Question

[lu nguyễn]

bài 1 : rút gọn các phân thức sau

a, \(\dfrac{x^2-2x}{x^2-4}\)

b, \(\dfrac{x^2+5x+4}{x^2-1}\)

c,\(\dfrac{x^4+4}{x\left(x^2+2\right)-2x^2-\left(x-1\right)^2-1}\)

bài 2 : rút gọn các biểu thức sau.

a,\(\left(\right)\dfrac{2x+1}{2x-1}-\dfrac{2x-1}{2x+1}\left(\right):\dfrac{4x}{10x-5}\)

b, \(\left(\dfrac{1}{x^2+x}-\dfrac{2-x}{x+1}\right):\left(\dfrac{1}{x}+x-2\right)\)

c, \(\left(\dfrac{5x+2}{x^2-10x}\dfrac{5x-2}{x^2+10x}\right)\times\dfrac{x^2-100}{x^2+4}\)

Answer 1

[Rain Tờ Rym Te]

\(a,\dfrac{x^2-2x}{x^2-4}=\dfrac{x\left(x-2\right)}{\left(x-2\right)\left(x+2\right)}=\dfrac{x}{x+2}\)

b) \(\dfrac{x^2+5x+4}{x^2-1}=\dfrac{x^2+x+4x+4}{x^2-1}=\dfrac{\left(x+1\right)\left(x+4\right)}{\left(x-1\right)\left(x+1\right)}=\dfrac{x+4}{x-1}\)

c) \(\dfrac{x^4+4}{x\left(x^2+2\right)-2x^2-\left(x-1\right)^2-1}\)

\(=\dfrac{x^4+4x^2-4x^2+4}{x^3+2x-2x^2-x^2+2x-1-1}\)

\(=\dfrac{\left(x^2+2\right)^2-4x^2}{\left(x^3+2x-2x^2\right)-\left(x^2-2x+2\right)}\)

\(=\dfrac{\left(x^2+2-2x\right)\left(x^2+2+2x\right)}{x\left(x^2+2-2x\right)-\left(x^2+2-2x\right)}\)

\(=\dfrac{x^2+2+2x}{x-1}\)

Bài 2:

a) \(\left(\dfrac{2x+1}{2x-1}-\dfrac{2x-1}{2x+1}\right):\dfrac{4x}{10x-5}\)

\(=\dfrac{\left(2x+1\right)^2-\left(2x-1\right)^2}{\left(2x-1\right)\left(2x+1\right)}.\dfrac{5\left(2x-1\right)}{4x}\)

\(=\dfrac{8x}{\left(2x-1\right)\left(2x+1\right)}.\dfrac{5\left(2x-1\right)}{4x}\)

\(=\dfrac{10}{2x+1}\)

b) \(\left(\dfrac{1}{x^2+x}-\dfrac{2-x}{x+1}\right):\left(\dfrac{1}{x}+x-2\right)\)

\(=\dfrac{1-2x+x^2}{x\left(x+1\right)}:\dfrac{1+x^2-2x}{x}\)

\(=\dfrac{1}{x+1}\)

c) Trong ngoặc giữa hai phân số là dấu gì vậy ?

Answer 2

[lu nguyễn]

là dấu cộng