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16 tháng 10 2018

28=256

33=27

52=25

16 tháng 10 2018

\(2^8=2.2.2.2.2.2.2.2=256\)

\(3^3=3.3.3=27\)

\(5^2=5.5=25\)

5: \(=3-\dfrac{1}{4}+\dfrac{2}{3}-5+\dfrac{1}{3}+\dfrac{6}{5}-6+\dfrac{7}{4}-\dfrac{3}{2}\)

\(=3-5-6+\dfrac{-1}{4}+\dfrac{7}{4}+\dfrac{2}{3}+\dfrac{1}{3}+\dfrac{6}{5}-\dfrac{3}{2}\)

\(=-8+\dfrac{3}{2}+1+\dfrac{-3}{10}\)

\(=-7+\dfrac{15-3}{10}=-7+\dfrac{6}{5}=-\dfrac{29}{5}\)

6: \(=6-\dfrac{2}{3}+\dfrac{1}{2}-5-\dfrac{5}{3}+\dfrac{3}{2}-3+\dfrac{7}{3}-\dfrac{5}{2}\)

\(=6-5-3-\dfrac{2}{3}-\dfrac{5}{3}+\dfrac{7}{3}+\dfrac{1}{2}+\dfrac{3}{2}-\dfrac{5}{2}\)

\(=-2-\dfrac{1}{2}=-\dfrac{5}{2}\)

7: \(=\dfrac{5}{3}-\dfrac{3}{7}+9-2-\dfrac{5}{7}+\dfrac{2}{3}+\dfrac{8}{7}-\dfrac{4}{3}-10\)

\(=9-2-10+\dfrac{5}{3}+\dfrac{2}{3}-\dfrac{4}{3}+\dfrac{-3}{7}-\dfrac{5}{7}+\dfrac{8}{7}\)

=-3+1

=-2

8: \(=8-\dfrac{9}{4}+\dfrac{2}{7}+6+\dfrac{3}{7}-\dfrac{5}{4}-3-\dfrac{2}{4}+\dfrac{9}{7}\)

\(=8+6-3+\dfrac{2}{7}+\dfrac{3}{7}+\dfrac{9}{7}-1-\dfrac{2}{4}\)

\(=11+2-1-\dfrac{1}{2}\)

=11+1/2

=11,5

2 tháng 12 2019

Lời giải chi tiết:

8 – 3 = 5 8 – 5 = 3 8 – 6 = 2 8 – 8 = 0
8 – 1 – 2 = 5 8 – 2 – 3 = 3 8 – 5 – 1 = 2 8 – 0 = 8
8 – 2 – 1 = 5 8 – 3 – 2 = 3 8 – 1 – 5 = 2 8 + 0 = 8
18 tháng 12 2021

5 5 5 3 3 3

31 tháng 12 2018

mình đang cần gấp câu trả lời ,bạn nào giải được nhanh k luôn ,hứa đấy

31 tháng 12 2018

bạn đi học thêm à ?

28 tháng 8 2021

a,

\(5^{x+4}-3.5^{x+3}=2.5^{11}\)

\(\Rightarrow5^{x+3}\left(5-3\right)=2.5^{11}\)

\(\Rightarrow5^{x+3}2=2.5^{11}\)

\(\Rightarrow5^{x+3}=5^{11}\)

\(\Rightarrow x+3=11\)

\(\Rightarrow x=8\)

28 tháng 8 2021

b, (Check lai xem de sai o dau khong nhe)

\(3.5^{x+2}+4.5^{x+3}=19.5^{10}\)

Dat 5x ra ben ngoai

\(\Rightarrow5^x.5^23+5^x:5^{-3}.4\)

\(\Rightarrow5^x\left(5^2.3+5^{-3}.4\right)\)

\(\Rightarrow5^x\left(5^{-3}.5^5.3+5^{-3}.4\right)\)

\(\Rightarrow5^x[5^{-3}\left(5^53+4\right)\)

\(\Rightarrow5^x[5^{-3}\left(3125.3+4\right)\)

\(\Rightarrow5^x\left(5^{-3}\right).9379\)

