-17/21.(5/4-2/5)<x+4/7<1-1/2+1/3-1/4......tìm giá trị của x
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HN
1
4 tháng 7 2021
\(-\dfrac{3}{17}+\left(\dfrac{2}{3}+\dfrac{3}{17}\right)=\dfrac{-3}{17}+\dfrac{3}{17}+\dfrac{2}{3}=\dfrac{2}{3}\)
\(\dfrac{-5}{21}+\dfrac{-16}{21}+1=-1+1=0\)
\(\dfrac{-4}{11}\cdot\dfrac{5}{15}\cdot\dfrac{11}{-4}=\dfrac{5}{15}=\dfrac{1}{3}\)
11 tháng 3 2022
a: =-5/11-6/11+1=-11/11+1=0
b: =-13/17-13/21-4/17=-1-13/21=-34/21
b: \(=-\dfrac{5}{12}\cdot\dfrac{9}{20}\cdot\dfrac{7}{17}=\dfrac{-21}{272}\)
d: \(=\dfrac{13}{17}\left(-\dfrac{4}{5}-\dfrac{3}{4}\right)=\dfrac{13}{17}\cdot\dfrac{-31}{20}=\dfrac{-403}{340}\)
C
29 tháng 5 2022
a) \(\dfrac{-3}{5}+\dfrac{7}{21}+\dfrac{-4}{5}+\dfrac{7}{5}\)
\(=\left(-\dfrac{3}{5}+\dfrac{-4}{5}+\dfrac{7}{5}\right)+\dfrac{7}{21}\)
\(=0+\dfrac{7}{21}\)
\(=\dfrac{7}{21}\)
b) `-3/17 + ( 2/3 + 3/17)`
` = -3/17 + 2/3 + 3/17`
` = 2/3 + ( -3/17 +3/17)`
` = 2/3 + 0`
` = 2/3`
c)
` -5/21 + ( -16/21 +1)`
\(=\dfrac{-5}{21}+\dfrac{-16}{21}+1\)
\(=\left(\dfrac{-5}{21}+\dfrac{-16}{21}\right)+1\)
\(=-1+1=0\)
TV
1
TV
1
TV
3
TV
2
LM
Lê Minh Vũ
VIP
2 tháng 8 2023
\(\dfrac{1}{21}+\dfrac{2}{21}+\dfrac{3}{21}+\dfrac{4}{21}+\dfrac{5}{21}+...+\dfrac{17}{21}+\dfrac{18}{21}+\dfrac{19}{21}+\dfrac{20}{21}\)
\(=\dfrac{1+2+3+4+5+...+17+18+19+20}{21}\)
\(=\dfrac{1+2+3+4+5+6+7+8+9+10+11+12+13+14+15+16+17+18+19+20}{21}\)
\(=\dfrac{210}{21}\)
\(=10\)
VN
Võ Ngọc Phương
CTVHS
VIP
27 tháng 3 2023
\(5:\dfrac{2}{3}\)\(=5\times\dfrac{3}{2}=\dfrac{5\times3}{2}=\dfrac{15}{2}\)
______________________________
\(\dfrac{4}{7}+\dfrac{2}{5}=\dfrac{20}{35}+\dfrac{14}{35}=\dfrac{34}{35}\)
______________________________
\(1-\dfrac{17}{21}=\dfrac{21}{21}-\dfrac{17}{21}=\dfrac{4}{21}\)
Chúc bạn học tốt:>
8 tháng 6 2021
`(-3)/5+7/21+(-4)/5+7/5`
`=(-3)/5+(-4)/5+7/5+7/21`
`=0+7/21=7/21`
`(-3)/17+(2/3+3/17)`
`=(-3)/17+3/17+2/3`
`=0+2/3=2/3`
MN
8 tháng 6 2021
\(-\dfrac{3}{5}+\dfrac{7}{21}+-\dfrac{4}{5}+\dfrac{7}{5}\)
\(=\left(\dfrac{-3-4+7}{5}\right)+\dfrac{7}{21}=0+\dfrac{7}{21}=\dfrac{7}{21}\)
\(-\dfrac{3}{17}+\left(\dfrac{2}{3}+\dfrac{3}{17}\right)=\left(-\dfrac{3}{17}+\dfrac{3}{17}\right)+\dfrac{2}{3}=0+\dfrac{2}{3}=\dfrac{2}{3}\)