tìm số nguyên x
2.(x+3)-(13-x).6=64+\(^{\left(-1^{1003}\right)}\)
K
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NT
4
4 tháng 3 2020
a) \(-2\left(x+6\right)=8-6\left(x-10\right)\)
\(\Leftrightarrow-2x-12=8-6x+60\)
\(\Leftrightarrow-2x-12=-6x+68\)
\(\Leftrightarrow-2x=-6x+68+12\)
\(\Leftrightarrow-2x=-6x+80\)
\(\Leftrightarrow-2x+6x=80\)
\(\Leftrightarrow4x=80\)
\(\Leftrightarrow x=20\)
Vậy \(x=20\)
b) \(-4\left(2x+9\right)=\left(x+13\right)+\left(-8x+3\right)\)
\(\Leftrightarrow-4\left(2x+9\right)=x+13+-8x+3\)
\(\Leftrightarrow-4\left(2x+9\right)=x+13-8x+3\)
\(\Leftrightarrow-4\left(2x+9\right)=-7x+16\)
\(\Leftrightarrow-8x-36=-7x+16\)
\(\Leftrightarrow-36=-7x+16+8x\)
\(\Leftrightarrow x+16=-36\)
\(\Leftrightarrow x=-52\)
Vậy \(x=-52\)
4 tháng 3 2020
a) -2(x+6)=8-6(x-10)
<=> -2x-12=8-6x+60
<=> -2x-12-68+6x=0
<=> 4x-80=0
<=> 4x=80
<=> x=20
b) -4(2x+9)=(x+13)+(-8x+3)
<=> -8x-36=x+13-8x+3
<=> -8x-36=-7x+16
<=> -8x-36+7x-16=0
<=> -x-52=0
<=> -x=52
<=> x=-52
PK
2
15 tháng 6 2017
minh giai nhu the nay xem dung ko nha:
x se la mu 2 :
nhu vay ta se duoc :
\(\left(-8\right)^2\) = 64 { vi (- 8) . (- 8) = 64 vi am nham voi am se ra duong }
tuong tu : \(13^2\)= 169 ( vi 13 .13 = 169 )
nen ta co \(\frac{64}{169}=\frac{64}{169}\)
nen ta => so nguyen x con co the noi la mu x = 2
vay \(\frac{64}{169}=\left(-\frac{8}{13}\right)^2\)
30 tháng 6 2016
a)\(\left(\frac{1}{2}-\frac{1}{3}\right).6^x+6^{x+2}=6^{15}+6^{18}\)
\(\frac{1}{6}.6^x+6^{x+2}=6^{15}\left(1+6^3\right)\)
\(\frac{1}{6}.6^x\left(1+6^3\right)=6^{15}.217\)
\(6^{x-1}.217=6^{15}.217\)
\(6^{x-1}=6^{15}\)
\(x-1=15\)
\(x=16\)
b) \(\left(\frac{1}{2}-\frac{1}{6}\right).3^{x+4}-4.3^x=3^{16}-4.3^{13}\)
\(\frac{1}{3}.3^x.4\left(3^4-1\right)=3^{13}.4\left(3^3-1\right)\)
\(3^x.4.\left(3^3-1\right)=3^{13}.4.\left(3^3-1\right)\)
\(3^x=3^{13}\)
\(x=13\)
30 tháng 6 2016
\(\left(\frac{1}{2}-\frac{1}{6}\right).\left(3^x.3^4\right)-4.3^x=3^{16}-4.3^{13}\)
=> \(\frac{1}{3}.3^x.3^4-4.3^x=3^{16}-4.3^{13}\)
=> \(3^x.3^4-4.3^x=\left(3^{16}-4.3^{13}\right):\frac{1}{3}\)
=> \(3^x.3^4-4.3^x=-386339074,3\)
=> \(3^x.\left(3^4-4\right)=-386339074,3\)
=> \(3^x.77=-386339074,3\)
=> \(3^x=-386339074,3:77\)
=> \(3^x=-5017390,575\)
=> x = ... chắc tự ngồi tính đc
21 tháng 7 2019
\(5^{x+4}-3.5^{x+3}=2.5^{11}\)
\(5^{x+3}\left(5-3\right)=2.5^{11}\)
\(5^{x+3}.2=2.5^{11}\)
\(5^{x+3}=5^{11}\)
\(x+3=11\)
\(x=8\)
\(4^{x+3}-3.4^{x+1}=13.4^{11}\)
\(4^{x+1}\left(4^2-3\right)=13.4^{11}\)
\(4^{x+1}.13=13.4^{11}\)
\(4^{x+1}=4^{11}\)
\(x+1=11\)
\(x=10\)
Y
1
LM
1
1 tháng 7 2016
a.\(\frac{1}{6}.6^x+6^x.36=6^{15}\left(1+6^3\right)\)
\(6^x.\frac{217}{6}=6^{15}.217\)
\(6^x=6^{16}\)
\(x=16\)
Y
11 tháng 1 2023
\(8,1-\left(x-6\right)=4\left(2-2x\right)\)
\(\Leftrightarrow1-x+6=8-8x\)
\(\Leftrightarrow-x+8x=8-1-6\)
\(\Leftrightarrow7x=1\)
\(\Leftrightarrow x=\dfrac{1}{7}\)
\(9,\left(3x-2\right)\left(x+5\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}3x-2=0\\x+5=0\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{2}{3}\\x=-5\end{matrix}\right.\)
\(10,\left(x+3\right)\left(x^2+2\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}x+3=0\\x^2+2=0\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}x=-3\\x=\varnothing\end{matrix}\right.\)
2
11 tháng 1 2023
`8)1-(x-5)=4(2-2x)`
`<=>1-x+5=8-6x`
`<=>5x=2<=>x=2/5`
`9)(3x-2)(x+5)=0`
`<=>[(x=2/3),(x=-5):}`
`10)(x+3)(x^2+2)=0`
Mà `x^2+2 > 0 AA x`
`=>x+3=0`
`<=>x=-3`
`11)(5x-1)(x^2-9)=0`
`<=>(5x-1)(x-3)(x+3)=0`
`<=>[(x=1/5),(x=3),(x=-3):}`
`12)x(x-3)+3(x-3)=0`
`<=>(x-3)(x+3)=0`
`<=>[(x=3),(x=-3):}`
`13)x(x-5)-4x+20=0`
`<=>x(x-5)-4(x-5)=0`
`<=>(x-5)(x-4)=0`
`<=>[(x=5),(x=4):}`
`14)x^2+4x-5=0`
`<=>x^2+5x-x-5=0`
`<=>(x+5)(x-1)=0`
`<=>[(x=-5),(x=1):}`