Question

[Bùi Nguyên Hùng Long]

Giai nhu nao vay

Answer 1

[Nguyễn Huy Tú]

g, \(\frac{x+2}{98}+\frac{x+4}{96}=\frac{x+6}{94}+\frac{x+8}{92}\)

\(\Leftrightarrow\frac{x+2}{98}+1+\frac{x+4}{96}+1=\frac{x+6}{94}+1+\frac{x+8}{92}+1\)

\(\Leftrightarrow\frac{x+100}{98}+\frac{x+100}{96}-\frac{x+100}{94}-\frac{x+100}{92}=0\)

\(\Leftrightarrow\left(x+100\right)\left(\frac{1}{98}+\frac{1}{96}-\frac{1}{94}-\frac{1}{92}\ne0\right)=0\Leftrightarrow x=-100\)

Answer 2

[Nguyễn Huy Tú]

e, \(\frac{1}{2}\left(x+1\right)+\frac{1}{4}\left(x+3\right)=3-\frac{1}{3}\left(x+2\right)\)

\(\Leftrightarrow\frac{x+1}{2}+\frac{x+3}{4}=3-\frac{x+2}{3}\)

\(\Leftrightarrow\frac{6x-6+3x+9}{12}=\frac{36-4x-8}{12}\)

\(\Rightarrow9x+3=28-4x\Leftrightarrow13x=25\Leftrightarrow x=\frac{25}{13}\)