tim x
(x-3):[\(\frac{1}{2}\)nhan (-1\(\frac{3}{4}\)) ] = -2\(\frac{1}{2}\)
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DP
16 tháng 6 2017
\(a.\) \(25,4-\frac{1}{4}\div x+1250\%=37,5\)
\(25,4-0.25\div x+12,5=37,5\)
\(25,4-0,25\div x=37,5-12,5\)
\(25,4-0,25\div x=25\)
\(0,25\div x=25,4-25\)
\(0,25\div x=0,4\)
\(x=0,25\div0,4\)
\(x=0,625\)
\(b.\)\(3\frac{1}{8}\div\left(\frac{2}{5}-x\right)\times\frac{8}{25}=3\)
\(\frac{3\times8+1}{8}\div\left(\frac{2}{5}-x\right)=3\div\frac{8}{25}\)
\(\frac{25}{8}\div\left(\frac{2}{5}-x\right)=\frac{75}{8}\)
\(\frac{2}{5}-x=\frac{25}{8}\div\frac{75}{8}\)
\(\frac{2}{5}-x=\frac{25}{8}\times\frac{8}{75}\)
\(\frac{2}{5}-x=\frac{1}{3}\)
\(x=\frac{2}{5}-\frac{1}{3}=\frac{6}{15}-\frac{5}{15}\)
\(x=\frac{1}{15}\)
16 tháng 6 2017
a)25,4-\(\frac{1}{4}\): x +1250%=37,5
25,4 - 0,25 : x + 12,5 = 37,5
25,4 - 0,25 : x =37,5 -12,5
25,4 - 0,25 : x = 25
0,25 : x = 25,4 -25
0,25 : x = 0,4
x = 0,25;0,4
x = 0,625
b) \(3\frac{1}{8}:\left(\frac{2}{5}-x\right)\times\frac{8}{25}=3\)
\(3,125:\left(0,4-x\right)\times0,32=3\)
\(3,125:\left(0,4-x\right)=3:0,32\)
\(3,125:\left(0,4-x\right)=9,375\)
\(0,4-x=3,125:9,375\)
\(0,4-x=\frac{1}{3}\)
\(x=0,4-\frac{1}{3}\)
\(x=\frac{1}{15}\)
8 tháng 7 2017
\(\frac{x+2015}{5}+\frac{x+2016}{4}=\frac{x+2017}{3}+\frac{x+2018}{2}\)
\(\Leftrightarrow\left(\frac{x+2015}{5}+1\right)+\left(\frac{x+2016}{4}+1\right)=\left(\frac{x+2017}{3}+1\right)+\left(\frac{x+2018}{2}+1\right)\)
\(\Leftrightarrow\frac{x+2020}{5}+\frac{x+2020}{4}-\frac{x+2020}{3}-\frac{x+2020}{2}=0\)
\(\Leftrightarrow\left(x+2020\right)\left(\frac{1}{5}+\frac{1}{4}-\frac{1}{3}-\frac{1}{2}\right)=0\)
\(\Leftrightarrow x+2020=0\)vì \(\frac{1}{5}+\frac{1}{4}+\frac{1}{3}+\frac{1}{2}\ne0\)
\(\Leftrightarrow x=-2020\)
F
0
PH
0
\(\left(x-3\right):\left[\frac{1}{2}.\left(-1\frac{3}{4}\right)\right]=-2\frac{1}{2}\)
\(\left(x-3\right):\left[\frac{1}{2}.\left(\frac{-7}{4}\right)\right]=\frac{-5}{2}\)
\(\left(x-3\right):\frac{-7}{8}=\frac{-5}{2}\)
\(\left(x-3\right)=\frac{-5}{2}.\frac{-7}{8}\)
\(\left(x-3\right)=\frac{35}{16}\)
\(x=\frac{35}{16}+3=\frac{83}{16}\)
\(\left(x-3\right):\left[\frac{1}{2}.\left(-1\frac{3}{4}\right)\right]=-2\frac{1}{2}\)
\(\left(x-3\right):\left(\frac{1}{2}.\frac{-7}{4}\right)=\frac{-5}{2}\)
\(\left(x-3\right):\frac{-7}{8}=\frac{-5}{2}\)
\(x-3=\frac{-5}{2}.\frac{-7}{8}\)
\(x-3=\frac{35}{16}\)
\(x=\frac{35}{16}+3\)
\(x=\frac{35+48}{16}=\frac{83}{16}\)