1=5
2=10
3=15
4=20
5=?
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a) 5 6 + 1 6 ≤ x ≤ 13 4 + 14 8 ⇔ 1 ≤ x ≤ 5 ⇔ x ∈ 1 ; 2 ; 3 ; 4 ; 5
b) − 5 6 + 8 3 + 29 − 6 ≤ x ≤ − 1 2 + 2 + 5 2 ⇔ − 3 ≤ x ≤ 4 ⇔ x ∈ − 3 ; − 2 ; − 1 ; 0 ; 1 ; 2 ; 3 ; 4
c) 79 15 + 7 5 + − 8 3 ≤ x ≤ 10 3 + 15 4 + 23 12 ⇔ 4 ≤ x ≤ 9 ⇔ x ∈ 4 ; 5 ; 6 ; 7 ; 8 ; 9
![](https://rs.olm.vn/images/avt/0.png?1311)
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[ 2006 x ( 154 - 52 )] - 4012
= [ 2006 x 102 ] - 4012
= 204612 - 4012
= 200600
![](https://rs.olm.vn/images/avt/0.png?1311)
a) \(103^2=\left(100+3\right)^2=10000+600+9=10609\)
b) \(52\cdot48=\left(50-2\right)\left(50+2\right)=2500-4=2496\)
c) \(75^2-50\cdot75+25^2=\left(75-25\right)^2=50^2=2500\)
\(103^2=\left(100+3\right)^2=100^2+2.3.100+3^2=10000+600+9=10609\)
\(52.48=\left(50+2\right)\left(50-2\right)=50^2-2^2=2500-4=2496\)
\(75^2-50.75+25^2=75^2-25.75-25.75+25^2=75\left(75-25\right)-25\left(75-25\right)=\left(75-25\right)=50^2=2500\)
![](https://rs.olm.vn/images/avt/0.png?1311)
a) 1 ≤ x ≤ 6 ⇒ x ∈ - 3 ; - 2 ; - 1 ; 0 ; 1
b) - 7 ≤ x ≤ - 3 ⇒ x ∈ - 3 ; - 2 ; - 1 ; 0 ; 1
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a ) x : 4 5 + 5 2 = − 3 3 4 ⇒ x : 4 5 = − 3 3 4 − 5 2 ⇒ x : 4 5 = − 11 2 ⇒ x = − 22 5 .
b ) x − 3 4 = 1 5 4 ⇒ x − 3 4 = 9 4 ⇒ x = 3 x − 3 4 = − 9 4 ⇒ x = − 3 2 .
![](https://rs.olm.vn/images/avt/0.png?1311)
a: 43/52>26/52=1/2=60/120
b: 17/68=1/4<1/3=35/105<35/103
c: \(\dfrac{2018\cdot2019-1}{2018\cdot2019}=1-\dfrac{1}{2018\cdot2019}\)
\(\dfrac{2019\cdot2020-1}{2019\cdot2020}=1-\dfrac{1}{2019\cdot2020}\)
2018*2019<2019*2020
=>-1/2018*2019<-1/2019*2020
=>\(\dfrac{2018\cdot2019-1}{2018\cdot2019}< \dfrac{2019\cdot2020-1}{2019\cdot2020}\)
TL
1=52=103=154=205=256
nha
HT
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