tim x biet 3^2x=81
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32x=81
32x=34
32x=32.2
=>x=2
k mik nha
\(3^{2x}=81\Rightarrow2^{2x}=3^4\)
\(\Rightarrow2x=4\Leftrightarrow x=4:2\)
\(x=2\)
Vậy \(x=2\)
![](https://rs.olm.vn/images/avt/0.png?1311)
5x=125
Mà: 53=125
=>x=3
32x=81
Mà: 34=81
=>32x=34
=>2x=4
=>x=4:2
=>x=2
52x-3-2.52=52.3
=>52x-3-50=75
=>52x-3=75+50
=>52x-3=125
Mà: 53=125
=> 52x-3=53
=>2x-3=3
=>2x=3+3
=>2x=6
=>x=6:2
=>x=3
5x=125
Mà: 53=125
=>x=3
32x=81
Mà: 34=81
=>32x=34
=>2x=4
=>x=4:2
=>x=2
52x-3-2.52=52.3
=>52x-3-50=75
=>52x-3=75+50
=>52x-3=125
Mà: 53=125
=> 52x-3=53
=>2x-3=3
=>2x=3+3
=>2x=6
=>x=6:2
=>x=3
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a)
\(\Rightarrow3^x\left(3^2+3+1\right)=117\)
\(\Rightarrow3^x.13=117\)
\(\Rightarrow3^x=9\)
\(\Rightarrow3^x=3^2\)
=>x=2
b)
\(3^{2x+1}=3^{-4}\)
=> 2x+1= - 4
=>\(x=-\frac{5}{2}\)
c)
\(\left(x+2\right)^4=16\)
\(\Rightarrow\left[\begin{array}{nghiempt}\left(x+2\right)^4=2^4\\\left(x+2\right)^4=\left(-2\right)^4\end{array}\right.\)
\(\Rightarrow\left[\begin{array}{nghiempt}x+2=2\\x+2=-2\end{array}\right.\)
\(\Rightarrow\left[\begin{array}{nghiempt}x=0\\-4\end{array}\right.\)
![](https://rs.olm.vn/images/avt/0.png?1311)
a: -x+5/9=-1/3
nên x=5/9+1/3=5/9+3/9=8/9
b: \(\Leftrightarrow\dfrac{1}{5}+\dfrac{1}{10}+\dfrac{11}{15}< x< \dfrac{1}{2}+\dfrac{13}{12}+\dfrac{1}{3}\)
=>31/30<x<23/12
mà x là số nguyên
nên \(x\in\varnothing\)
c: x+5/3=1/81
nên x=1/81-135/81=-134/81
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\left(x+2\right)^2=81\)
\(\left(x+2\right)^2=9^2\)
\(\Rightarrow x+2=9\)
\(\Rightarrow x=7\)
\(\left(x+2\right)^2-9^2=0\)
\(\left(x+2+9\right)\left(x+2-9\right)=0\)
\(x=-11\)
\(x=7\)
Ta có 81 = \(^{3^4}\)
=> 3^2x = 81 = \(^{3^4}\)
=> 2x = 4
=> x = 4 : 2
=> x = 2