Có ai giúp mình không
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a)
⇔\(\dfrac{2x-5}{x+5}-\dfrac{3x+15}{x+5}=0\)
⇔\(\dfrac{3x-5-3x-15}{x+5}=0\)
⇔\(-x-20=0\)
⇔\(x=-20\)
c)
⇔x(x+1) = (x+4)(x-1)
⇔x2+x=x2-x+4x-4
⇔x2+x-x2+x-4x=-4
⇔-2x=-4
⇔x=2
Vậy S={2}
1 shall we
2 aren't I
3 isn't there
1 don't they
2 isn't she
3 will they
4 isn't it
5 are there
6 doesn't he
7 wouldn't he
8 are those
9 have you
10 isn't it
11 can't they
12 did they
13 did it
15 aren't I
16 aren't they
17 have you
18 was it
19 hadn't he
20 don't you
21 aren't they
22 have you
23 isn't it
24 are there
25 aren't you
1 didn't you
2 can't we
\(a,\Leftrightarrow-m+5\ne0\Leftrightarrow m\ne5\\ b,\text{Đồng biến }\Leftrightarrow-m+5>0\Leftrightarrow m< 5\\ \text{Nghịch biến }\Leftrightarrow-m+5< 0\Leftrightarrow m>5\)
trước khi đăng kí trên onine math bn chưa tìm hiểu nội quy à