Question

[Lưu Hạ Vy]

1) (4-3x) (10x-5)=0

2) (7-2x) (4+8x) = 0

3) (9-7x) (11-3x) = 0

4) (7-14x) (x-2) = 0

5) (2x+1) (x-3) = 0

6) (8-3x) (-3x+5) = 0

7) (16-8x) (2-6x) = 0

8) (x+4) (6x-12) = 0

9) (11-33x) (x+11) = 0

10) (x-1/4) (x+5/6) = 0

11) (7/8-2x) (3x+1/3) = 0

12) 3x - 2x^2 = 0

13) 5x + 10x^2 = 0

14) 4x + 3x^2 = 0

15) -8x^2 + x =0

16) 10x^2 - 15x = 0

17) x^2 -4 =0

18) 9 - x^2 = 0

19) x^2 -1 = 0

20) (x-3) (2x-1) = (2x-1) ( 2x+3)

21) (5+4x) (-x+2) = (5+4x) (7+5x)

22) (4+x) (x-5) = (3x-8) (x-5) = 0 

23) (3x-8) (7-21x) - (9+2x) (7-21x)

24) (10+ 7x) (x+1) = (9x-2)(x-1)

25) (9x-4) (x-1/2) - (x-1/2) (6+x) = 0

26) 9x^2 - 1 = (3x-1) (x+4)

27) (x+7) (3x+1) = 49-x^2

28) (2x+1)^2 = (x-1)^2

29)x^3- 5x^2+6x = 0

30) 3x^2 + 5x + 2 = 0

Giảii giúpp mìnhh đyy mọii ngườii .

Answer 1

[๖²⁴ʱTú❄⁀ᶦᵈᵒᶫ]

\(\left(4-3x\right)\left(10x-5\right)=0\)

\(\Rightarrow\orbr{\begin{cases}4-3x=0\\10x-5=0\end{cases}\Rightarrow\orbr{\begin{cases}3x=4\\10x=5\end{cases}\Rightarrow}\orbr{\begin{cases}x=\frac{4}{3}\\x=\frac{1}{2}\end{cases}}}\)

\(\left(7-2x\right)\left(4+8x\right)=0\)

\(\Rightarrow\orbr{\begin{cases}7-2x=0\\4+8x=0\end{cases}\Rightarrow\orbr{\begin{cases}2x=7\\8x=-4\end{cases}\Rightarrow\orbr{\begin{cases}x=\frac{7}{2}\\x=-\frac{1}{2}\end{cases}}}}\)

rồi thực hiện đến hết ... 

Answer 2

[๖²⁴ʱんuﾘ ｲú❄✎﹏]

Brainchild bé ngây thơ qus e , ko thực hiện đến hết như thế đc đâu :>

\(\left(x-3\right)\left(2x-1\right)=\left(2x-1\right)\left(2x+3\right)\)

\(2x^2-7x+3=4x^2+4x-3\)

\(2x^2-7x+3-4x^2-4x+3=0\)

\(-2x^2-11x+6=0\)

\(2x^2+11x-6=0\)

\(2x^2+12x-x-6=0\)

\(2x\left(x+6\right)-\left(x+6\right)=0\)

\(\left(x+6\right)\left(2x-1\right)=0\)

\(x+6=0\Leftrightarrow x=-6\)

\(2x-1=0\Leftrightarrow2x=1\Leftrightarrow x=\frac{1}{2}\)

\(3x-2x^2=0\)

\(x\left(2x-3\right)=0\)

\(x=0\)

\(2x-3=0\Leftrightarrow2x=3\Leftrightarrow x=\frac{3}{2}\)

Tự lm tiếp nha