nếu 3x+2y+3=7 , thì 9x+6y-10=?
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3x+2y+3=7 => 3x+2y=4
9x+6y-10
= 3x+6x+2y+4y-10
= 3x+2y+6x+4y-10
= 3x+2y+2.(3x+2y)-10
= 4+2.4-10
= 4+8-10
= 12-10
= 2.
![](https://rs.olm.vn/images/avt/0.png?1311)
a.x2-7x+10
⇔x2-2x-5x+10
⇔x(x-2)-5(x-2)
⇔(x-2)(x-5)
b.\(\left(12x^6y^4+9x^5y^3-15x^2y^3\right):3x^2y^3\)
=\(4x^4y+3x^3-5\)
=
x2-7x+10
= x2-5x-2x+10
=x(x-5)-2(x-5)
=(x-5)(x-2)
(12x6y4+9x5y3-15x2y3): 3x2y3
=4x4y+3x3-3
![](https://rs.olm.vn/images/avt/0.png?1311)
a) 5xy ( x - y ) - 2x + 2y
= 5xy ( x - y ) - 2 ( x - y )
= ( x - y ) ( 5xy - 2 )
b) 6x-2y-x(y-3x)
= 2 ( y - 3x ) - x ( y - 3x )
= ( y - 3x ( ( 2 - x )
c) x2 + 4x - xy-4y
= x ( x + 4 ) - y ( x + 4 )
( x + 4 ) ( x - y )
d) 3xy + 2z - 6y - xz
= ( 3xy - 6y ) + ( 2z - xz )
= 3y ( x - 2 ) + z ( x - 2 )
= ( x - 2 ) ( 3y + z )
a,5xy(x-y)-2x+2y=5xy(x-y)-2(x-y)=(x-y)(5xy-2)
b,6x-2y-x(y-3x)=-2(y-3x)-x(y-3x)=(y-3x)(-2-x)
c,x^2+4x-xy-4y=x(x+4)-y(x+4)=(x+4)(x-y)
d,3xy+2z-6y-xz=(3xy-6y)+(2z-xz)=3y(x-2)+z(2-x)=3y(x-2)-z(x-2)=(x-2)(3y-z)
11)
a,4-9x^2=0
(2-3x)(2+3x)=0
2-3x=0=>x=2/3 hoặc 2+3x=0=>x=-2/3
b,x^2 +x+1/4=0
(x+1/2)^2 =0
x+1/2=0
x=-1/2
c,2x(x-3)+(x-3)=0
(x-3)(2x+1)=0
x-3=0=>x=3 hoặc 2x+1=0=>x=-1/2
d,3x(x-4)-x+4=0
3x(x-4)-(x-4)=0
(x-4)(3x-1)=0
x-4=0=>x=4 hoặc 3x-1=0=>x=1/3
e,x^3-1/9x=0
x(x^2-1/9)=0
x(x+1/3)(x-1/3)=0
x=0 hoặc x+1/3=0=>x=-1/3 hoặc x-1/3=0=>x=1/3
f,(3x-y)^2-(x-y)^2 =0
(3x-y-x+y)(3x-y+x-y)=0
2x(4x-2y)=0
4x(2x-y)=0
x=0hoặc 2x-y=0=>x=y/2
![](https://rs.olm.vn/images/avt/0.png?1311)
đề dài nên T giải câu a thôi bn tự làm tiếp mấy câu khác nhé
2x^2 - 2y^2 - 6x - 6y
= 2(x^2-y^2) - 6(x+ y)
= 2(x-y)(x+y) - 6(x+y)
= (2(x-y)-6) (x+y)
![](https://rs.olm.vn/images/avt/0.png?1311)
a) \(2xy+3z+6y+xz\)
\(=2xy+2.3y\)
\(=2y\left(x+3\right)+3z+xz\)
\(=2y\left(x+3\right)+z\left(x+3\right)\)
\(=\left(x+3\right)\left(2y+z\right)\)
c) \(x^4-9x^3+x^2-9x\)
\(=x\left(x^3-9x^2+x-9\right)\)
\(=x\left(x-9\right)\left(x^2+1\right)\)
3x+2y+3=7 => 3x+2y=4
9x+6y-10
= 3x+6x+2y+4y-10
= 3x+2y+6x+4y-10
= 3x+2y+2.(3x+2y)-10
= 4+2.4-10
= 4+8-10
= 12-10
= 2.