a, 3^3*x+1 *5 = 10935
b, 2^5*x+1 *3= 6144
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DA
4
4 tháng 10 2020
a) 33x+1 . 5 = 10935
=> 33x . 3 . 5 = 10935
=> 27x . 3 . 5 = 10935
=> 27x = 729
=> 27x = 272
=> x = 2
b) 25x + 1 . 3 = 6144
=> 25x . 2 . 3 = 6144
=> 32x . 6 = 6144
=> 32x = 1024
=> 32x = 322
=> x = 2
c) (2x + 3)4 = 625
=> (2x + 3)4 = (\(\pm\)5)4
=> \(\orbr{\begin{cases}2x+3=5\\2x+3=-5\end{cases}}\Rightarrow\orbr{\begin{cases}x=1\\x=-4\end{cases}}\)
d) (3x + 1)3 = 343
=> (3x + 1)3 = 73
=> 3x + 1 = 7 => 3x = 6 => x = 2
HN
14 tháng 11 2019
\(3^{3x+1}.5=10935\)
\(\Rightarrow3^{3x+1}=10935:5\)
\(\Rightarrow3^{3x+1}=2187\)
\(\Rightarrow3^{3x+1}=3^7\)
\(\Rightarrow3x+1=7\)
\(\Rightarrow3x=6\)
\(\Rightarrow x=2\)
\(2^{5x+1}.3=6144\)
\(\Rightarrow2^{5x+1}=6144:3\)
\(\Rightarrow2^{5x+1}=2048\)
\(\Rightarrow2^{5x+1}=2^{11}\)
\(\Rightarrow5x+1=11\)
\(\Rightarrow5x=10\)
\(\Rightarrow x=2\)
14 tháng 11 2019
1) 33.x+1.5=10935
33.x+1 = 10935 : 5
33.x+1 = 2187
Mà 2187 = 37
=> 33.x+1 = 37
=> 3.x + 1 = 7
=> 7 = 3.2+1 = 6 +1 = 7
=> 33.2+1 . 5 = 10935
2) 25.x+1.3=6144
25.x+1 = 6144 : 3
25.x+1 = 2048
=> 2048 = 25.x+1
Mà 2048 = 211
=> 211 = 25.x+1
=> 5.x + 1 = 11
=> 11 = 5.2+1 = 10 +1 = 11
=> 25.2+1 . 5 = 10935
TT
6
NL
14 tháng 11 2019
a)
\(3^{3x+1}=\frac{10935}{5}\)
\(3^{3x+1}=2187=3^7\)
\(\Rightarrow3x+1=7\)
\(3x=7-1\)
\(3x=6\)
\(x=\frac{6}{3}=2\)
14 tháng 11 2019
a)3^3x+1=10935/5
=>3^3x+1=2187
=>3^3x+1=3^7
=>3x+1=7
=>3x=6
=>x=2
Vậy x=2
17 tháng 8 2023
a: =>x-2/5=3/4:1/3=3/4*3=9/4
=>x=9/4+2/5=45/20+8/20=53/20
b: =>x-2/3=7/3:4/5=7/3*5/4=35/12
=>x=35/12+2/3=43/12
c: 1/3(x-2/5)=4/5
=>x-2/5=4/5*3=12/5
=>x=12/5+2/5=14/5
d: =>2/3x-1/3-1/4x+1/10=7/3
=>5/12x-7/30=7/3
=>5/12x=7/3+7/30=77/30
=>x=77/30:5/12=154/25
e: \(\Leftrightarrow x\cdot\dfrac{3}{7}-\dfrac{2}{7}+\dfrac{1}{2}-\dfrac{5}{4}x+\dfrac{5}{2}=0\)
=>\(x\cdot\dfrac{-23}{28}=\dfrac{2}{7}-3=\dfrac{-19}{7}\)
=>x=19/7:23/28=76/23
f: =>1/2x-3/2+1/3x-4/3+1/4x-5/4=1/5
=>13/12x=1/5+3/2+4/3+5/4=257/60
=>x=257/65
i: =>x^2-2/5x-x^2-2x+11/4=4/3
=>-12/5x=4/3-11/4=-17/12
=>x=17/12:12/5=85/144
28 tháng 4 2018
a) \(\left(3x-1\right).\left(\frac{-1}{2}x+5\right)=0\)
\(\Rightarrow3x-1=0\Rightarrow3x=1\Rightarrow x=\frac{1}{3}\)
\(\frac{-1}{2}x+5=0\Rightarrow\frac{-1}{2}x=-5\Rightarrow x=10\)
