x mũ 18 = x mũ 13
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![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
dai the giai bao gio xong chac mua quyt nam sau moi giai xong
![](https://rs.olm.vn/images/avt/0.png?1311)
a: \(27^{x-1}=9^2\)
\(\Leftrightarrow3^{3x-3}=3^4\)
=>3x-3=4
=>3x=7
hay x=7/3
b: \(32^9=2^{45}\)
\(18^{13}=\left(2\right)^{13}\cdot3^{26}\)
mà \(2^{32}< 3^{26}\)
nên \(32^9< 18^{13}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
1, 15-(2x-3)=6
<=>2x-3=15-6
<=>2x=15-6+3
<=>2x=12
<=>x=12:2
<=>x=6
Vậy x=6
2, (x-2).3=3\(^2\)
<=>x-2=3\(^2\):3
<=>x-2=9:3
<=>x=9:3-2
<=>x=1
vậy x=1
3, (x+7)-25=13
<=>x+7=13+25
<=>x=13+25-7
<=>x=31
Vậy x=31
4, 450:(x-190)=50
<=>x-190=450:50
<=>x=450:50+/ 190
<=>x=199
Vậy x=199
5, 3 \(^x\)x 2=18
<=>3\(^x\)=18:2
<=>3\(^x\)=9=3\(^2\)
=>x=2
vậy x=2
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\frac{9^{14}\cdot25^5\cdot8^7}{18^{12}\cdot625^3\cdot24^3}=\frac{3^{28}\cdot5^{10}\cdot2^{21}}{2^{12}\cdot3^{24}\cdot5^{12}\cdot2^9\cdot3^3}=\frac{3\cdot3^{27}\cdot5^{10}\cdot2^{21}}{2^{21}\cdot3^{27}\cdot5^2\cdot5^{10}}=\frac{3}{5^2}=\frac{3}{25}\)
\(\frac{9^{14}.25^5.8^7}{18^{12}.625^3.24^3}\)
\(=\)\(\frac{3^{28}.5^{10}.2^{21}}{2^{12}.3^{24}.5^{12}.2^9.3^3}\)
\(=\)\(\frac{3.3^{27}.5^{10}.2^{21}}{2^{21}.3^{27}.5^2.5^{10}}\)
\(=\)\(\frac{3}{5^2}\)
\(=\)\(\frac{3}{25}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(13^4\times16^2=13\times13\times13\times13\times16\times16\)
\(=\left(13\times13\right)\times\left(13\times13\right)\times\left(13\times6\right)\)
\(=28561\times256\)
\(=7311616=52^4\)
134.162
= 134.(42)2
= 134.44
= (13.4)4
= 524
![](https://rs.olm.vn/images/avt/0.png?1311)
Tìm x hả bạn ?
a ) \(\left(3x+\frac{1}{4}\right)^3=-27\)
\(\left(3x+\frac{1}{4}\right)^3=\left(-3\right)^3\)
\(\Rightarrow3x+\frac{1}{4}=-3\)
\(\Rightarrow3x=-3-\frac{1}{4}=-\frac{13}{4}\)
\(\Rightarrow x=-\frac{13}{4}:3=-\frac{13}{12}\)
Vậy x = \(-\frac{13}{12}\)
cho em hoi câu này xin các anh chị:
10mux x+4y = 2013
![](https://rs.olm.vn/images/avt/0.png?1311)
1. 53 = 5.5.5 = 125
2. 27 = 2.2.2.2.2.2.2 = 128
3. 44 = 4.4.4.4 = 256
4. 73 = 7.7.7 = 343
6. 35 = 243
7. 26 = 64
8. 34 = 81
9. 83 = 512
11. 132 = 169
12. 112 = 121
13. 142 = 196
14. 152 = 225
16. 172 = 289
17. 182 = 324
18. 192 = 361
19. 202 = 400
21. 104 = 10000
22. 105 = 100000
23. 106 = 1000000
24. 107 = 10000000
![](https://rs.olm.vn/images/avt/0.png?1311)
a, (-0,2)2 \(\times\) 5 - \(\dfrac{2^{13}\times27^3}{4^6\times9^5}\)
= 0,04 \(\times\) 5 - \(\dfrac{2^{13}\times3^9}{2^{12}\times3^{10}}\)
= 0,2 - \(\dfrac{2}{3}\)
= \(\dfrac{2}{10}\) - \(\dfrac{2}{3}\)
= - \(\dfrac{7}{15}\)
b, \(\dfrac{5^6+2^2.25^3+2^3.125^2}{26.5^6}\)
= \(\dfrac{5^6+4.5^6+8.5^6}{26.5^6}\)
= \(\dfrac{5^6.\left(1+4+8\right)}{26.5^6}\)
= \(\dfrac{1}{2}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
Đề bài:\(5^x\times5^{x+1}\times5^{x+2}\le100...0\left(18\text{ số }10\right):2^{18}\)
Hay có thể viết thế này:\(5^x.5^{x+1}.5^{x+2}\le10^{18}:2^{18}=5^{18}\)
\(\Leftrightarrow5^{x+\left(x+1\right)+\left(x+2\right)}\le5^{18}\)
\(\Leftrightarrow x+\left(x+1\right)+\left(x+2\right)\le18\)
\(\Leftrightarrow3x+3\le18\)
\(\Leftrightarrow3x\le15\Leftrightarrow x\le5\)
lấy số mũ + với nhau giữ nguyên x là ra nhé
x18 = x13
=> x18 - x13 = 0
=> x13 . ( x5 - 1 ) = 0
\(\Rightarrow\orbr{\begin{cases}x^{13}=0\\x^5-1=0\end{cases}}\)
\(\Rightarrow\orbr{\begin{cases}x=0\\x^5=1\end{cases}}\)
\(\Rightarrow\orbr{\begin{cases}x=0\\x=1\end{cases}}\)