Giusp mik với
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a)\(\dfrac{-2}{17}+\dfrac{8}{17}=\dfrac{6}{17}\)
b) \(\dfrac{-9}{16}+\dfrac{7}{24}=\dfrac{-13}{48}\)
c)\(\dfrac{1}{8}+\dfrac{-5}{6}+\dfrac{7}{-36}=\dfrac{-17}{24}+\dfrac{7}{-36}=\dfrac{-65}{72}\)
a) =\(\dfrac{-2+8}{17}=\dfrac{6}{17}\)
b) =\(\dfrac{-27}{48}+\dfrac{14}{48}=\dfrac{-27+14}{48}=\dfrac{-13}{48}\)
c) \(=\dfrac{9}{72}+\dfrac{-60}{72}+\dfrac{-14}{72}=\dfrac{9+\left(-60\right)+\left(-14\right)}{72}=\dfrac{-65}{72}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
Lời giải:
Ta có:
\(P=1+x+x^2+x^3+...+x^9+x^{10}\)
\(\Rightarrow xP=x+x^2+x^3+...+x^{10}+x^{11}\)
Trừ theo vế:
\(xP-P=(x+x^2+x^3+...+x^{10}+x^{11})-(1+x+x^2+...+x^{10})\)
\(\Rightarrow \)\(xP-P=x^{11}-1\) (đpcm)
P.s: Bạn lưu ý lần sau nhớ viết công thức rõ ràng.
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
Ta có:
VT: \(\left(a+b\right)^2=\left(a+b\right)\left(a+b\right)\)
\(=a^2-ab-ab+b^2=a^2-2ab+b^2=VP\)
\(\Rightarrow\left(a+b\right)^2=a^2-2ab+b^2\left(đpcm\right)\)
hok tốt!!
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f: =>(x-3)(x-1)>=0
=>x>=3 hoặc x<=1
g: =>(x-2)(x^2+3)<0
=>x-2<0
=>x<2
h: =>x+2>=0
=>x>=-2
i: =>(x-1-x+3)/(x-3)>0
=>x-3>0
=>x>3
![](https://rs.olm.vn/images/avt/0.png?1311)
\(E=\dfrac{-1}{3}-\dfrac{2}{3}+\dfrac{2}{5}-\dfrac{3}{5}+\dfrac{1}{5}=-1\)
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
1) FD n
2) BK n
3) RT k
4) LT k
5) PU
6) Home
7) CS
8) HT
9) PD
10) Clean
Xin lỗi mik chỉ nhớ được có nhiêu đó à ;-; thông cảm nha
3-C; 4-B