3/4-(x-2/3)=5/6
helppp cho mimh lời giải chi tiết
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TL
6
20 tháng 1
\(\dfrac{3}{4}\cdot\dfrac{2}{5}+\dfrac{3}{4}\cdot\dfrac{2}{5}\)
\(=\dfrac{3}{4}\cdot\dfrac{2}{5}\left(1+1\right)\)
\(=\dfrac{6}{20}\cdot2\)
\(=\dfrac{12}{20}=\dfrac{3}{5}\)
H
30 tháng 9 2023
`a, 3/4 - 5/4 :(x-1) =1/2`
`=> 5/4:(x-1)= 3/4 -1/2`
`=> 5/4:(x-1)= 3/4 - 2/4`
`=> 5/4:(x-1)= 1/4`
`=> x-1= 5/4 : 1/4`
`=> x-1=5`
`=>x=5+1`
`=>x=6`
__
`(1/2-x)^2 -2^2 =12`
`=> (1/2-x)^2 = 12+4`
`=> (1/2-x)^2= 16`
`=> (1/2-x)^2 =4^2`
\(\Rightarrow\left[{}\begin{matrix}\dfrac{1}{2}-x=4\\\dfrac{1}{2}-x=-4\end{matrix}\right.\\ \Rightarrow\left[{}\begin{matrix}x=-\dfrac{7}{2}\\x=\dfrac{9}{2}\end{matrix}\right.\)
__
`(1/2)^(2x-1) =1/16`
`=> (1/2)^(2x-1) = (1/2)^4`
`=> 2x-1=4`
`=> 2x=4+1`
`=>2x=5`
`=>x=5/2`
VQ
30 tháng 9 2023
\(a,\dfrac{3}{4}-\dfrac{5}{4}:\left(x-1\right)=\dfrac{1}{2}\)
\(\dfrac{5}{4}:\left(x-1\right)=\dfrac{3}{4}-\dfrac{1}{2}\)
\(\dfrac{5}{4}:\left(x-1\right)=\dfrac{1}{4}\)
\(x-1=\dfrac{5}{4}:\dfrac{1}{4}\)
\(x-1=5\)
\(x=6\)
\(\left(\dfrac{1}{2}-x\right)^2-2^2=12\)
\(\left(\dfrac{1}{2}-x\right)^2-4=12\)
\(\left(\dfrac{1}{2}-x\right)^2=16\)
\(\left(\dfrac{1}{2}-x\right)^2=4^2hoặc\left(\dfrac{1}{2}-x\right)^2=\left(-4\right)^2\)
\(\dfrac{1}{2}-x=4hoặc\dfrac{1}{2}-x=-4\)
=>1/2 -x =4 1/2 -x= -4
=> x=1/2-4 x=1/2-(-4)
=>x=-7/2 x=9/2
vậy x∈{-7/2 ; 9/2}
\(\left(\dfrac{1}{2}\right)^{2x-1}=\dfrac{1}{16}\)
\(=>\left(\dfrac{1}{2}\right)^{2x-1}=\left(\dfrac{1}{2}\right)^4\)
\(=>2x-1=4\)
\(=>2x=5\)
\(=>x=\dfrac{5}{2}\)
DT
12 tháng 2 2022
a,
\(\Leftrightarrow\left(\left(2x^2-4\right)-2\left(x+1\right)^2\right)< 0\)
\(\Leftrightarrow2x^2-4-2\left(x^2+2x+1\right)< 0\)
\(\Leftrightarrow2x^2-4-2x^2-4x-2< 0\)
\(\Leftrightarrow-4x-6< 0\)
\(\Rightarrow x+\dfrac{3}{2}>0\)
\(\Rightarrow x>-\dfrac{3}{2}\)
\(x\in\left\{-\dfrac{3}{2};\infty\right\}\)
DT
12 tháng 2 2022
b/
\(\Leftrightarrow\left(x-3\right)^2-5+6x< 0\)
\(\Leftrightarrow x^2-6x+9-5+6x< 0\)
\(\Leftrightarrow x^2+4< 0\) ( điều này vô lý vì không có giá trị nào của x khiến x^2+4<0)
từ trên suy ra:
không có giá trị nào của x để pt này đúng .
DS
1
12 tháng 6 2023
`@` `\text {Ans}`
`\downarrow`
\(\left(x-\dfrac{1}{5}\right)^2+1=3,5\div7\%\)
`=> (x-1/5)^2 + 1 = 3,5 \div 0,07`
`=> (x-1/5)^2 +1=50`
`=> (x-1/5)^2 = 49`
`=> (x-1/5)^2 = (+-7)^2`
`=>`\(\left[{}\begin{matrix}x-\dfrac{1}{5}=7\\x-\dfrac{1}{5}=-7\end{matrix}\right.\)
`=>`\(\left[{}\begin{matrix}x=7+\dfrac{1}{5}\\x=-7+\dfrac{1}{5}\end{matrix}\right.\)
`=>`\(\left[{}\begin{matrix}x=\dfrac{36}{5}\\x=-\dfrac{34}{5}\end{matrix}\right.\)
Vậy, `x={36/5; -34/5}.`
BD
6 tháng 7 2023
\(\dfrac{1}{3}+\dfrac{5}{6}\cdot\left(x-\dfrac{11}{5}\right)=\dfrac{3}{4}\)
\(\dfrac{5}{6}\cdot\left(x-\dfrac{11}{5}\right)=\dfrac{3}{4}-\dfrac{1}{3}\)
\(\dfrac{5}{6}\cdot\left(x-\dfrac{11}{5}\right)=\dfrac{5}{12}\)
\(x-\dfrac{11}{5}=\dfrac{5}{12}\cdot\dfrac{6}{5}\)
\(x-\dfrac{11}{5}=\dfrac{1}{2}\)
\(x=\dfrac{1}{2}+\dfrac{11}{5}\)
\(x=\dfrac{27}{10}\)
6 tháng 7 2023
\(\dfrac{5}{6}\left(x-\dfrac{11}{5}\right)=\dfrac{3}{4}-\dfrac{1}{3}\)
\(\dfrac{5}{6}\left(x-\dfrac{11}{5}\right)=\dfrac{5}{12}\)
\(x-\dfrac{11}{5}=\dfrac{5}{12}:\dfrac{5}{6}\)
\(x-\dfrac{11}{5}=\dfrac{1}{2}\)
\(x=\dfrac{1}{2}+\dfrac{11}{5}=\dfrac{27}{10}\)
LG
19 tháng 7 2017
\(\left(x-2\right)\left(2x+1\right)-5\left(x+3\right)=2x\left(x-3\right)+4\left(1+2x\right)-2\left(1+x\right)\)
\(2x^2+x-4x-2-5x-15=2x^2-6x+4+8x-2-2x\)
\(x-4x-2-5x-15=-6x+4+8x-2-2x\)
\(\Rightarrow-8x-17=2\)
\(-8x=19\Rightarrow x=-\dfrac{19}{8}\)
Vậy \(x=-\dfrac{19}{8}\)
=>x-2/3=-1/12
hay x=7/12
\(\dfrac{3}{4}-\left(x-\dfrac{2}{3}\right)=\dfrac{5}{6}\\ \Rightarrow x-\dfrac{2}{3}=\dfrac{3}{4}-\dfrac{5}{6}\\ \Rightarrow x-\dfrac{2}{3}=-\dfrac{1}{12}\\ \Rightarrow x=\dfrac{2}{3}-\dfrac{1}{12}\\ \Rightarrow x=\dfrac{7}{12}\)