Tìm x biết (x+1)5=(x+1)3
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\(1.x-\dfrac{2}{3}\times\left(x+9\right)=1\)
\(x-\dfrac{2}{3}\times x-6=1\)
\(x\times\left(1-\dfrac{2}{3}\right)=7\)
\(x\times\dfrac{1}{3}=7\)
\(x=21\)
\(2.x-\dfrac{11}{15}=\dfrac{3+x}{5}\)
\(\dfrac{15x}{15}-\dfrac{11}{15}=\dfrac{9+3x}{15}\)
\(15x-11=9+3x\)
\(12x=20\)
\(x=\dfrac{5}{3}\)
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bài 1 : a,ta có 3/x-1 =4/y-2=5/z-3 => x-1/3=y-2/4=z-3/5
áp dụng .... => x-1+y-2+z-3 / 3+4+5 = x+y+z-1-2-3/3+4+5 = 12/12=1
do x-1/3 = 1 => x-1 = 3 => x= 4 ( tìm y,z tương tự
Bài 1:
a) Ta có: 3/x - 1 = 4/y - 2 = 5/z - 3 => x - 1/3 = y - 2/4 = z - 3/5 áp dụng ... =>x - 1 + y - 2 + z - 3/3 + 4 + 5 = x + y + z - 1 - 2 - 3/3 + 4 + 5 = 12/12 = 1 do x - 1/3 = 1 => x - 1 = 3 => x = 4 ( tìm y, z tương tự )
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`(1/(1.3)+1/(3.5)+.......+1/(23.25))xx((x+1)+(x+3)+(x+5)+.....+(x+23))=144`
`(2/(1.3)+2/(3.5)+.......+2/(23.25))xx[(x+x+....+x)+(1+3+5+...+23)]=288`
`(1-1/3+1/3-1/5+.....+1/23-1/25)xx(12x+(24.12)/2)=288`
`(1-1/25)xx(12x+12.12)=288`
`24/25xx[12(x+12)]=288`
`24/25xx(x+12)=28`
`x+12=28:24/25=50`
`x=50-12=38`
Vậy `x=38`
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