1,CMR: a,810-89-88⋮55 b,817-279-913⋮45 c,76+75-74⋮11
2,CMR:abcd⋮99 thì ab+cd⋮99
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a) \(7^6+7^5-7^4=7^4\left(7^2+7-1\right)=7^4\left(49+7-1\right)=7^4.55⋮55\)
b) \(16^5+2^{15}=\left(2^4\right)^5+2^{15}=2^{20}+2^{15}=2^{15}\left(2^5+1\right)=2^{15}\left(32+1\right)=2^{15}.33⋮33\)
c) \(81^7-27^9-9^{13}=\left(3^4\right)^7-\left(3^3\right)^9-\left(3^2\right)^{13}=3^{28}-3^{27}-3^{26}=3^{26}\left(3^2-3-1\right)=3^{26}.5=3^{22}.3^4.5=3^{22}.405⋮405\)
a: \(=7^4\left(7^2+7-1\right)=7^4\cdot55⋮55\)
b: \(=2^{20}+2^{15}=2^{15}\left(2^5+1\right)=2^{15}\cdot33⋮33\)
c: \(=3^{28}-3^{27}-3^{26}=3^{26}\left(3^2-3-1\right)=3^{26}\cdot5=3^{22}\cdot405⋮405\)
a) 7⁶ + 7⁵ - 7⁴
= 7⁴.(7² + 7 - 1)
= 7⁴.55 ⋮ 55
Vậy (7⁶ + 7⁵ - 7⁴) ⋮ 55
b) 81⁷ - 27⁹ + 3²⁹
= (3⁴)⁷ - (3³)⁹ + 3²⁹
= 3²⁸ - 3²⁷ + 3²⁹
= 3²⁶.(3² - 3 + 3³)
= 3²⁶.(9 - 3 + 27)
= 3²⁶.33 ⋮ 33
Vậy (81⁷ - 27⁹ + 3²⁹) ⋮ 33
(45+75)*66+(75+45)*34
=(45+75)*(66+34)
=120*100
=12000
11+22+33+44+55+66+77+88+99:11
=11+22+33+44+55+66+77+88+9
=(11+9)+(22+88)+(33+77)+(44+66)+55
=20+110*3+55
=20+330+55
=405
Ta có :
a, (45 + 75) x 66 + (75 + 45) x 34
= (45 + 75) x (66 + 34)
= 120 x 100
= 12000
11 + 22 + 33 + 44 + 55 + 66 + 77 + 88 + 99 : 11
= 33 + 77 + 121 + 165 + 9
= 405
Bài 2.Tínhnhẩm:
51 x 11 = 561 | 59 x 11 = 649 |
91 x 11 = 1001 | 45 x 11 =495 |
88 x 11 = 968 | 89 x 11 =979 |
99 x 11 = 1089 | 94 x 11 = 1034 |
Câu 1:
a: \(=8^8\left(8^2-8-1\right)=8^8\cdot55⋮55\)
b: \(=3^{28}-3^{27}-3^{26}=3^{26}\left(3^2-3-1\right)=3^{26}\cdot5=3^{24}\cdot45⋮45\)
c: \(=7^4\left(7^2+7-1\right)=7^4\cdot55⋮11\)