2^7.9^2/3^3.2^5
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![](https://rs.olm.vn/images/avt/0.png?1311)
\(\frac{2^7.9^2}{3^3.2^5}=\frac{2^7.\left(3^2\right)^2}{3^3.2^5}=\frac{2^7.3^4}{3^3.2^5}=2^2.3=12\)
Có gì sai sót thì bỏ qua nhé chị !
Ta có : \(\frac{2^7.9^2}{3^3.2^5}=\frac{2^5.2^2.81}{27.2^5}=\frac{2^5.2^2.27.3}{27.2^5}=2^2.3=12\)
Vậy \(\frac{2^7.9^2}{3^3.2^5}=12\)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\dfrac{2^7.9^2}{3^3.2^5}\)
\(=\dfrac{2^7.\left(3^2\right)^2}{3^3.2^5}\)
\(=\dfrac{2^7.3^4}{3^3.2^5}\)
\(=2^2.3\)
\(=4.3\)
\(=12\)
\(\dfrac{2^7.9^2}{3^3.2^5}=\dfrac{2^7.\left(3^2\right)^2}{3^3.2^5}=\dfrac{2^7.3^4}{3^3.2^5}=\dfrac{2^2.3}{1}=4.3=12\)
![](https://rs.olm.vn/images/avt/0.png?1311)
Ta có :\(\frac{2^7.9^2}{3^3.2^5}=\frac{2^7.\left(3^2\right)^2}{3^3.2^5}\)
\(=\frac{2^7.3^4}{3^3.2^5}=\frac{2^2.3}{1}=12\)
Trả lời:
\(\frac{2^7.9^2}{3^3.2^5}=\frac{2^2.\left(3^2\right)^2}{3^3}=\frac{2^2.3^4}{3^3}=\frac{2^2.3}{1}=4.3=12\)
Học tốt
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\frac{2^7.9^2}{3^3.2^5}=\frac{2^7.3^4}{3^3.2^5}=\frac{2^2.3}{1.1}=12\)
![](https://rs.olm.vn/images/avt/0.png?1311)
Mk sửa đề nha :
\(C=\frac{-5}{7}.\frac{2}{11}+\frac{-5}{7}.\frac{9}{11}+\frac{12}{7}\)
\(=\frac{-5}{7}.\left(\frac{2}{11}+\frac{9}{11}\right)+\frac{12}{7}\)
\(=\frac{-5}{7}.1+\frac{12}{7}\)
\(=\frac{-5}{7}+\frac{12}{7}\)
\(=1\)
Study well ! >_<
\(\frac{2^7.9^2}{3^3.2^5}\)\(=\frac{2^7.\left(3^2\right)^2}{3^3.2^5}=\frac{2^7.3^4}{3^3.2^5}=\frac{2^2.3}{1}=2^2.3=4.3=12\)