25.17+76.17-17
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\(a,\left(-113\right)+55+113-155=\left(-113+133\right)+\left(55-155\right)=0+\left(-100\right)=-100\\ b,-25.17+17.\left(-75\right)=17\left[\left(-25\right)+\left(-75\right)\right]=17.\left(-100\right)=-1700\)
\(c,6^8:6^6-3\left[\left(-53\right)-\left(-21-53\right)\right]+2022^0\\ =6^2-3\left(-53+21+53\right)+1\\ =36-3.21+1\\ =36-63+1\\ =-26\)
a(-113) + 55 + 113 - 155
=>(-113)+ 113+(55 - 155)
=>-100
b -25.17+17.(-75)
=>17(-25-75)
=>17. (-100)
=>-1700
c 68 : 66-3 [( -53) - ( -21 -53 )] + 20220
=>62- 3[ -53 +21 +53 )]+1
=>36−3.21+1
=>36−63+1
=>−26
![](https://rs.olm.vn/images/avt/0.png?1311)
a) \(65.16=1040\)
\(\rightarrow\left(-65\right).16=65.\left(-16\right)=-1040\)
\(\left(-65\right).\left(-16\right)=1040\)
\(\Rightarrow65.16=\left(-65\right).\left(-16\right)=1040\)
b) \(25.\left(-27\right)=-675\)
\(\rightarrow\left(-25\right).\left(-17\right)=25.17=675\)
\(\left(-25\right).17=-675\)
\(\Rightarrow25.\left(-17\right)=\left(-25\right).17=-675\)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(117.\left(-25\right)+25.17\)
\(=\left(-117\right).25+25.17\)
\(=25.\left[\left(-117\right)+17\right]\)
\(=25.\left(-100\right)\)
\(=-2500\)
![](https://rs.olm.vn/images/avt/0.png?1311)
Em xem lại đầu bài nhé chỗ:
\(36\times17\times29\times17\)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\frac{25\cdot9-25\cdot17}{-8\cdot80-8\cdot10}=\frac{25\cdot(9-17)}{8\cdot(-80)-8\cdot10}=\frac{25\cdot(-8)}{8\cdot(-80-10)}=\frac{25\cdot(-8)}{8\cdot(-90)}=\frac{5}{18}\)
P/S : Hoq chắc :>
\(\frac{25.9-25.17}{-8.80-8.10}\)= \(\frac{25\left(9-17\right)}{-8\left(80+10\right)}\)= \(\frac{25.\left(-8\right)}{90.\left(-8\right)}\)= \(\frac{25}{90}\)= \(\frac{5}{18}\)
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a)
17.85+25.17+81.100
=17.(85+25) +81.100
=17.110+81.100
=1870+8100
=9970
Ta có : 17. 85 +25. 17 + 81.100
= 17 . (85 + 25) + 81 . 100
= 17 . 110 + 81 . 100
= 17.(10 + 100) + 81 . 100
= 170 + 17 . 100 + 81 . 100
= 170 + [100 .( 17 +81)]
= 170 + 100 . 98
= 9800 + 170 =9970 .
Mik chắc đúng đấy , tick mik nha Nguyễn Hoàng Nina
= 251 . 100 = 25100 .
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\frac{5^2\cdot3^3-25\cdot17}{25\cdot3^2-5^2\cdot8}\)
\(=\frac{25\cdot\left(27-17\right)}{25\left(9-8\right)}\)
\(=\frac{25\cdot17}{25\cdot1}\)
\(=17\)
Nhầm đoạn cuối :
\(=\frac{25\cdot10}{25\cdot1}\)
\(=10\)
Sorry ( ko gạch đá )
=425+1292-17
=1717-17
=1700