021
a) Ta có: \(3x-15=25-5x\)
\(\Leftrightarrow3x-15-25+5x=0\)
\(\Leftrightarrow8x-40=0\)
\(\Leftrightarrow8x=40\)
hay x=5
Vậy: x=5
b) Ta có: \(3x-17=2x-7\)
\(\Leftrightarrow3x-17-2x+7=0\)
\(\Leftrightarrow x-10=0\)
hay x=10
Vậy: x=10
c) Ta có: \(2x-17=-\left(3x-18\right)\)
\(\Leftrightarrow2x-17=-3x+18\)
\(\Leftrightarrow2x-17+3x-18=0\)
\(\Leftrightarrow5x-35=0\)
\(\Leftrightarrow5x=35\)
hay x=7
Vậy: x=7
d) Ta có: \(3x-14=2\left(x-9\right)+1\)
\(\Leftrightarrow3x-14=2x-18+1\)
\(\Leftrightarrow3x-14-2x+18-1=0\)
\(\Leftrightarrow x+3=0\)
\(\Leftrightarrow x=-3\)
Vậy: x=-3
f) Ta có: \(\left(x-5\right)^2=9\)
\(\Leftrightarrow\left[{}\begin{matrix}x-5=3\\x-5=-3\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=8\\x=2\end{matrix}\right.\)
Vậy: \(x\in\left\{2;8\right\}\)
10 tháng 4 2022
Câu 1:
a: =>-2x-x+17=34+x-25
=>-3x+17=x+9
=>-4x=-8
hay x=2
b: =>17x+16x+27=2x+43
=>33x+27=2x+43
=>31x=16
hay x=16/31
c: =>-2x-3x+51=34+2x-50
=>-5x+51=2x-16
=>-7x=-67
hay x=67/7
e: 3x-32>-5x+1
=>8x>33
hay x>33/8
a ) 2x + 5 = 17
2x = 17 - 5
2x = 12
x = 12 : 2
x = 6
b ) -14 + 3x = 13
3x = 13 - ( -14 )
3x = -27
x = -27 : 3
x = -9
c ) 4x - 13 = -77
4x = ( -77 ) + 13
4x = 64
x = 64 : 4
x = 16
\(a,2x+5=17\)
\(2x=17-5\)
\(2x=12\)
\(x=12:2\)
\(x=6\)
\(b,-14+3x=13\)
\(3x=13+14\)
\(3x=27\)
\(x=27:3\)
\(x=9\)
\(c,4x-13=-77\)
\(4x=-77+13\)
\(4x=-64\)
\(x=-64:4\)
\(x=-16\)