=> Khong tim duoc gia tri cua x \(\Rightarrow x\in\varnothing\)

Chọn A

a) Ta có: \(\dfrac{-5}{7}\left(\dfrac{14}{5}-\dfrac{7}{10}\right):\left|-\dfrac{2}{3}\right|-\dfrac{3}{4}\left(\dfrac{8}{9}+\dfrac{16}{3}\right)+\dfrac{10}{3}\left(\dfrac{1}{3}+\dfrac{1}{5}\right)\)

\(=\dfrac{-5}{7}\cdot\dfrac{3}{2}\cdot\dfrac{21}{10}-\dfrac{3}{4}\cdot\dfrac{56}{3}+\dfrac{10}{3}\cdot\dfrac{8}{15}\)

\(=\dfrac{-9}{4}-14+\dfrac{16}{9}\)

\(=\dfrac{-1621}{126}\)

b) Ta có: \(\dfrac{17}{-26}\cdot\left(\dfrac{1}{6}-\dfrac{5}{3}\right):\dfrac{17}{13}-\dfrac{20}{3}\left(\dfrac{2}{5}-\dfrac{1}{4}\right)+\dfrac{2}{3}\left(\dfrac{6}{5}-\dfrac{9}{2}\right)\)

\(=\dfrac{-17}{26}\cdot\dfrac{13}{17}\cdot\dfrac{-3}{2}-\dfrac{20}{3}\cdot\dfrac{3}{20}+\dfrac{2}{3}\cdot\dfrac{-33}{10}\)

\(=\dfrac{3}{4}-1-\dfrac{11}{5}\)

\(=-\dfrac{49}{20}\)

9 tháng 8 2023

a) \(4\dfrac{3}{8}+5\dfrac{2}{3}\)

\(=\dfrac{35}{8}+\dfrac{17}{3}\)

\(=\dfrac{105}{24}+\dfrac{136}{24}\)

\(=\dfrac{241}{24}\)

b) \(2\dfrac{3}{8}+1\dfrac{1}{4}+3\dfrac{6}{7}\)

\(=\dfrac{19}{8}+\dfrac{5}{4}+\dfrac{27}{7}\)

\(=\dfrac{29}{8}+\dfrac{27}{7}\)

\(=\dfrac{419}{56}\)

c) \(2\dfrac{3}{8}-1\dfrac{1}{4}+5\dfrac{1}{3}\)

\(=\dfrac{19}{8}-\dfrac{5}{4}+\dfrac{16}{3}\)

\(=\dfrac{9}{8}+\dfrac{16}{3}\)

\(=\dfrac{155}{24}\)

d) \(\left(\dfrac{5}{2}+\dfrac{1}{3}\right):\left(1-\dfrac{1}{2}\right)\)

\(=\dfrac{17}{6}:\dfrac{1}{2}\)

\(=\dfrac{17}{6}\cdot2\)

\(=\dfrac{17}{3}\)

e) \(\left(\dfrac{5}{2}-\dfrac{1}{3}\right)\cdot\dfrac{9}{2}-\dfrac{6}{7}\)

\(=\dfrac{13}{6}\cdot\dfrac{9}{2}-\dfrac{6}{7}\)

\(=\dfrac{39}{4}-\dfrac{6}{7}\)

\(=\dfrac{249}{28}\)

a: =4+3/8+5+2/3

=9+9/24+16/24

=9+25/24

=216/24+25/24=241/24

b: \(=\dfrac{19}{8}+\dfrac{5}{4}+\dfrac{27}{7}=\dfrac{19+10}{8}+\dfrac{27}{7}\)

=27/7+29/8

=419/56

c: =2+3/8-1-1/4+5+1/3

=6+3/8-1/4+1/3

=6+3/8+1/12

=144/24+9/24+2/24

=155/24

d: =(15/6+2/6):1/2

=17/6*2

=17/3

e: =(15/6-2/6)*9/2-6/7

=13/6*9/2-6/7

=117/12-6/7

=249/28

10 tháng 8 2021

Xóa nhanh đi ko CTV xóa giờ

10 tháng 8 2021

xóa j