1.tính:
a) A= \(2^3\).\(5^3-3\).{639-8(\(7^8\):\(7^6\)+1)}
b) B= \(-19^2 \)-{147-2[\(7^3\)+(93-126):(6-\(3^2\))]}
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b: \(B=\dfrac{5}{2}-\dfrac{7}{2}+\dfrac{3}{8}+\dfrac{6}{8}+\dfrac{-6}{11}-\dfrac{5}{11}=-2-1+\dfrac{9}{8}=\dfrac{9}{8}-3=-\dfrac{15}{8}\)
c: \(C=\left(\dfrac{4}{3}+\dfrac{7}{3}+\dfrac{1}{3}\right)+\left(\dfrac{2}{5}+\dfrac{3}{5}\right)=4+1=5\)
d: \(D=\dfrac{4}{19}\left(\dfrac{-5}{6}-\dfrac{7}{12}\right)-\dfrac{40}{57}\)
\(=\dfrac{4}{19}\cdot\dfrac{-17}{12}-\dfrac{40}{57}=-1\)
e: \(E=\dfrac{1}{3}\left(\dfrac{4}{5}-\dfrac{9}{5}\right)+\dfrac{2}{3}=\dfrac{2}{3}-\dfrac{1}{3}=\dfrac{1}{3}\)
(-9).27-13.9+40.11
= (-243) - 117+440
= 80+440
= 520
-192-{147-2[73+(93-126):(6-32)]}
= 361- {147- 2[ 343 +(-33):(-3)]}
= 361- { 147-2[ 343+ 11]}
=361 - { 147 -2. 354}
=361 - { 147- 708}
= 361 - (-561)
= 922
`1/3 + 1/5 -1/4`
`= 5/15 + 3/15 -1/4`
`= 8/15 -1/4`
`= 17/60`
__
`7/8 -(1/4 + 2/5)`
`= 7/8-1/4 - 2/5`
`= 7/8 - 2/8 -2/5`
`= 5/8 -2/5`
`= 9/40`
__
`5/11-(3/5 -6/11)`
`= 5/11 -3/5 +6/11`
`= (5/11 + 6/11)-3/5`
`= 1 -3/5`
`= 5/5-3/5`
`=2/5`
__
`5/7 - ( 19/35 - 6/15)`
`= 5/7 - 19/35 + 6/15`
`= 25/35 -19/35 + 6/15`
`=6/35 +6/15`
`=4/7`
B=4*13/9*3-4/3*40/9
B=4/3*13/9-4/3*40/9
B=4/3*(13/9-40/9)
B=4/3*(-27)/9
B=4*(-3)/9
B=-4
A=6/7 + 1/7.(2/7+5/7)
A=6/7 + 1/7.7/7=6/7+1/7.1
A=6/7+1/7=7/7=1
a) 1-2-3+4+5-6-7+8+......+17-18-19+20=(1-2-3+4)+(5-6-7+8)+....+(17-18-19+20)
=0+0+......+0
=0
câu b hơi khó mình cần thời gian ,mai mình đưa kết quả cho
a) A= \(2^3.5^3-3.\left[639-8\left(7^8:7^6+1\right)\right]\)
= \(2^3.5^3-3.\left[639-8.50\right]\)
= \(2^3.5^3-3.\left[639-400\right]\)
= \(2^3.5^3-3.239\)
= \(10^3-717\)
= 283
b) \(-19^2-\left\{147-2\left[7^3+\left(93-126\right):\left(6-3^2\right)\right]\right\}\)
= \(-19^2-\left\{147-2\left[7^3+\left(-33\right):\left(-3\right)\right]\right\}\)
= \(-19^2-\left\{147-2\left[7^3+11\right]\right\}\)
\(=-19^2-\left\{147-2.354\right\}\)
\(=-19^2-\left\{-561\right\}\)
= 922
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