( x -1 ) ^2 / 3 = 9 / x -1
nhanh nhe mik tik
/ co nghia la a/b phan so do
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CW
12 tháng 3 2017
a, (1-x)(5x+3)= (3x-8)(1-x)
<=> (1-x) (5x+3) - (3x-8)(1-x) =0 <=> (1-x) (2x+11) = 0
\(\Leftrightarrow\left[{}\begin{matrix}1-x=0\\2x+11=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=1\\x=-\dfrac{11}{2}\end{matrix}\right.\)
Vậy.........
b, (x-3)(x+4)-2(3x-2)=(x-4)^2
<=> 3x = 24<=> x=8
Vậy .......
c,x^2+ x^3+x+1=0
<=> x^2 (x+1) +(x+1) =0 <=> (x^2 +1)(x+1) =0
<=> x+1 =0 => x=-1
Vậy.......
d, \(\dfrac{x-3}{x+3}-\dfrac{2}{x-3}=\dfrac{3x+1}{9-x^2}\)
\(\Leftrightarrow x^2-6x+9-2x-6=-3x-1\)
\(\Leftrightarrow x^2-5x+4=0\Leftrightarrow\left(x+4\right)\left(x-1\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}x+4=0\\x-1=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=-4\\x=1\end{matrix}\right.\)
Vậy...........
27 tháng 10 2015
a) không tồn tại số tự nhiên x
b) x= 5,1; 5,2; 5,3; 5,4; 5,5; 5,6; 5,7; 5,8; 5,9
trong cùng em học toán hả
PH
2
5 tháng 7 2017
\(a,\frac{x+6}{x+1}\)
\(\left\{\left(x+6\right)-\left(x+1\right)\right\}⋮x+1\)
\(5⋮x+1\)
\(x+1\inƯ_{\left(5\right)}=\left\{-5;5;1;-1\right\}\)
\(=>x\inƯ_{\left(5\right)}=\left\{-6;4;0;-2\right\}\)
5 tháng 7 2017
\(b,\frac{x-2}{x+3}\)
\(\left\{\left(x+3\right)-\left(x-2\right)\right\}⋮x+3\)
\(5⋮x+3\)\(=>x+3\inƯ_{\left(5\right)}=\left\{-5;5;-1;1\right\}\)
\(=>x\in\left\{-8;2;-4;-2\right\}\)
5 tháng 12 2015
a)3/4+1/1/4*2/2/3-(-1/2)^2:6/5
=3/4+5/4*8/3-1/4:6/5
=3/4+10/3-5/24=18/24+80/24-5/24=93/24=31/8
b)(x-1)^5=32=2^5
=>x-1=2
x=2+1
x=3
15 tháng 4 2019
\(a,\frac{6}{7}+\frac{5}{8}:5-\frac{3}{16}\cdot(-2)^2\)
\(=\frac{6}{7}+\frac{5}{8}:\frac{5}{1}-\frac{3}{16}\cdot4\)
\(=\frac{6}{7}+\frac{5}{8}\cdot\frac{1}{5}-\frac{3}{16}\cdot4\)
\(=\frac{6}{7}+\frac{1}{8}-\frac{3\cdot4}{16}\)
\(=\frac{6}{7}+\frac{1}{8}-\frac{3\cdot1}{4}\)
\(=\frac{6}{7}+\frac{1}{8}-\frac{3}{4}=\frac{48+7-42}{56}=\frac{13}{56}\)
\(b,\frac{2}{3}+\frac{1}{3}\cdot\left[\frac{-2}{3}+\frac{5}{6}\right]:\frac{2}{3}\)
\(=\frac{2}{3}+\frac{1}{3}\cdot\left[\frac{-4+5}{6}\right]:\frac{2}{3}\)
\(=\frac{2}{3}+\frac{1}{3}\cdot\frac{1}{6}:\frac{2}{3}=\frac{2}{3}+\frac{1}{3}\cdot\frac{1}{6}\cdot\frac{3}{2}=\frac{2}{3}+\frac{1}{12}=\frac{8}{12}+\frac{1}{12}=\frac{9}{12}=\frac{3}{4}\)
c, Xem lại đề
d, \(\frac{-3}{5}+\left[\frac{-2}{5}-99\right]\)
\(=\frac{-3}{5}+\frac{-497}{5}=\frac{-500}{5}=-100\)
b, Tìm x
\(\left[\frac{2}{11}+\frac{1}{3}\right]\cdot x=\left[\frac{1}{7}-\frac{1}{8}\right]\cdot56\)
\(\Rightarrow\left[\frac{2}{11}+\frac{1}{3}\right]\cdot x=\left[\frac{8}{56}-\frac{7}{56}\right]\cdot56\)
\(\Rightarrow\left[\frac{6}{33}+\frac{11}{33}\right]\cdot x=1\)
\(\Rightarrow\frac{17}{33}\cdot x=1\)
\(\Rightarrow x=1:\frac{17}{33}=1\cdot\frac{33}{17}=\frac{33}{17}\)
\(\frac{\left(x-1\right)^2}{3}=\frac{9}{x-1}\)
\(\Rightarrow\left(x-1\right)^3=27\)
\(\Rightarrow\left(x-1\right)^3=3^3\)
\(\Rightarrow x-1=3\)
\(\Rightarrow x=4\)