(99 + x) . (x^2 - 16) = 0
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(99+x).(x^2-16)=0
<=> (x-4).(x+4).(99+x)=0
<=> x-4=0 => x=4
x+4=0 => x=(-4)
99+x=0 => x=(-99)
vậy x thuộc (4;-4;-99)
( 99 + x ).( x2 -16) = 0
TH1: 99 + x = 0
x = 0 - 99
x = -99
TH2: x2 - 16 = 0
x2 = 0 + 16
x2 = 16
x2 = 42
=> x = 4
Vậy....
![](https://rs.olm.vn/images/avt/0.png?1311)
\(x^2-x+1=x^2-2.x.\frac{1}{2}+\left(\frac{1}{2}\right)^2+\frac{3}{4}\)
\(=\left(x+\frac{1}{2}\right)+\frac{3}{4}\ge\frac{3}{4}>0\)( đpcm )
\(2004^2-16\)
\(=\left(2004-4\right)\left(2004+4\right)\)
\(=2000.2008\)
\(=4016000\)
\(99^3+1+3\left(99^2+99\right)=99^3+3.1.99^2+3.1^2.99+1^3=\left(99+1\right)^3=100^3=1000000.\)
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a, \(x\) + 99: 3 = 55
\(x\) + 33 = 55
\(x\) = 55 - 33
\(x\) = 22
b, (\(x\) - 25):15 = 20
\(x\) - 25 = 20 x 15
\(x\) - 25 = 300
\(x\) = 300 + 25
\(x\) = 325
c, (3\(x\) - 15).7 = 42
3\(x\) - 15 = 42:7
3\(x\) - 15 = 6
3\(x\) = 6 + 15
3\(x\) = 21
\(x\) = 21: 3
\(x\) = 7
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\(46\cdot99\)
\(=46\cdot\left(100-1\right)\)
\(=46\cdot100-46\)
\(=4600-46\)
\(=4554\)
___________
\(34\cdot11\)
\(=34\cdot\left(10+1\right)\)
\(=34\cdot10+34\)
\(=340+34\)
\(=374\)
___________
\(25\cdot12\)
\(=5\cdot5\cdot12\)
\(=5\cdot60\)
\(=300\)
__________
\(15\cdot4\)
\(=15\cdot2\cdot2\)
\(=30\cdot2\)
\(=60\)
____________
\(45\cdot6\)
\(=45\cdot2\cdot3\)
\(=90\cdot3\)
\(=2700\)
________
\(13\cdot99\)
\(=13\cdot\left(100-1\right)\)
\(=13\cdot100-13\)
\(=1300-13\)
\(=1287\)
______________
\(16\cdot19\)
\(=16\cdot\left(20-1\right)\)
\(=16\cdot20-16\)
\(=320-16\)
\(=304\)
_____________
\(35\cdot98\)
\(=35\cdot\left(100-2\right)\)
\(=35\cdot100-35\cdot2\)
\(=3500-70\)
\(=3430\)
____________
\(125\cdot16\)
\(=125\cdot8\cdot2\)
\(=1000\cdot2\)
\(=2000\)
___________
\(47\cdot101\)
\(=47\cdot\left(100+1\right)\)
\(=47\cdot100+47\)
\(=4700+47\)
\(=4747\)
46 x 99 =4554 , 34 x 11 = 374 , 25 x 12 =- 300 , 15 x 4 = 60 , 45 x 6 = 270 , 13 x 99 = 1287 , 16 x 19 = 304
35 x 98 = 3430 , 125 x 16 = 2000 , 47 x 101 = 4747
![](https://rs.olm.vn/images/avt/0.png?1311)
Tính nhanh mỗi biểu thức sau:
a, 0 + 1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 + 9 + 10 + 11 + 12 + 13 + 14 + 15 + 16 + 17 + 18 + 19 + 20
= (0 + 20) + (1 + 19) + (2 + 18) + (3 + 17) + (4 + 16) + (5 + 15) + (6 + 14) + (7 + 13) + (8 + 12) + (9 + 11) + 10
= 20 + 20 + 20 + 20 + 20 + 20 + 20 + 20 + 20 + 20 + 10
= 20 x 10 + 10
= 200 + 10
= 210
b, 1 x 2 x 3 x 4 x 5 x 6 x 7 x 8 x 9 x (4 x 9 - 36)
= 1 x 2 x 3 x 4 x 5 x 6 x 7 x 8 x 9 x (36 - 36)
= 1 x 2 x 3 x 4 x 5 x 6 x 7 x 8 x 9 x 0
= A x 0
= 0
c, (81 - 7 x 9 - 18) : (1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 + 9)
= (81 - 63 - 18) : (1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 + 9)
= (18 - 18) : (1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 + 9)
= 0 :(1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 + 9)
= 0 : A
= 0
d, (6 x 5 + 7 - 37) x (1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 + 9 + 10)
= (30 + 7 - 37) x (1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 + 9 + 10)
= (37 - 37) x (1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 + 9 + 10)
