bài 1 tìm x
a) \(\frac{1}{20}-\left(x-\frac{8}{5}\right)=\frac{1}{10}\) b) /x-\(\frac{3}{2}\)/=\(\frac{4}{3}\) c) /x-\(\frac{1}{3}\)/= / \(-\frac{5}{2}\)/ -\(\left(\frac{1}{4}-\frac{2}{3}\right)\)
d)/x-\(\frac{5}{8}\)/-\(\frac{3}{4}\)=0 e) /2.x+ \(\frac{5}{6}\)/= /\(\frac{1}{5}-\frac{2}{3}\)/+\(\frac{-3}{4}\)
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Đọc tiếp
bài 1 tìm x
a) \(\frac{1}{20}-\left(x-\frac{8}{5}\right)=\frac{1}{10}\) b) /x-\(\frac{3}{2}\)/=\(\frac{4}{3}\) c) /x-\(\frac{1}{3}\)/= / \(-\frac{5}{2}\)/ -\(\left(\frac{1}{4}-\frac{2}{3}\right)\)
d)/x-\(\frac{5}{8}\)/-\(\frac{3}{4}\)=0 e) /2.x+ \(\frac{5}{6}\)/= /\(\frac{1}{5}-\frac{2}{3}\)/+\(\frac{-3}{4}\)
giúp mk vs mk đang cần gấp
a: =>x-8/5=1/20-1/10=-1/20
=>x=-0,05+1,6=1,55
b: =>x-3/2=4/3 hoặc x-3/2=-4/3
=>x=17/6 hoặc x=1/6
c: =>\(\left|x-\dfrac{1}{3}\right|=\dfrac{5}{2}-\dfrac{1}{4}+\dfrac{2}{3}=\dfrac{35}{12}\)
=>x-1/3=35/12 hoặc x-1/3=-35/12
=>x=39/12=13/4 hoặc x=-31/12
d: =>|x-5/8|=3/4
=>x-5/8=3/4 hoặc x-5/8=-3/4
=>x=11/8 hoặc x=-1/8