X ÷ 10 + X × 2 + X ÷ 5 = 24 mình cần gấp trong tối nay . Xin cảm ơn
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(x - 38) : 11 = 89
x - 38 = 89 x 11
x - 38 = 979
x = 979 + 38
x = 1017
t i c k cho mình nha
học tốt!!!!
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a, 5x(x-2) + (2-x)=0
⇔5x(x-2) - (x-2) =0
⇔(x-2)(5x-1)=0
\(\left[{}\begin{matrix}x-2=0\\5x-1=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=2\\x=\frac{1}{5}\end{matrix}\right.\)
Vậy....
c, (x3 - x2) - 4x2 + 8x -4 =0
⇔x3 - x2 -4x2 + 8x - 4=0
⇔x2(x-1) - 4x(x-1) +4(x-1) =0
⇔(x-1) (x-2)2=0
⇔\(\left[{}\begin{matrix}x-1=0\\\left(x-2\right)^2=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=1\\x=2\end{matrix}\right.\)
Vậy...
Phần b cậu có chép sai đề không?
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C1 : 5/24 x 5/12 x 24
= 5/24 x ( 5/12 x 24 )
= 5/24 x 10
= 50/24
= 25/12
C2 : 5/24 x 5/12 x 24
= ( 5/24 x 24 ) x ( 5/12 )
= 5 x ( 5/12 )
= 25/12
Chúc em học giỏi !!!
Cách 1 : 5/24 x 5/12 x 24 = (5/24 x 24) x 5/12
= 5 x 5/12 = 25/12
Cách 2 : 5/24 x 5/12 x 24 = 5/24 x (5/12 x 24)
= 5/24 x 10 = 25/12
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\(\frac{-6}{30}=\frac{x}{-20}\)
nhân chéo \(x\cdot30=\left(-6\right)\cdot\left(-20\right)\)
=>\(30x=120\)
\(x=4\)
\(\frac{-6}{30}=\frac{3}{y}\)
nhân chéo => \(-6x=90\)
\(x=-15\)
\(\frac{-6}{30}=\frac{z}{5}\)
nhân chéo => \(30z=-30\)
\(z=-1\)
x/-20 = -6/30
=> 30x = 120
<=> x = 4
3/y = -6/30
=> -6y = 90
<=> y = -15
z/5 = -6/30
=> -6z = 150
<=> z = - 25
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\(x^2-\sqrt{x^2-5}=7\)
\(\Leftrightarrow\sqrt{x^2-5}=x^2-7\)
\(\Leftrightarrow\left(\sqrt{x^2-5}\right)^2=\left(x^2-7\right)^2\)
\(\Leftrightarrow x^2-5=\left(x^2\right)^2-2.x^2.7+7^2\)
\(\Leftrightarrow x^2-5=x^4-14x^2+49\)
\(\Leftrightarrow-x^4+x^2+14x^2-5-49=0\)
\(\Leftrightarrow-x^4+15x^2-54=0\)
Đặt : \(t=x^2\left(t\ge0\right)\) , ta có :
\(-t^2+15t-54=0\)
\(\left(a=-1;b=15;c=-54\right)\)
\(\Delta=b^2-4ac\)
\(=15^2-4.\left(-1\right).\left(-54\right)\)
\(=225+4.\left(-54\right)\)
\(=225-216\)
\(=9>0\)
\(\sqrt{\Delta}=\sqrt{9}=3\)
\(t_1=\frac{-15+3}{2.\left(-1\right)}=6\) ( nhận )
\(t_2=\frac{-15-3}{2.\left(-1\right)}=9\) ( nhận )
Vs : \(t_1=6\Rightarrow x^2=6\Rightarrow x=\pm\sqrt{6}\)
Vs : \(t_2=9\Rightarrow x^2=9\Rightarrow x=\pm3\)
Vậy phương trình có 4 nghiệm : \(x_1=3;x_2=-3;x_3=6;x_4=-6\)
Cái đề có gì đó sai sai
\(\)
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\(2^4.5-\left[31-9^2\right]=16.5-\left(31-81\right)=80-\left(-50\right)=130\)
\(2^4\).5-[1.31-(13-4)^2]
=16.5-[1.31-81]
=16.5-[31-81]
=16.5-(-50)
=80-(-50)
=130
\(x\div10+x\times2+x\div5=24\)
\(\Leftrightarrow x\times\frac{1}{10}+x\times2+x\times\frac{1}{5}=24\)
\(\Leftrightarrow x=\left(\frac{1}{10}+2+\frac{1}{5}\right)=24\)
\(\Leftrightarrow x\times2,3=24\)
\(\Leftrightarrow x=\frac{240}{23}\)
x/10+x*2+x/5=24
=>2x/15=24-2x
=>x/15=12-x
=>16x/15=24
=>16x=360=>x=45/2