a) -(1045+756-952)+(-952-224+45)
b) -39.(127-721)-127.(-38)-(-39).(-722)
Mong mọi người giải giúp mk câu này.
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-(127+38-21)-(121-27+48)+50
=-127-38+21-121+27-48+50
=(-127+27)-(38+48)+(21-121)+50
=-100-86-100+50
=-(100+100+86)+50
=-286+50
=-236
-39+(193-127+96)-(193+196-127)
=-39+193-127+96-193-196+127
=-39+(193-193)-(127+127)+(96-196)
=-39-100
=-139
1045 + 57 - 1045 - 67
= ( 1045 - 1045 ) + ( 57 - 67 ) [_Tự lm tiếp_]
1890 - 456 - 434
= 1890 - ( 456 + 434 )
= 1890 - 890 [_Tự lm tiếp_]
-45 + 189 - 155
= 189 - ( 45 + 155 )
= 189 - 200 [_Tự lm tiếp_]
-127 + 34 - 73 + 166
= ( -127 + -73 ) + ( 34 + 166 ) [_Tự lm tiếp_]
-15 - 17 + 29 + 15 - 83
= ( -15 + 15 ) - ( 17 - 29 + 83 ) [_Tự lm tiếp_]
-45 + 140 - (-45) - 240
= [ -45 - ( -45 ) ] + ( 140 - 240 ) [_Tự lm tiếp_]
-75 + (-89) + (-75) + 89 - 122
= [ -75 + ( -75 ) ] + [ ( -89 ) + 89 ] - 122 [_Tự lm tiếp_]
P/s: Hoq chắc_:333
a) 166.(-127)+166.234+(-234).166-234.127
166.(-234+234)+127.(-166-234)
=0+127.(-400)
=-50800
b) 53.39+43.39-53.21-47.21
=39.(53+43)+(-21).(53+47)
=39.96+(-21).100
=-1644
k cho minh
\(\dfrac{x+1}{39}+\dfrac{x+2}{38}+\dfrac{x+3}{37}=0\)
\(\Leftrightarrow\dfrac{x+1}{39}+1+\dfrac{x+2}{38}+1+\dfrac{x+3}{37}+1-3=0\)
\(\Leftrightarrow\dfrac{x+40}{39}+\dfrac{x+40}{38}+\dfrac{x+40}{37}=3\)
\(\Leftrightarrow\left(x+40\right)\left(\dfrac{1}{39}+\dfrac{1}{38}+\dfrac{1}{37}\right)=3\)
\(\Leftrightarrow\left(x+40\right).\dfrac{4331}{54834}=3\)
\(\Leftrightarrow x+40=\dfrac{164502}{4331}\)
\(\Leftrightarrow x=\dfrac{-8738}{4331}\)
-Vậy \(S=\left\{\dfrac{-8738}{4331}\right\}\)
a, (1 + 3 + 5 + 7+ ... + 2003 + 2005) x (125125 x 127 - 127127 x125)
= (1 + 3 + 5 +...+2003 + 2005) x (125 x 1001 x 127 - 127x1001 x 125)
= (1 + 3 + 5 +...+ 2003 + 2005) x 0
= 0
a) \(1045:\left[215-\left(3x-24\right)\right]=5\)
\(\Rightarrow215-\left(3x-24\right)=1045:5\)
\(\Rightarrow215-\left(3x-24\right)=209\)
\(\Rightarrow3x-24=215-209\)
\(\Rightarrow3x-24=6\)
\(\Rightarrow3x=6+24\)
\(\Rightarrow3x=30\)
\(\Rightarrow x=30:3\)
\(\Rightarrow x=10\)
Vậy x = 10
b) \(\left[195-\left(15x+27\right)\right]\times39=4212\)
\(\Rightarrow195-\left(15x+27\right)=4212:39\)
\(\Rightarrow195-\left(15x+27\right)=108\)
\(\Rightarrow15x+27=195-108\)
\(\Rightarrow15x+27=87\)
\(\Rightarrow15x=87-27\)
\(\Rightarrow15x=60\)
\(\Rightarrow x=60:15\)
\(\Rightarrow x=4\)
Vậy x = 4
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