b) \(3\left(x-\frac{1}{2}\right)-5\left(x+\frac{3}{5}\right)=x+\frac{1}{5}\)
\(3x-\frac{3}{2}-5x-3=x+\frac{1}{5}\)
\(\Rightarrow3x-5x-x=\frac{1}{5}+\frac{3}{2}+3\)
\(-3x=\frac{47}{10}\)
\(x=\frac{-47}{30}\)
c) \(-5.\left(x+\frac{1}{5}\right)-\frac{1}{2}\left(x-\frac{2}{3}\right)=\frac{3}{2}x-\frac{5}{6}\)
\(-5x-1-\frac{1}{2}x+\frac{1}{3}=\frac{3}{2}x-\frac{5}{6}\)
\(-5x-\frac{1}{2}x-\frac{3}{2}x=\frac{-5}{6}+1-\frac{1}{3}\)
\(-7x=\frac{-1}{6}\)
\(x=\frac{1}{42}\)
d) \(3.\left(3x-\frac{1}{2}\right)^3+\frac{1}{9}=0\)
\(3.\left(3x-\frac{1}{2}\right)^3=\frac{-1}{9}\)
\(\left(3x-\frac{1}{2}\right)^3=\frac{-1}{27}\)
\(\left(3x-\frac{1}{2}\right)^3=\left(\frac{-1}{3}\right)^3\)
\(\Rightarrow3x-\frac{1}{2}=\frac{-1}{3}\)
\(3x=\frac{1}{6}\)
\(x=\frac{1}{18}\)
Học tốt nhé bn!
9 tháng 1 2021
Câu 1 :
a, \(\frac{3\left(2x+1\right)}{4}-\frac{5x+3}{6}=\frac{2x-1}{3}-\frac{3-x}{4}\)
\(\Leftrightarrow\frac{6x+3}{4}+\frac{3-x}{4}=\frac{2x-1}{3}+\frac{5x+3}{6}\)
\(\Leftrightarrow\frac{5x+6}{4}=\frac{9x+1}{6}\Leftrightarrow\frac{30x+36}{24}=\frac{36x+4}{24}\)
Khử mẫu : \(30x+36=36x+4\Leftrightarrow-6x=-32\Leftrightarrow x=\frac{32}{6}=\frac{16}{3}\)
tương tự
PN
16 tháng 5 2021
\(\frac{19}{4}-\frac{2\left(3x-5\right)}{5}=\frac{3-2x}{10}-\frac{3x-1}{4}\)
\(< =>\frac{19.5}{20}-\frac{8\left(3x-5\right)}{20}=\frac{2\left(3-2x\right)}{20}-\frac{5\left(3x-1\right)}{20}\)
\(< =>95-24x+40=6-4x-15x+5\)
\(< =>-24x+135=-19x+11\)
\(< =>5x=135-11=124\)
\(< =>x=\frac{124}{5}\)
KV
4 tháng 11 2023
Bài 1
a) 3 2/5 - 1/2
= 17/5 - 1/2
= 34/10 - 5/10
= 29/10
b) 4/5 + 1/5 × 3/4
= 4/5 + 3/20
= 16/20 + 3/20
= 19/20
c) 3 1/2 × 1 1/7
= 7/2 × 8/7
= 4
d) 4 1/6 : 2 1/3
= 25/6 : 7/3
= 25/14
KV
4 tháng 11 2023
Bài 2
a) 3 × 1/2 + 1/4 × 1/3
= 3/2 + 1/12
= 18/12 + 1/12
= 19/12
b) 1 4/5 - 2/3 : 2 1/3
= 9/5 - 2/3 : 7/3
= 9/5 - 2/7
= 63/35 - 10/35
= 53/35
PC
1
5 tháng 3 2022
a, \(-5x-1-\dfrac{x}{2}+\dfrac{1}{3}=\dfrac{3}{2}x-5\Leftrightarrow-7x=-\dfrac{13}{3}\Leftrightarrow x=\dfrac{13}{21}\)
b, \(3x-\dfrac{3}{2}-5x-3=-x+\dfrac{1}{5}\Leftrightarrow-x=\dfrac{47}{10}\Leftrightarrow x=-\dfrac{47}{10}\)
a) \(3^3\cdot x+5=10935\)
\(27\cdot x=10935-5\)
\(27\cdot x=10930\)
\(x=\frac{10930}{27}\)
\(x=404,8148148\)
b) \(32\cdot x+3=6144\)
\(32\cdot x=6144-3\)
\(32\cdot x=6141\)
\(x=\frac{6141}{32}\)
\(x=191,90625\)