197-(x+4) =120
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197 x 85 + 197 x 14 + 197 = 197 x (85 + 14 + 1) = 197 x 100 = 197
a) x + (-32) = -95
x = -95 + 32
x = -63
b) -197 - x = 123
x = -197 - 123
x = -320
c) 231 + (79 - x) = -46
79 - x = -46 - 231
79 - x = -277
x = 79 + 277
x = 356
d) x - (-168) = 4⁷ : 4⁵
x + 168 = 16
x = 16 - 168
x = -152
a) x + (-32) = -95 b) -197 - x = 123x = -320
x = -95 + 32 = -197 - 123x
x = -63 = -320
c) 231 + (79 - x) = -46 d) x - (-168) = 4⁷ : 4⁵
79 - x = -46 - 231 x + 168 = 16
79 - x = -277 x = 16 - 168
x = 79 + 277 x= -152
x = 356
\(\dfrac{x+1}{199}+\dfrac{x+2}{198}+\dfrac{x+3}{197}+\dfrac{x+4}{196}+\dfrac{x+220}{5}=0\)
\(\Leftrightarrow\left(\dfrac{x+1}{199}+1\right)+\left(\dfrac{x+2}{198}+1\right)+\left(\dfrac{x+3}{197}+1\right)+\left(\dfrac{x+4}{196}+1\right)+\dfrac{x+200}{5}+\dfrac{20}{5}-4=0\)
\(\Leftrightarrow\dfrac{x+200}{199}+\dfrac{x+200}{198}+\dfrac{x+200}{197}+\dfrac{x+200}{196}+\dfrac{x+200}{5}=0\)
\(\Leftrightarrow\left(x+200\right)\left(\dfrac{1}{199}+\dfrac{1}{198}+\dfrac{1}{197}+\dfrac{1}{196}+\dfrac{1}{5}\right)=0\)
\(\Leftrightarrow x=-200\)( do \(\dfrac{1}{199}+\dfrac{1}{198}+\dfrac{1}{197}+\dfrac{1}{196}+\dfrac{1}{5}>0\))
\(\dfrac{x+1}{199}+\dfrac{x+2}{198}+\dfrac{x+3}{197}+\dfrac{x+4}{196}+\dfrac{x+220}{5}=0\\ \Leftrightarrow\left(\dfrac{x+1}{199}+1\right)+\left(\dfrac{x+2}{198}+1\right)+\left(\dfrac{x+3}{197}+1\right)+\left(\dfrac{x+4}{196}+1\right)+\left(\dfrac{x+220}{5}-4\right)=0\\ \Leftrightarrow\dfrac{x+200}{199}+\dfrac{x+200}{198}+\dfrac{x+200}{197}+\dfrac{x+200}{196}+\dfrac{x+200}{5}=0\\ \Leftrightarrow\left(x+200\right)\left(\dfrac{1}{199}+\dfrac{1}{198}+\dfrac{1}{197}+\dfrac{1}{196}+\dfrac{1}{5}\right)=0\\ \Leftrightarrow x=-200\)
a: =197+3*(34-64)
=197-3*30
=197-90=107
b: =25(134-34)+100=100*26=2600
d: =>x thuộc B(84)
mà 100<x<200
nên x=168
a)=407.52.34
=21164.34
=719576
b)=197.(52+23+59)
=197.134
=26398
\(a,\left(4^{19}+3^{21}\right).\left(5^{20}-3^{15}\right).\left(2^6-8^2\right)\\ =\left(4^{19}+3^{21}\right).\left(5^{20}-3^{15}\right).\left(2^{3.2}-2^{3.2}\right)\\ =\left(4^{19}+3^{21}\right).\left(5^{20}-3^{15}\right).0=0\)
\(b,2^5.197+197.3^2+197.59\\ =197.32+197.9+197.59\\ =197.\left(32+9+59\right)\\ =197.100=19700\)
197-(x+4) =120
x+4 = 197 - 120
x+4 = 77
x = 77 - 4
x = 73.
Vậy x = 73.
Hok tốt !
197-(x+4) =120
x+4=197-120
x+4 =77
x=77-4
x=73
Vậy x=73