= 0 x (1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 + 9 + 10)
= 0 x A
= 0
e, (11 x 9 - 100 + 1) : (1 x 2 x 3 x 4 x ... x 10)
= (99 - 100 + 1) : (1 x 2 x 3 x 4 x ... x 10)
= (99 + 1 - 100) : (1 x 2 x 3 x 4 x ... x 10)
= (100 - 100) : (1 x 2 x 3 x 4 x ... x 10)
= 0 : (1 x 2 x 3 x 4 x ... x 10)
= 0 : A
= 0
g, (m : 1 - m x 1) : (m x 2008 + m x 2008)
= (m - m) : (m x 2008 + m x 2008)
= 0 : (m x 2008 + m x 2008)
= 0 : A
= 0
h, (2 + 4 + 6 + 8 + m x n) x (324 x 3 - 972)
= (2 + 4 + 6 + 8 + m x n) x (972 - 972)
= (2 + 4 + 6 + 8 + m x n) x 0
= A x 0
= 0
l, (1 + 2 + 3 + ... + 99) x (13 x 15 - 12 x 15 - 15)
= (1 + 2 + 3 + ... + 99) x (15 x (13 - 12 - 1))
= (1 + 2 + 3 + ... + 99) x (15 x 0)
= (1 + 2 + 3 + ... + 99) x 0
= A x 0
= 0
i, (0 x 1 x 2 x...x 99 x 100) : (2 + 4 + 6 +...+ 98)
= 0 x : (2 + 4 + 6 +...+ 98)
= 0 x A
= 0
k, (0 + 1 + 2 +...+ 97 + 99) x (45 x 3 - 45 x 2 - 45)
= (0 + 1 + 2 +...+ 97 + 99) x (45 x (3 - 2 - 4))
= (0 + 1 + 2 +...+ 97 + 99) x (45 x 0)
= (0 + 1 + 2 +...+ 97 + 99) x 0
= A x 0
= 0
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
(x+1)+ (x+3) + (x+5)+.....+(x+99) = 0
x+1 + x+3 +x+5 +....+x+99 =0
Có số số hạng x là : (99-1):2+1= 50 số
Ta có: 50x + ( 1+3+5+...+99) = 0
Đặt A= 1+3+5+...+99
Tổng A là: (99+1).50:2= 2500
=> 50x + 2500 = 0
50x = 0-2500
50x= -2500
x= -2500 :50
x= -50
Vậy...
a) xy - 3x =-19
x(y-3) = -19
=> y-3 \(\in\)Ư(-19) ={ 1; 19; -19 ; -1}
=> y \(\in\){ 4; 22; -16; 2}
Sau bn lập bảng tìm x nha
b) 3x + 4y - xy = 16
3x + y(4-x) =16
12 - [ 3x+ y(4-x)] =12-16
12 - 3x - y(4-x)= -4
3(4-x)- y(4-x) = -4
(3-y) ( 4-x) =-4
Sau bn lập bảng tìm xy nha
Nguồn phần b là của bn Tài nha :>
Bài 1 :
\(\left(x+1\right)+\left(x+3\right)+\left(x+5\right)+...+\left(x+99\right)=0\)
Có tất cả các số số hạng là : \(\left(99-1\right)\div2+1=50\) ( số )
\(x+1+x+3+x+5+...+x+99=0\)
\(x+x+...+x+1+3+...+99=0\)
\(\left(x\times50\right)+\left[\left(99+1\right)\times50\div2\right]=0\)
\(\left(x\times50\right)+\left(100\times50\div2\right)=0\)
\(\left(x\times50\right)+\left(5000\div2\right)=0\)
\(\left(x\times50\right)+2500=0\)
\(x\times50=0-2500\)
\(x\times50=-2500\)
\(x=-2500\div50\)
\(x=-50\)
Bài 2 :
a ) \(xy-3x=-19\)
\(\Leftrightarrow\)\(x,y\inℤ\)và \(y-3\) \(\inƯ\)\(\left(-19\right)\)\(\in\)\(\left\{1;-1;19;-19\right\}\)
Ta có bảng sau
x | - 19 | 19 | - 1 | 1 |
y - 3 | 1 | - 1 | 19 | - 19 |
y | 4 | 2 | 22 | - 16 |
Vậy \(\left(x;y\right)\) \(\in\) \(\left\{\left(-19;4\right);\left(19;2\right);\left(-1;22\right);\left(1;-16\right)\right\}\)
b ) \(3x+4y-xy=16\)
\(\Leftrightarrow3x+4y-xy-12=16-12\)
\(\Leftrightarrow\left(3x-xy\right)+\left(4y-12\right)=4\)
\(\Leftrightarrow x\left(3-y\right)+4\left(-y\right)+3=4\)
\(\Leftrightarrow\left(3-y\right)\left(x+4\right)=4\)
\(\Leftrightarrow\)\(x;y\)\(\inℤ\)\(\Rightarrow\)\(3-y\) và \(x+4\)\(\in\)\(Ư\)\(\left(4\right)\)=
Ta có bảng sau :
x + 4 | 1 | - 1 | 2 | - 2 | 4 | - 4 |
x | - 3 | - 5 | - 2 | - 6 | 0 | - 8 |
y - 3 | 4 | - 4 | 2 | - 2 | 1 | - 1 |
y | 7 | - 1 | 5 | 1 | 4 | 2 |
Vậy \(\left(x;y\right)\)\(\in\)\(\left\{\left(-3;7\right);\left(-5;-1\right);\left(-2;5\right);\left(-6;1\right);\left(0;4\right);\left(-8;2\right)\right\}\)